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Amazon Aptitude Paper 3


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Amazon Aptitude Paper 3 - Question 1

A function f(x) is defined as f(x) = f(x - 2) - x(x + 2) for all the integer values of x and f(1) + f(4) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?

Detailed Solution for Amazon Aptitude Paper 3 - Question 1

Let S = f(1) + f(2) + f(3) + f(4) + f(5) + f(6) 

As f(1) + f(4) = 0, therefore S = f(2) + f(3) + f(5) + f(6) ------ (1)

f(2) = f(0) - 8

f(3) = f(1) - 15

f(4) = f(2) - 24 = f(0) - 32

f(5) = f(3) - 35 = f(1) - 50

f(6) = f(4) - 48 = f(0) - 80 

Put the above values in equation (1), we get

S = f(0) - 8 + f(1) - 15 + f(1) - 50 + f(0) - 80

S = 2(f(0) + f(1)) - 153 ------ (2) 

As we already know f(1) + f(4) = 0 ⇒f(1) + f(0) - 32 = 0 ⇒f(1) + f(0) = 32

Putting this value in equation 2, we get S = 2(32) - 153 = -89

So, Ans is option C.

Amazon Aptitude Paper 3 - Question 2

In ABC, the internal bisectors of  ABC and  ACB met at 1 and BAC = 50.The measure of BIC is

Detailed Solution for Amazon Aptitude Paper 3 - Question 2

I is the In-centre

So,  BIC = 90 + 1/2  BAC

= 90 + 1/2 50 = 115

Amazon Aptitude Paper 3 - Question 3

The difference between [3/5] of [2/3] a number and [2/5] of[1/4] of the same number is 288. What is the number?

Detailed Solution for Amazon Aptitude Paper 3 - Question 3

Let the current price be Rs. 100.

For getting 12% profit he should sell it at Rs. 112.

Let the label price be x.

Let the no. Be [3/5]*[{2/5}x]-[2/5]*[1/4]x,then = 288 Solving it we will get 960

Amazon Aptitude Paper 3 - Question 4

A, B, C and D are four consecutive odd numbers and their average is 42. What is the product of B and D?

Detailed Solution for Amazon Aptitude Paper 3 - Question 4

Work done by A and B in 12 days is

12[112*5/4]=12*5/120=.5

As diff. Is same so average should lie between B and C so B is 41 & C is 43 so D must be 45 as we have to find the product of B and D so it would be 1845

Amazon Aptitude Paper 3 - Question 5

BL and CM are medians of ABC right angled at A and BC =5 cm. If BL =3- 5/2 cm, then the length of CM is

Detailed Solution for Amazon Aptitude Paper 3 - Question 5

Here, BC = 5cm

BL = 3 5/2 cm 

By using the formula

4(BL2 + CM2) = 5BC2

Amazon Aptitude Paper 3 - Question 6

A sum of Rs 731 is divided among A, B and C such that A receive 25% more than B and B receive 25% less than C. What is Cs share in the amount?

Detailed Solution for Amazon Aptitude Paper 3 - Question 6

A + B + C = 731 ..... (i) A = 1.25B, gives A = 1.25 * 0.75 C = 0.9375 C....(ii) B = 0.75C....(iii) Using (ii) and (iii) in (i) we get 0.9375C + 0.75C + C = 731, gives C = 272. So option E is the answer.

Amazon Aptitude Paper 3 - Question 7

In how many different ways can letters of the word "PRAISE" be arranged?

Detailed Solution for Amazon Aptitude Paper 3 - Question 7

As total number of alphabets in PRAISE are 6, so total no. of ways is 6!=720 So option A is the answer

Amazon Aptitude Paper 3 - Question 8

If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 300%, the resultant fraction is [5/18]. What is original fraction?

Detailed Solution for Amazon Aptitude Paper 3 - Question 8

Let the fraction be [n/d] & after that it becomes [2.5 n / 4 d]=5/18 . So we get the result as [4/9]

Amazon Aptitude Paper 3 - Question 9

A car covers the first 30 km of its journey in 45 minutes and the remaining 25 km in 30 minutes. What is the average speed of the car?

Detailed Solution for Amazon Aptitude Paper 3 - Question 9

Total distance/Total time =(30+25)/[(3/4)+(1/2)]

Average Speed=44kmph

Amazon Aptitude Paper 3 - Question 10

Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?

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