RD Sharma Test: Statistics - Class 10 MCQ

Median=L + 
=40 + 
=40 + 6 = 46

Mode=L+ 
Where L=lower limit of the modal class =40
f1= modal class frequency.=7
f2 = just after the modal class frequency.=6
f0 = just previous the modal class frequency=3
C = Class size=15
Mode=40+ * 15 = 40 + 12 = 52

Mode is the most occurred value. In the data we have three 5 and three 8 , so if mode is only 8 then the value of x must be 8 ,so that only 8 is the most occurring value.

Mode is the most frequently occurring observation. Since it's not a grouped data the frequency is the occurrence of only one observation , So the highest no. of frequency is 3 . So the modal age is 3.

Modal class as the name suggests is the interval which occurs most of the times which means the interval which has the highest frequency.By changing the distribution in grouped distribution 30-40 has the maximum frequency that is 30

A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers. So 10 prime numbers are: 2,3,5,7,11,13,17,19,23,29
Since the number of terms are even ,
Median = 
 10/2=5th term=11
10/2 +1=6th term=13
Median = 

 Central tendency is the central value for a probability distribution. Mean,media,mode and range are the measures of central tendeny. Amongst them, median can be determined graphically.

Median is the middle value of the observations. So Median cannot be obtained when the observations are not in order. So first we have to arrange in ascending order. 
59, 46, 30, 23, 27, 44, 52, 40 and 29
Gives- 23,27,29,30,40,44,46,52,59
Since the no. of observations is odd 

The middle most value of the data set is called median.

An give, also known as a cumulative histogram, is a graph that is used to determine the number of data points that are equal to or below a certain value in a data set.It is a plot of cumulative values, rather than a plot of the values themselves. Median is determined by finding the (n/2)th value and then dropping it to the x axis.