Probability Experimental Approach - Free MCQ Practice Test with solutions,

Definition of Experimental Probability: The experimental probability of the happening of an event is the ratio of the number of trials in which the event happened to the total number of trials.
The experimental probability of the occurrence of an event E is defined as:

The probability of anything is 1.
∵ It is given that the probability of winning the game is 0.7 
Therefore, the probability of losing the game is
1 - 0.7 = 0.3

Clearly, n(S) = 52.
There are 26 red cards (including 2 kings ) and there are 2 more kings. 
Let (E) be the event of getting either a red card or a king.
⇒ n(E) = 28
∴ P(E) = n(E) / n(S) = 28/52 = 7/13

the event of getting a number that is either an even number or a multiple of 3.
C = {2,3,4,6}
n(C) = 4

⇒ Total number of pins = 100 

⇒ Number of pins that landed pointed up = 73 

⇒ The number of pins that landed pointed down would be = 100-73 = 27 

⇒ P( the pin selected and dropped would be pointed down) = Number of pins that landed pointed down / total number of pins.

⇒ Probability = 27/100 = 0.27 

In a leap year, there are 366 days.
∵ There are 52 weeks
i.e.52×7=364 days

⇒ The remaining 2 days may be {(Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed, Thu),(Thu, Fri), (Fri, Sat), (Sat, Sun)}.

∴ P (53 Sundays ) = 2/7.

E ⟶ event of getting a sum more than 7

No. of favorable outcomes = 15 {(2, 6) , (3, 5) , (3, 6) , (4, 4) , (4, 5) , (4, 6) , (5, 3) , (5, 4) , (5, 5) , (5, 6) , (6, 2) , (6, 3) , (6, 4) , (6, 5) , (6, 6)}

Total no. of possible outcomes = 36

P(E) = 15/36 = 5/12

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

An event that cannot possibly happen has a probability of zero. If there is a chance that an event will happen, then its probability is between zero and 1.
Examples of Events: tossing a coin and it landing on heads.