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CBSE Class 9  >  Class 9 Test  >  Science   >  Test: Newton's Second Law Of Motion - Class 9 MCQ

Newton's Second Law Of Motion - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Newton's Second Law Of Motion (20 Questions)

You can prepare effectively for Class 9 Science Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Newton's Second Law Of Motion". These 20 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 20

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Test: Newton's Second Law Of Motion - Question 1
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The S.I. unit of force is

Detailed Solution: Question 1

Force is the product of the ass and acceleration.
Therefore, Force = Mass x Acceleration 
The SI unit of Force is  kg.m/s² or Newton
1 Newton =  10⁵ Dyne

Test: Newton's Second Law Of Motion - Question 2
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Two balls A and B, of masses m and 2m are in motion with velocities 2v and v respectively. Compare the force needed to stop them in the same time

Detailed Solution: Question 2

The acceleration produced in a body is directly proportional to the force acting on it and inversely proportional to the mass of the body. If the mass of the body is doubled, its acceleration will be halved. And if the mass is halved then acceleration will get doubled. So the provided force remains same.

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Test: Newton's Second Law Of Motion - Question 3
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Find the time taken by a body of mass 16 kg to come to rest from a uniform velocity of magnitude 10 m/s, when a force of 4N is applied continously

Detailed Solution: Question 3

To find the time taken for the body to come to rest, we can use the formula derived from Newton's second law:

F=ma

where:

  • F is the force applied,
  • m is the mass of the body,
  • a is the acceleration.

First, we calculate the acceleration:

The body is initially moving with a velocity of 10 m/s and will come to rest, so the final velocity v=0v = 0v=0.

Using the equation of motion:

v=u+at

where:

  • v is the final velocity (0 m/s),
  • u is the initial velocity (10 m/s),
  • a is the acceleration (-0.25 m/s²) (negative because the force is acting opposite to the direction of motion),
  • t is the time taken.

Substitute the values:

0=10+(−0.25)t

0.25t=10

So, the time taken by the body to come to rest is 40 seconds.

Answer: 3 (40 s)

Test: Newton's Second Law Of Motion - Question 4
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If the force acting on the body is zero. Its momentum is:

Detailed Solution: Question 4

The relationship also implies the conservative of momentum : when the net force on the body is zero, the momentum of the body is constant. Any net force is equal to the rate of change of the momentum.

Test: Newton's Second Law Of Motion - Question 5
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Which of the following has the largest momentum?

Detailed Solution: Question 5

Because the momentum is the force created by the mass and velocity of a body for example if a table tennis ball hit you it will not hurt because it have lesser mass and lesser velocity and if a cricket ball hits you it will hurt because the cricket ball have more mass and velocity. so by this we can say that the pickup truck travelling down the highway will have greater momentum as it have more mass than any other and also it have more velocity than others as it is in higher speed. I hope you learned something

Test: Newton's Second Law Of Motion - Question 6
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What force can change the velocity of a body of mass 1kg from 20 m/s to 30m/s in 2 seconds?

Detailed Solution: Question 6

  • Mass = 1 kg

  • Initial velocity (u) = 20 m/s

  • Final velocity (v) = 30 m/s

  • Time (t) = 2 seconds

Acceleration (a) = (v - u) / t
= (30 - 20) / 2
= 10 / 2
= 5 m/s²

Force = mass × acceleration
= 1 × 5
= 5 Newtons

Test: Newton's Second Law Of Motion - Question 7
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A football of mass 0.30 kg is kicked and moves with a velocity of 15 m/s. What is its momentum?

Detailed Solution: Question 7

Given

  • Mass, m = 0.30 kg
  • Velocity, v = 15 m/s

Concept & formula

  • Linear momentum (p) measures “quantity of motion”.
  • Formula: p = m × v
  • SI unit: kg·m/s
  • Direction: same as the velocity (since momentum is a vector). Here we’re asked for the value (magnitude).

Substitute and calculate

  • p = 0.30 × 15
  • Quick multiply: 3 × 15 = 45 → place one decimal (because 0.30 has one non-zero decimal place) → 4.5
  • So, p = 4.5 kg·m/s

Unit check (dimensional sanity)

  • kg × (m/s) = kg·m/s  (correct momentum unit)

Eliminate wrong options

b) 0.02 kg·m/s — way too small; likely from incorrect operation (e.g., dividing 0.30 by 15).

c) 15 kg·m/s — equals the speed; ignores mass.

d) 225 kg·m/s — looks like 15 × 15 (used speed twice), not m × v.

 

Test: Newton's Second Law Of Motion - Question 8
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A resistive force of 16 N acts on a ball of mass 40 g continuously. If the initial velocity of the ball is 24 ms-1 ,the time taken by it to come to rest is:

Detailed Solution: Question 8

Mass of ball: m= 40 g = 0.040kg
resistive force: F = -16 N
thus resistive acceleration, a = F/m (because force, F= ma)
thus a = -400m/s2
initial velocity, u = 24m/s
final velocity, v = 0m/s
Thus according to first equation of motion, v = u+at (t=timetaken)
t= 0.06s

Test: Newton's Second Law Of Motion - Question 9
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The acceleration of an object is inversely proportional to:

Detailed Solution: Question 9

The acceleration is inversely proportional to the mass of the object.
Newton's Second Law
"If the net force on an object is not zero, the object will accelerate. The direction of the acceleration is the same as the direction of the net force. The magnitude of the acceleration is directly proportional to the net force applied, and inversely proportional to the mass of the object."
For the same force, an object with twice the mass will have half the acceleration. If it had three times the mass, the same force will produce one-third of the acceleration. Four times the mass gives one-fourth of the acceleration, and so on.
This type of relationship between quantities (double one, get half the other) is called an inverse proportion or inverse variation. 

