TCS Aptitude Paper 1 - Interview Preparation MCQ

# TCS Aptitude Paper 1 - Interview Preparation MCQ

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## 30 Questions MCQ Test Placement Papers - Technical & HR Questions - TCS Aptitude Paper 1

TCS Aptitude Paper 1 for Interview Preparation 2024 is part of Placement Papers - Technical & HR Questions preparation. The TCS Aptitude Paper 1 questions and answers have been prepared according to the Interview Preparation exam syllabus.The TCS Aptitude Paper 1 MCQs are made for Interview Preparation 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for TCS Aptitude Paper 1 below.
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TCS Aptitude Paper 1 - Question 1

### There are two water tanks A and B, A is much smaller than B. While water fills at the rate of 1 liter every hour in A, it gets filled up like, 10, 20, 40,80, 160..in tank B. 1/8 th of the tank B is filled in 22 hours. What is the time to fill the tank fully?

Detailed Solution for TCS Aptitude Paper 1 - Question 1

Tank B is filled in geometric progression, so after 22 hrs water in tank will be = 10 * 2^21 = x/8

where x = volume of tank x = 10 * 2^24 thus by geometric progression we get that n-1 = 24

so n = 25, hence time required is  25 hrs.

TCS Aptitude Paper 1 - Question 2

### A sheet of paper has statements numbered from 1 to 70. For all values of n from 1 to 70. Statement n says At least n of the statements on this sheet are false. Which statements are true and which are false?

Detailed Solution for TCS Aptitude Paper 1 - Question 2

Note: For this type of Questions, follow this:

--At least- Ist half are true, Last half are false

--Exactly- Last second one is true or (N-1)th Statement is true

--Almost- All are true.

Aliter :

Suppose the first 35 statements are true!

Statement 1: At least 1 statement is false [TRUE]

Statement 2: At least 2 statements are false   [TRUE]

...

Statement 35: At least 35 statements are false  [TRUE]

--------------------------------------------------------------------

Statement 36: At least 36 statements are false  [FALSE]

..

Statement 40: At least 40 statements are false  [FALSE]

-------------------------------------------------------------------

AT LEAST puts the minimum tag or the floor tag on the statements

So, if the first 35 statements are true and the rest are false, everything fits into place!

TCS Aptitude Paper 1 - Question 3

### Unnecessary data. A lady has fine gloves and hats in her closet- 18 blue- 32 red , 10 white , 25 yellow, 55 purple, 30 orange. The lights are out and it is totally dark in spite of the darkness. She can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a glove. How many gloves must she take out to make sure she has a pair of each color of blue, red, yellow?

Detailed Solution for TCS Aptitude Paper 1 - Question 3

Note: For this type of questions:

Bigger+Middle+1 (Suppose 18, 32, 25 =32+25+1), If you do not find answer in options, choose the one closer those the answer you got.

*Answer can only contain numeric values
TCS Aptitude Paper 1 - Question 4

The IT giant Tirnop has recently crossed a head count of 150000 and earnings of \$7 billion. As one of the forerunners in the technology front, Tirnop continues to lead the way in products and services in India. At Tirnop, all programmers are equal in every respect. They receive identical salaries and also write code at the same rate. Suppose 12 such programmers take 12 minutes to write 12 lines of code in total. How long will it take 72 programmers to write 72 lines of code in total?

Detailed Solution for TCS Aptitude Paper 1 - Question 4

12 prog 12 line 12 min

1 prog 12 line 12*12

1 1 12*12/12

72 1 12*12/(12*72)

72 72 12*12*72/(12*72)

TCS Aptitude Paper 1 - Question 5

12 people {a1, a2, a12} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3},  {a11, a12}, {a12, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is

Detailed Solution for TCS Aptitude Paper 1 - Question 5

12 x 11 / 2 = 66 Handshake

TCS Aptitude Paper 1 - Question 6

10 suspects are rounded by the police and questioned about a bank robbery. Only one of them is guilty. The suspects are made to stand in a line and each person declares that the person next to him on his right is guilty. The rightmost person is not questioned. Which of the following possibilities are true?

