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Test: Area Of Triangles - Class 9 MCQ


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20 Questions MCQ Test - Test: Area Of Triangles

Test: Area Of Triangles for Class 9 2024 is part of Class 9 preparation. The Test: Area Of Triangles questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Area Of Triangles MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Area Of Triangles below.
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Test: Area Of Triangles - Question 1

A median of a triangle divides it into two triangles of

Test: Area Of Triangles - Question 2

The area of quadrilateral ABCD is:

Detailed Solution for Test: Area Of Triangles - Question 2
Area of triangle abd =1/2*9*12=54 Area of triangle bcd=1/2*8*15=60 area of quadrilateral =54+60=114cm2
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Test: Area Of Triangles - Question 3

Area of an equilateral triangle is equal to

Test: Area Of Triangles - Question 4

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. If area (ΔAOD) = 37sq cm, then area (ΔBOC) =

Test: Area Of Triangles - Question 5

ABCD is a parallelogram whose diagonals intersect at O. A line through O intersects AB at P and DC at Q. Then

Test: Area Of Triangles - Question 6

The area of a right triangle is 30 sq cm. If the base is 5 cm, then the hypotenuse must be

Test: Area Of Triangles - Question 7

AE is a median to side BC of triangle ABC. If area(ΔABC) = 24 cm, then area(ΔABE) =

Test: Area Of Triangles - Question 8

D is the mid point of side BC of ABC and E is the mid point of BD. If O is the mid point of AE, then

Test: Area Of Triangles - Question 9

In the figure, ∠PQR = 90°, PS = RS, QP = 12 cm and QS = 6.5 cm. The area of ΔPQR is

Test: Area Of Triangles - Question 10

In the given figure, if parallelogram ABCD and rectangle ABEF are of equal area then:

Test: Area Of Triangles - Question 11

In ΔABC, if L and M are points on AB and AC respectively such that LM BC then ar (LMC) is equal to

Test: Area Of Triangles - Question 12

In a parallelogram ABCD, P is a point in interior of parallelogram ABCD. If ar (||gm ABCD) = 18 cm2 then [arΔAPD) + ar(ΔCPB)] is :​

Test: Area Of Triangles - Question 13

Diagonals AC and BD of a trapezium ABCD with AB ll DC intersect each other at O. If area (ΔAOD)=37sq cm, then area (ΔBOC) = ?

Test: Area Of Triangles - Question 14

In ΔPQR, if D and E are points on PQ and PR respectively such that DE || QR, then ar (PQE) is equal to

Test: Area Of Triangles - Question 15

ABC is a triangle in which D is the mid point of BC and E is the mid point of AD. Then area (ΔBED) is equal to

Test: Area Of Triangles - Question 16

In a parallelogram ABCD, E and F are any two points on the sides AB and BC respectively. If ar (ΔDCE) is 12 cm2, then ar(ΔADF) is

Test: Area Of Triangles - Question 17

AD is one of the medians of a Δ ABC. X is any point on AD. Then, the area of ΔABX is equal to

Test: Area Of Triangles - Question 18

ABC and BDE are two equilateral triangles such that D is the mid point of BC. AE intersects BC in F. Then ar (BDE) is equal to

Test: Area Of Triangles - Question 19

In figure P, Q are points on sides AB, AC respectively of ΔABC such that ar (BCQ) = ar (BCP). Then,

Test: Area Of Triangles - Question 20

In ΔABC, E is the mid-point of median AD. Area(ΔBED) =

Detailed Solution for Test: Area Of Triangles - Question 20

AD is the median of ΔABC. Therefore, it will divide ΔABC into two triangles of equal area.

∴ Area (ΔABD) = Area (ΔACD)

⇒Area (ΔABD ) = (1/2) area (Δ ABC) ------------(1)

In ΔABD, E is the mid-point of AD.

Therefore, BE is the median.

∴ Area (ΔBED) = Area (ΔABE)

Area (ΔBED) = (1/2)Area (ΔABD)

Area (ΔBED) = (1/2 ) x(1/2) Area (ΔABC)         [From (1)]

∴ Area (ΔBED) = (1/4)Area (ΔABC).

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