Test: Newton's Second Law Of Motion - Question 10
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Quantitative expression of force is given by:

Detailed Solution: Question 10

Force can be calculated from Newton’s second law of motion which gives that force is the product of mass and acceleration.

Test: Newton's Second Law Of Motion - Question 11
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If the same force acts on two bodies of different masses which are initially at rest and gain same displacement, then the ratio of time for which these forces act is:

Detailed Solution: Question 11

Given: Both bodies start from rest (initial velocity u = 0), and gain the same displacement s under the action of the same force F.

From the equation of motion: s = (1/2) a t2

Let the acceleration of the two bodies be a1 and a2, and the times be t1 and t2 respectively.

Since the force is same, from Newton's second law: a = F/m

So, s = (1/2) (F/m) t2

For the two masses:

s = (1/2) (F/m1) t12 = (1/2) (F/m2) t22

Since s and F are the same for both, equate the two expressions:

(1/2)(F/m1) t12 = (1/2)(F/m2) t22

Canceling common terms:

(1/m1) t12 = (1/m2) t22

Rearranged:

t12 / t22 = m1 / m2

Taking square root on both sides:

t1 / t2 = √(m1 / m2)

Hence, the ratio of times is √(m1 / m2).

Test: Newton's Second Law Of Motion - Question 12
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A man throws a ball weighing 200 g vertically upwards with a speed of 10m/s. Its momentum at the highest point of its flight will be:

Detailed Solution: Question 12

As on highest point velocity is zero .Hence momentum will also be zero as it is the product of mass and velocity of a body.

Test: Newton's Second Law Of Motion - Question 13
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In high jump competition the athlete is made to fall on a cushioned bed to:

Detailed Solution: Question 13

In a high jump athletic event, the athletes are made to fall either on a cushioned bed or sand bed. This is to increase the time that the athletes fall to stop after making the jump. This decreases the rate of change of momentum and hence the force. As a result, the athlete does not get injured.

Test: Newton's Second Law Of Motion - Question 14
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Which of the following is the relation between SI unit of gravitational force and Newton?​

Detailed Solution: Question 14

In SI system, the gravitational unit of force is kilogram – weight. It is that force which when acting on a body of mass 1 kg produces an acceleration of 9.8 m s^-2

Test: Newton's Second Law Of Motion - Question 15
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A carpenter exerts a force of magnitude 1.5 N at right angles to the surface of a nail of mass 3 gram to drive it into the wood. If wood offers a resistive force of 0.6 N and the time of interaction of hammer and the nail 0.01 s, the depth through which the nail penetrates is

Detailed Solution: Question 15

First, calculate the net force acting on the nail:
Net force = Applied force - Resistive force = 1.5 N - 0.6 N = 0.9 N.
The mass of the nail is 3 grams = 0.003 kg.
Using the impulse-momentum theorem:
Impulse = change in momentum = Net force × time = 0.9 × 0.01 = 0.009 kg·m/s.
Initial velocity (u) = 0 (since the nail starts from rest). Final velocity (v) = ?
Change in momentum = m × v - m × u = m × v.
So, 0.009 = 0.003 × v ⇒ v = 0.009 / 0.003 = 3 m/s.
Now, using the work-energy principle:
Kinetic energy acquired = Work done against resistance = Resistive force × depth (s).
(1/2) × m × v² = Resistive force × s
(1/2) × 0.003 × (3)² = 0.6 × s
0.5 × 0.003 × 9 = 0.6 × s
0.0135 = 0.6 × s
s = 0.0135 / 0.6 = 0.0225 m = 2.25 cm.
Therefore, the correct answer is 2.25 cm.

Test: Newton's Second Law Of Motion - Question 16
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Change in momentum when a car weighing 700kg changes its speed from 100m/s to 200 m/s is:

Detailed Solution: Question 16

We want the change in momentum.

Step 1: Formula
Change in momentum = mass × (final speed – initial speed)

Step 2: Put values
Mass = 700 kg
Initial speed = 100 m/s
Final speed = 200 m/s

Change in momentum = 700 × (200 – 100)
= 700 × 100
= 70,000 kg·m/s

Answer: (d) 70,000 kg·m/s

Test: Newton's Second Law Of Motion - Question 17
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Momentum of a body of mass 0.5 kg moving with a speed of 10 m/s is​

Detailed Solution: Question 17

We know , p=mv Here m=0.5 kg & v=10 m/s . So p=0.5*10=5 Kg m/s

Test: Newton's Second Law Of Motion - Question 18
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The relation between acceleration, mass and force is given by:

Detailed Solution: Question 18

The acceleration is directly proportional to f and inversely proportional to m and so the force applied on a mass of a body let to movement that's why here a is directly proportional to f

Test: Newton's Second Law Of Motion - Question 19
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What is the momentum of a body of mass 2m and velocity v/2?

Detailed Solution: Question 19

We know; P = mv
If m = 2 m ;   v= v/2
P  =  (2m) (v/2) 
P = mv

Test: Newton's Second Law Of Motion - Question 20
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An object of mass 20 kg is moving with a velocity of 10 m/s. Its momentum will be:

Detailed Solution: Question 20

Momentum p = mass x velocity
Given mass m=20 kg and velocity v = 10 m/s

So,
p = 20 kg x 10 m/s = 200 kg.m/s

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This test contains 20 MCQs on Newton's Second Law Of Motion with detailed solutions for each question. It is part of the Science Class 9 course on EduRev, designed to align with the current Class 9 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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