A. All suspects are lying.
B. leftmost suspect is innocent.
C. leftmost suspect is guilty

Detailed Solution for TCS Aptitude Paper 1 - Question 6

Here leftmost person is lying since there is nobody to his right!-U have to visualise the rightside of the person and not yours!

Ans is c . Here leftmost person is lying since there is nobody to his right!-

you have to visualise the rightside of the person and not yours!

< 1< 2< 3< 4< 5< 6< 7< 8< 9< 10 this is there right side they are facing u..10th right most of you not questioned left most of u is 1 he is guilty as he is saying that the person to his right is guilty but there is no one to his right and first statement is false as 2 is not lying as 1(left most of u) is guilty as 1 is guity then not innocent so neither of them

TCS Aptitude Paper 1 - Question 7

How many four digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4? Can you help Alok find the answer?

Detailed Solution for TCS Aptitude Paper 1 - Question 7

1= 5^4-1=125, n= no of digits

---  --- 1 2

--- --- 2 4

--- --- 3 2

--- --- 4 4

--- --- 5 2

The first two digits in the place can be filled in 5 x 5 ways.

So there are totally 25 x 5 = 125 ways

TCS Aptitude Paper 1 - Question 8

The age of the two friends were in the ration of 6:5.If the sum of their ages is 66.Then after how many years their ratio will become 7:6?

Detailed Solution for TCS Aptitude Paper 1 - Question 8

Let the age of two friends be 6x and 5x

Sum of their ages 66 => 6x + 5x = 66 => 11x = 66 => x=6

The ages will be 36 and 30

(36+k)/(30+k) = 7/6 => 36 x 6 + 6k = 210 + 7k

216 + 6k = 210 + 7k => 6 = k

After 6 years their ages will be in the ratio 7:6

TCS Aptitude Paper 1 - Question 9

The age of the two friends were in the ratio of 2:3.If the sum of their ages is 55.Then after how many years their ratio will become 4:5?

Detailed Solution for TCS Aptitude Paper 1 - Question 9

Let the age be the friends be 2x and 3x. Sum of their ages = 55

2x + 3x = 55 => 5x=55 => x=11

Their ages are 22 and 33

After k years both of them will be 22+k and 33+k years old

Ratio of their age at that time will me 4:5

• (22+k)/(33+k)=4/5
• 5(22+k)=4(33+4) => 110 + 5k = 132+4k
• K=132-110 = 22
TCS Aptitude Paper 1 - Question 10

A volume of 10936 l water is in a container of sphere.How many semisphere of volume 4l each will be required to transfer all the water into the small semispheres?

TCS Aptitude Paper 1 - Question 11

A person is manufacturing a house. He bought 20 ropes of wire which has a density of 300 Kg/m3.The height of the building to be constructed is 40 m. If the capacity of the current passed in the wire is 20 A and the voltage capacity is 80 Volts.Then what will be the opposing force to the current if the wire is used ?

Detailed Solution for TCS Aptitude Paper 1 - Question 11

by ohms law

v = ir

so r = v/i

so r = 80/20 = 4

TCS Aptitude Paper 1 - Question 12

A horse chases a pony 2 hours after the pony runs. Horse takes 3 hours to reach the pony. If the average speed of the horse is 81Kmph.Then what is the average speed of the pony?

Detailed Solution for TCS Aptitude Paper 1 - Question 12

Horse covers = 81*3 = 243 kms

So ponys speed = 243/(2+3) = 243/5 = 48.6

TCS Aptitude Paper 1 - Question 13

The difference between two no is 9 and the product of the two is 14.What is the square of their sum?

Detailed Solution for TCS Aptitude Paper 1 - Question 13

One number be x and other y, then  x - y = 9

(x - y)2 = 81

x2 + y2 = 81 + 2xy = 109

(x+y)2 = x2 + y2 + 2xy = 109 + 28 = 137

TCS Aptitude Paper 1 - Question 14

On planet korba, a solar blast has melted the ice caps on its equator. 9 years after the ice melts, tiny planetoids called echina start growing on the rocks. Echina grows in the form of circle, and the relationship between the diameter of this circle and the age of echina is given by the formula d = 4*v (t-9) for t = 9 where d represents the diameter in mm and t the number of years since the solar blast.Jagan recorded the radius of some echina at a particular spot as 7mm. How many years back did the solar blast occur?

