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Surface Area of a Cone - Free MCQ Practice Test with solutions, Class 9


MCQ Practice Test & Solutions: Test: Surface Area of a Cone (10 Questions)

You can prepare effectively for Class 9 Mathematics (Maths) Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Surface Area of a Cone". These 10 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Surface Area of a Cone - Question 1

The area surrounded by a conical tent is 4526 m2. If the cost of canvas is Rs. 17 per square meter, then find the total cost of canvas.​

Detailed Solution: Question 1

total cost = area of canvas used x cost of per meter square canvas

= 4526 x 17 

= Rs. 76942

Test: Surface Area of a Cone - Question 2

The height of a right circular cone is 3 cm and its base radius is 4 cm. Find the curved surface area of the cone

Detailed Solution: Question 2

The curved surface area (CSA) of a cone is given by:

CSA = πrl

Where:

  • r = base radius of the cone
  • l = slant height of the cone

The slant height l can be calculated using

 

Calculating CSA

Test: Surface Area of a Cone - Question 3

A conical tomb of base diameter 24m and height 16 m. What is the curved surface area?

Detailed Solution: Question 3


Test: Surface Area of a Cone - Question 4

The curved surface area of a right circular cone whose slant height is 14 cm and base radius is 21 cm is​

Detailed Solution: Question 4

L = 14 cm
R = 21 cm
C S A of Cone = πRL
22/7 * 21 * 14 cm
22 * 21 * 2 cm
462 * 2 cm
924 cm2

Test: Surface Area of a Cone - Question 5

A conical tent is 15 m high and the radius of its base is 20 m. The cost of the canvas required to make the tent at the rate of Rs 7 per m2 is​

Detailed Solution: Question 5

  • Height of cone (h) = 15 m

  • Radius of base (r) = 20 m

  • Cost per m² = ₹7

Cost = CSA × Rate

= 1571.43×7 ≈ ₹11000

 

Test: Surface Area of a Cone - Question 6

The solid generated by the rotation of a right triangle about one of its sides containing the right angle is called a ………

Detailed Solution: Question 6

When the triangle is rotated about its side it becomes the height of the cone and the other side containing the right angle becomes the radius..

Test: Surface Area of a Cone - Question 7

The total surface area of a cone of slant height 9 cm and radius 5 cm is​

Test: Surface Area of a Cone - Question 8

A right circular cone has an altitude of 40 cm and a diameter of 60 cm. The slant height of the cone is

Detailed Solution: Question 8

d=60
so r=30
l=√r2+h2
l= √302+402
l=50

Test: Surface Area of a Cone - Question 9

An ice cream cone has base radius 6 cm and altitude 8 cm. The total surface area of 21 such cones is​

Test: Surface Area of a Cone - Question 10

The curved area of a cone is 242 cm2 and its radius and slant height are in the ratio 7:11. Calculate the radius of the cone.​

Detailed Solution: Question 10

We are given:

  • Curved surface area (CSA) of a cone = 242 cm²

  • Radius : Slant height = 7 : 11

We use the formula for CSA of a cone:

CSA = π × r × l

Where:

  • r = radius

  • l = slant height

Let the radius be 7x and slant height be 11x, since they are in the ratio 7:11.

So:

CSA = π × r × l
242 = (22/7) × (7x) × (11x)

Simplify

Left side: 242
Right side: (22/7) × 7x × 11x = 22 × 11x² = 242x²

So:

242 = 242x²
x² = 1
x = 1

Find radius

Radius = 7x = 7 × 1 = 7 cm

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