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CBSE Class 9  >  Class 9 Test  >  Science   >  Test: Motion- Case Based Type Questions- 1 - Class 9 MCQ

Motion- Case Based Type Questions- 1 - Free Questions with solutions


MCQ Practice Test & Solutions: Test: Motion- Case Based Type Questions- 1 (5 Questions)

You can prepare effectively for Class 9 Science Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Motion- Case Based Type Questions- 1". These 5 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 5

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Test: Motion- Case Based Type Questions- 1 - Question 1
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Direction: Study the following graph and choose the correct options to answer any four questions given below:

The velocity-time graph of an object is shown in the following figure.

Q. Which of the following statement is correct?

Detailed Solution: Question 1

Velocity-time graph can never be a straight line parallel to velocity axis.
✅ Correct — A straight line parallel to the velocity axis would mean that time is not changing, which contradicts the idea of motion over time. So this statement is true.

Test: Motion- Case Based Type Questions- 1 - Question 2
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Direction: Study the following graph and choose the correct options to answer any four questions given below:

The velocity-time graph of an object is shown in the following figure.

Q. Identify the part of graph where the object has zero acceleration. Give reasons for your answer.

Detailed Solution: Question 2

(a) As we know that if the slope of velocity time graph is parallel to time axis then the body is moving with a constant velocity.Hence, From A to B body has an constant velocity of 40 m/s

From B to C, the body uniformly retards as the velocity changes with respect to time.

(b) From A to B, the body has zero acceleration (i.e, retardation) as we know that if the body is uniform velocity acceleration automatically becomes zero here in the graph as we know the body started from 40 metre per second and from A to B, when body reaches at B its velocity remains 40 metre per second.Hence there is no change in velocity and we can say that acceleration is zero in this part of the graph

(c)From B to C, the body has negative acceleration (i.e, retardation) as we know that if the body has some initial velocity u and after sometime t if it gains some velocity v, we can say the body has an acceleration a.if the initial velocity is greater than the final velocity the acceleration becomes negative that is retardation of the body is seen.similarly here at point B if we considered the initial velocity to be 40 metre per second it uniformly retards to 0 m/s by the time it crosses 45 secs.

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Test: Motion- Case Based Type Questions- 1 - Question 3
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Direction: Study the following graph and choose the correct options to answer any four questions given below:

The velocity-time graph of an object is shown in the following figure.

Q. State the kind of motion that objects has, from A to B and from B to C.

Detailed Solution: Question 3

From A to B, the body has zero acceleration (i.e, retardation) as we know that if the body is uniform velocity acceleration automatically becomes zero here in the graph as we know the body started from 40 metre per second and from A to B, when body reaches at B its velocity remains 40 metre per second.Hence there is no change in velocity and we can say that acceleration is zero in this part of the graph

From B to C, the body has negative acceleration (i.e, retardation) as we know that if the body has some initial velocity u and after sometime t if it gains some velocity v, we can say the body has an acceleration a.if the initial velocity is greater than the final velocity the acceleration becomes negative that is retardation of the body is seen.similarly here at point B if we considered the initial velocity to be 40 metre per second it uniformly retards to 0 m/s by the time it crosses 45 secs.

Topic in NCERT: Uniform and Non-Uniform Motion

Line in NCERT: "Uniform motion from A to B and non-uniform motion from B to C"

Test: Motion- Case Based Type Questions- 1 - Question 4
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Direction: Study the following graph and choose the correct options to answer any four questions given below:

The velocity-time graph of an object is shown in the following figure.

Q. Identify the part of graph where the object has negative acceleration. Give reasons for your answer.

Detailed Solution: Question 4

From A to B, the body has zero acceleration (i.e, retardation) as we know that if the body is uniform velocity acceleration automatically becomes zero here in the graph as we know the body started from 40 metre per second and from A to B, when body reaches at B its velocity remains 40 metre per second.Hence there is no change in velocity and we can say that acceleration is zero in this part of the graph

(c) From B to C, the body has negative acceleration (i.e, retardation) as we know that if the body has some initial velocity u and after sometime t if it gains some velocity v, we can say the body has an acceleration a.if the initial velocity is greater than the final velocity the acceleration becomes negative that is retardation of the body is seen.similarly here at point B if we considered the initial velocity to be 40 metre per second it uniformly retards to 0 m/s by the time it crosses 45 secs.

Topic in NCERT: Acceleration

Line in NCERT: "the acceleration is taken to be positive if it is in the direction of velocity and negative when it is opposite to the"

Test: Motion- Case Based Type Questions- 1 - Question 5
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Direction: Study the following graph and choose the correct options to answer any four questions given below:

The velocity-time graph of an object is shown in the following figure.

Q. The area enclosed by the velocity-time graph and the time axis represents the __________.

Detailed Solution: Question 5

The area enclosed by the velocity-time graph and the time axis represents the displacement.

Area enclosed by a velocity-time sketch with time axis represents velocity × time = displacement.

Velocity being a vector quantity, area under time axis corresponds to negative velocity × time = negative displacement.

Topic in NCERT: Velocity-Time Graphs and Displacement

Line in NCERT: "The area enclosed by the velocity-time graph and the time axis will be equal to the magnitude of the displacement."

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About this Class 9 Practice Test

This test contains 5 MCQs on Motion- Case Based Type Questions- 1 with detailed solutions for each question. It is part of the Science Class 9 course on EduRev, designed to align with the current Class 9 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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