Detailed Solution for TCS Aptitude Paper 1 - Question 14

The correct option is Option A.

r = 7

d = 14

Also, d =4 × (t-9)

So, 14 = 4t - 36

t = 12.25

Now, the plant starts growing after 9 years of blast.

So, 12.25 + 9 = 21.25

TCS Aptitude Paper 1 - Question 15

A man goes 50Km north , then turned left walked 40Km, then turned right ? In which direction he is?

Detailed Solution for TCS Aptitude Paper 1 - Question 15

Left and right consecutive movement nullified the change in direction. So, he is in the direction he started with.

TCS Aptitude Paper 1 - Question 16

In T. Nagar the building were numbered from 1 to 100.Then how many 6s will be present in the numbers?

TCS Aptitude Paper 1 - Question 17

Ferrari S.P.A is an Italian sports car manufacturer based in Maranello, Italy. Founded by Enzo Ferrari in 1928 as Scuderia Ferrari, the company sponsored drivers and manufactured race cars before moving into production of street-legal vehicles in 1947 as Ferrari S.P.A. Throughout its history, the company has been noted for its continued participation in racing, especially in Formula One where it has employed great success .Rohit once bought a Ferrari. It could go 4 times as fast as Mohans old Mercedes. If the speed of Mohans Mercedes is 35 km/hr and the distance traveled by the Ferrari is 490 km, find the total time taken for Rohit to drive that distance.

Detailed Solution for TCS Aptitude Paper 1 - Question 17

Mohans speed = 35 Km/hr

Rohit speed = 4 x Mohan speed = 4 x 35 = 140 Kmph

Time taken =Distance / Speed = 490 / 140 = 49/14 = 7/2

TCS Aptitude Paper 1 - Question 18

A man goes north 37km. turns left goes 2km.turns right goes 17km.turns right goes 2km. find distance b/w starting ending point.

Detailed Solution for TCS Aptitude Paper 1 - Question 18

Distance between the starting and end point is 37 + 17 = 54

TCS Aptitude Paper 1 - Question 19

If there are 30 cans out of them one is poisoned if a person tastes very little he will die within 14 hours so if there are mice to test and 24 hours to test, how many mices are required to find the poisoned can?

Detailed Solution for TCS Aptitude Paper 1 - Question 19

Have 6 mice for testing,

Give each mice contents from 5 cans each

5 5 5 5 5 5

After 14 hours, one of the mice will die

So, we will know which 5 cans must have the poison

Then , take the contents of these 5 cans and give to the remaining 5 mice each.

We will know in due time which can is poisoned

5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30

TCS Aptitude Paper 1 - Question 20

If a and b are mixed in 3:5 ration and b and c are mixed in 8:5 ration if the final mixture is 35 liters, find the amount of b?

Detailed Solution for TCS Aptitude Paper 1 - Question 20

a: b = 3:5

b: c =   8: 5

a:b:c  = 24 : 40 : 25  and total is 24+40+25 = 89

(40/89) x 35 = 15.73

TCS Aptitude Paper 1 - Question 21

It is the class with the seating arrangement in 4 rows and 8 columns. When the teacher says start the girl who is sitting in first row and first column will say 1, then the next girl sitting behind her will say 4, the next girl sitting behind that girl will say 7, in a particular order each girl is telling a number, the following girls told 10, 13 next turn is yours what u will say?

TCS Aptitude Paper 1 - Question 22

It is dark in my bedroom and I want to get two socks of the same color from my drawer, which contains 24 red and 24 blue socks. How many socks do I have to take from the drawer to get at least two socks of the same color?

Detailed Solution for TCS Aptitude Paper 1 - Question 22

The Answer is 25. First he will select 24 in that the maximum chance is all are redm so if we take one more socks, it has to be the other color. Hence, the answer is 24 + 1 = 25

TCS Aptitude Paper 1 - Question 23

If the Valentines Day in 2005 falls on Monday, then on which day will the Valentines Day fall on 2010?

