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Test:Triangles- 1 - Class 9 MCQ


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25 Questions MCQ Test Mathematics (Maths) Class 9 - Test:Triangles- 1

Test:Triangles- 1 for Class 9 2024 is part of Mathematics (Maths) Class 9 preparation. The Test:Triangles- 1 questions and answers have been prepared according to the Class 9 exam syllabus.The Test:Triangles- 1 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test:Triangles- 1 below.
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Test:Triangles- 1 - Question 1

If AB = QR, BC=RP and CA = QP, then which of the following holds?

Detailed Solution for Test:Triangles- 1 - Question 1

- The problem involves two triangles with corresponding side lengths: ( AB = QR ), ( BC = RP ), and ( CA = QP ).
- According to the Side-Side-Side (SSS) Congruence Theorem, two triangles are congruent if all three pairs of corresponding sides are equal.
- To match the sides correctly with the given order, note:
- ( CA = QP )
- ( AB = QR )
- ( BC = RP )
- Therefore, the correct correspondence is △CAB ≅ △PQR

Test:Triangles- 1 - Question 2

△PQR, ∠P = 60, ∠Q = 50 and Which side of the triangle is the longest?

Detailed Solution for Test:Triangles- 1 - Question 2

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Test:Triangles- 1 - Question 3

In the adjoining figure, the rule by which △ABC ≅ △ADC

Test:Triangles- 1 - Question 4

In the adjoining figure, BC = AC. If ∠ACD = 115, the ∠A is

Detailed Solution for Test:Triangles- 1 - Question 4

In △ABC,
∠ACD+∠ACB = 180 (Linear pair)
115+∠ACB =180
∠ACB = 180−115=65

since AC = BC then ∠ABC = ∠BAC = X
x + x + 65 = 180
2x = 180- 65
2x = 115
x = 57.5

Test:Triangles- 1 - Question 5

If the bisector of the angle A of a △ABC is perpendicular to the base BC of the triangle then the triangle ABC is :

Detailed Solution for Test:Triangles- 1 - Question 5

If the bisector of angle A of a triangle is perpendicular to the base BC of the triangle then the triangle ABC is:

B: Isosceles

Solution:

- The angle bisector of angle A divides the angle into two equal parts.
- For this bisector to be perpendicular to base BC, angles B and C must be equal.
- This means that triangle ABC has two equal sides opposite these equal angles.
- Therefore, triangle ABC is isosceles.

Test:Triangles- 1 - Question 6

Which is true?

Test:Triangles- 1 - Question 7

In the adjoining figure, BC = AD, CA⊥AB and BD⊥AB. The rule by which △ABC ≅ △BAD is

Test:Triangles- 1 - Question 8

In the given figure, ABC is an equilateral triangle. The value of x+y is 

Test:Triangles- 1 - Question 9

In quadrilateral ABCD, BM and DN are drawn perpendiculars to AC such that BM = DN. If BR = 8 cm. then BD is

Test:Triangles- 1 - Question 10

If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangles is

Detailed Solution for Test:Triangles- 1 - Question 10

Given:

BE = CD

Concept Used:

When 2 sides of a triangle are equal, then it is isosceles.

When 2 angles and 1 side of 2 triangles is equal, then both the triangles are similar.

Calculations:

In △ABE and △ACD,

BE = CD (Given)

∠BEA = ∠CDA (90° each)

∠BAE = ∠CAD (Common Angle)

∠ABE = ∠ACE (By Sum angle property)

⇒ △ABE is similar to △ACD

⇒ AB = AC

∴ If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangle is isosceles.

Test:Triangles- 1 - Question 11

In △AOC and △XYZ, ∠A =∠X, AO = YZ, AC = XY, then by which congruence rule △AOC ≅ △XYZ

Detailed Solution for Test:Triangles- 1 - Question 11

To determine the congruence rule for ΔAOC and ΔXYZ:


  • Given: ∠A = ∠X

  • AO = YZ (one pair of corresponding sides)

  • AC = XY (another pair of corresponding sides)

  • Two pairs of sides and the included angle are equal

  •  

Therefore, by the SAS (Side-Angle-Side) congruence rule, ΔAOC ≅ ΔXYZ.

Test:Triangles- 1 - Question 12

In the adjoining figure, AB = AC and AD⊥BC. The rule by which △ABD ≅ △ACD is

Test:Triangles- 1 - Question 13

In the adjoining Figure, AB = AC and BD = CD. The ratio ∠ABD : ∠ACD is

Test:Triangles- 1 - Question 14

In △ABC and △PQR, three equality relations between corresponding parts are as follows: AB = QP, ∠B = ∠P BC = PR. State which of the congruence criterion applies in this case:

Test:Triangles- 1 - Question 15

O is any point in the interior of △ABC.Then which of the following is true?

Test:Triangles- 1 - Question 16

It is not possible to construct a triangle when its sides are:

Test:Triangles- 1 - Question 17

In the adjoining figure, AB = AC and AD is bisector of ∠A. The rule by which △ABD ≅ △ACD

Test:Triangles- 1 - Question 18

In the adjoining figure, AB⊥BE and FE⊥BE. If AB = FE and BC = DE ,then

Test:Triangles- 1 - Question 19

D,E and f are the mid-points of the sides BC, CA and AB res. Of △ABC. Then △DEF is congruent to triangle:

Test:Triangles- 1 - Question 20

Which of the following is not a criterion for congruence of triangles?

Detailed Solution for Test:Triangles- 1 - Question 20

The criteria for congruence of triangles are:

  • RHS: Right Angle-Hypotenuse-Side, which is only used for right triangles 
  • SSS: Side-Side-Side, where all three sides of two triangles are equal
  • SAS: Side-Angle-Side, where two sides and the angle between them are equal
  • ASA: Angle-Side-Angle, where two angles and the included side of one triangle are equal to the corresponding angles and sides of another triangle
  • AAS: Angle-Angle-Side, where two angles and the non-included side of one triangle are congruent to two angles and the non-included side of another triangle
Test:Triangles- 1 - Question 21

△ABC = △PQR, then which of the following is true?

Test:Triangles- 1 - Question 22

In the adjoining figure, ∠B = ∠C and AD⊥BC. The rule by which △ABD ≅ △ADC

Detailed Solution for Test:Triangles- 1 - Question 22

△ABD ≅ △ADC can be done on all of these ways by using the properties of isoceles triangle and ∠B = ∠C and AD⊥BC

Test:Triangles- 1 - Question 23

In the adjoining figure, ABCD is a quadrilateral in which BN and DM are drawn perpendiculars to AC such that BN = DM. If OB = 4 cm. then BD is

Test:Triangles- 1 - Question 24

In triangle PQR length of the side QR is less than twice the length of the side PQ by 2 cm. Length of the side PR exceeds the length of the side PQ by 10 cm. The perimeter is 40 cm. The length of the smallest side of the triangle PQR is :

Test:Triangles- 1 - Question 25

In triangle ABC and triangle DEF, if AB/DE = AC/DF = BC/EF, then the triangles are:

Detailed Solution for Test:Triangles- 1 - Question 25

Explanation: This is the SSS similarity criterion, which states that if the sides of two triangles are in proportion, the triangles are similar

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