Detailed Solution for TCS Aptitude Paper 1 - Question 23

FEB. 14, 2005   IS A  MONDAY

From Feb. 14, 2005 to Feb. 14 2006, there will be 365 days which means one odd day.

So, FEB. 14, 2006   WILL BE A  TUESDAY

From Feb. 14, 2006 to Feb. 14 2007, there will be 365 days which means one odd day.

So, FEB. 14, 2007   WILL BE A  WEDNESDAY

From Feb. 14, 2007 to Feb. 14 2008, there will be 365 days which means one odd day.

So, FEB. 14, 2008   WILL BE A  THURSDAY

From Feb. 14, 2008 to Feb. 14 2009, there will be 366 days

- add one more odd day for Feb.29. Total is 2 odd days.

So FEB. 14, 2009    WILL BE A  SATURDAY

From Feb. 14, 2009 to Feb. 14 2010, there will be 365 days

one  odd day .

So FEB. 14, 2010    WILL BE A  SUNDAY

TCS Aptitude Paper 1 - Question 24

An athlete decides to run the same distance in 1/4th less time that she usually took. By how much percent will she have to increase her average speed?

Detailed Solution for TCS Aptitude Paper 1 - Question 24

(3/4)t=1

t=4/3=1+1/3

She will have to increase her speed by 33.333% to run the same distance in 3/4s of the time..

TCS Aptitude Paper 1 - Question 25

In a building there are 5 rooms. Each having a equal area .The length of the room is 4m and bread ht is 5 m.The height of the rooms are 2m.If 17 bricks are needed to make a square meter then how many bricks are needed to make the floor of a particular room?

Detailed Solution for TCS Aptitude Paper 1 - Question 25

Dimensions = 4 x 5 x 2

TSA = 2 (4 x 5 + 5 x 2 + 4 x 2) = 2(20+10+8)=2x38 =  76 sq m

So bricks required = 76 x 17 = 1292

For 5 rooms 1292 x5 = 6460

TCS Aptitude Paper 1 - Question 26

One man want to build a wall .The length and breadth of the wall are 20 and 30 respectively. He need 35 bricks for one square centimeter then how many bricks he need?

Detailed Solution for TCS Aptitude Paper 1 - Question 26

Area = 20 x 30 = 600 cm2

Bricks = 600 x 35 = 21000

TCS Aptitude Paper 1 - Question 27

In a hotel we can order two types of varieties,but we can make 6 more varieties in home.One can choose the four varieties with two from hotel as must.Find how many ways one can order.

Detailed Solution for TCS Aptitude Paper 1 - Question 27

No of ways of selecting 2 from hotel (6 choices) = 6C2

And from home (2 choices) = 2C2

2C2 x  6C2  = 1 x 15 = 15 ways

TCS Aptitude Paper 1 - Question 28

If a pipe can fill the tank within 6hrs. But due to leak it takes 30 min more.Now the tank is full then how much time will it take to empty the tank throught the leak.?

Detailed Solution for TCS Aptitude Paper 1 - Question 28

Let the capacity of the tank be 6 litre.

Then time to fill this tank is 6 hour ,when there is no leakage .

so in 1 hour it fills 1 litre.

when leakage is there then it takes 6.5 hour to fill 6 litre

so in 1 hour it fills 6/6.5 litre.

Time to vacate will be 1-(6/6.5) = 1/13 litre in 1 hour

time to vacate 1 litre will be 13 hour.

For 6 litre it will be 13*6 =78

TCS Aptitude Paper 1 - Question 29

The bacteria has the probability of split into 3 and probability to die is 1/3rd of the total bacteria.Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?

Detailed Solution for TCS Aptitude Paper 1 - Question 29

Probability for the bacteria to be dying = 1/3

Hence probability of survival = 1/5

if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5)

TCS Aptitude Paper 1 - Question 30

There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability

Detailed Solution for TCS Aptitude Paper 1 - Question 30

Probability of bacteria to die is 1/3

or its get tripled, hence the probability of getting tripled is (2/3)*p*p*p that is  (2/3)*p^3

so both the probability combined as P=1/3+(2/3*p^3)

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