JEE  >  BITSAT Mock Tests Series & Past Year Papers  >  BITSAT Chemistry Test - 6 Download as PDF

BITSAT Chemistry Test - 6


Test Description

40 Questions MCQ Test BITSAT Mock Tests Series & Past Year Papers | BITSAT Chemistry Test - 6

BITSAT Chemistry Test - 6 for JEE 2023 is part of BITSAT Mock Tests Series & Past Year Papers preparation. The BITSAT Chemistry Test - 6 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Chemistry Test - 6 MCQs are made for JEE 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Chemistry Test - 6 below.
Solutions of BITSAT Chemistry Test - 6 questions in English are available as part of our BITSAT Mock Tests Series & Past Year Papers for JEE & BITSAT Chemistry Test - 6 solutions in Hindi for BITSAT Mock Tests Series & Past Year Papers course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt BITSAT Chemistry Test - 6 | 40 questions in 50 minutes | Mock test for JEE preparation | Free important questions MCQ to study BITSAT Mock Tests Series & Past Year Papers for JEE Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you?
BITSAT Chemistry Test - 6 - Question 1

Hydrogen bonding is maximum in

BITSAT Chemistry Test - 6 - Question 2

The energy of a hydrogen atom in its ground state is -13.6eV. The energy of the level corresponding to the energy level equal to 5 is

BITSAT Chemistry Test - 6 - Question 3

The organic compound which will answer the Fehling solution test is

BITSAT Chemistry Test - 6 - Question 4

Which of the following is not a nucleophile?

BITSAT Chemistry Test - 6 - Question 5

The most stable free radical among the following is

BITSAT Chemistry Test - 6 - Question 6

The number of electrons in the M shell of the element with atomic number 24 is

BITSAT Chemistry Test - 6 - Question 7

In graphite, the electrons are

BITSAT Chemistry Test - 6 - Question 8

Amino acids are produced by the hydrolysis of

BITSAT Chemistry Test - 6 - Question 9

The enzyme which hydrolyses triglycerides to fatty acids and glycerol, is called

BITSAT Chemistry Test - 6 - Question 10

A is a higher phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by having a solution

BITSAT Chemistry Test - 6 - Question 11

Which of the following is a polar compound?

BITSAT Chemistry Test - 6 - Question 12

The law of mass action was given by

BITSAT Chemistry Test - 6 - Question 13

Which relation is correct ?

BITSAT Chemistry Test - 6 - Question 14

t1/4 can be taken as the time taken for the concentration of a reactant to drop to (3/4) of its initial value. If the rate constant for a first order reaction is K, the t1/4 can be written as

BITSAT Chemistry Test - 6 - Question 15

The heat of combustion of methane at 298K is expressed by
C H 4 g + 2 O 2 g → C O 2 g + 2 H 2 O l , Δ H = − 890.2 k J . The magnitude of Δ E of the reaction at this temperature is

BITSAT Chemistry Test - 6 - Question 16

The name of the element with atomic number 100 was adopted in honour of

Detailed Solution for BITSAT Chemistry Test - 6 - Question 16

Fermium (symbol Fm and atomic number 100) was named for the American physicist Enrico Fermi. It is a synthetic, radioactive, metallic transuranic element of the actinide series.

BITSAT Chemistry Test - 6 - Question 17

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour?
(Atomic numbers : Zn = 30, Cr = 24, Co = 27, Ni = 28)

BITSAT Chemistry Test - 6 - Question 18

Which of the following compounds is aspirin?

BITSAT Chemistry Test - 6 - Question 19

Which of the following factors may be regarded as the main cause of lanthanide contraction?

BITSAT Chemistry Test - 6 - Question 20

How many moles of acidified FeSO₄ solution can be completely oxidised by one mole of KMnO₄?

BITSAT Chemistry Test - 6 - Question 21

The oxidation no. of nitrogen in NaNO₂ is

Detailed Solution for BITSAT Chemistry Test - 6 - Question 21

The formal oxidation state of the nitrogen atom in a nitrite is +3. This means that it is can be either oxidised to oxidation states +4 and +5 or reduced to oxidation states as low as -3.

BITSAT Chemistry Test - 6 - Question 22

A σ - bond is

BITSAT Chemistry Test - 6 - Question 23

Which one of the following will undergo meta-substitution on monochlorination ?

BITSAT Chemistry Test - 6 - Question 24

Iodoethane reacts with sodium in the presence of dry ether. The main product is

BITSAT Chemistry Test - 6 - Question 25

Nascent hydrogen consists of

BITSAT Chemistry Test - 6 - Question 26

The pH of gastric juice is normally

BITSAT Chemistry Test - 6 - Question 27

The stereoisomers which are neither superimposable nor mirror-image are called

BITSAT Chemistry Test - 6 - Question 28

Which among MeX, RCH₂X, R₂CHX, R₃CX is most reactive towards SN2 reaction?

BITSAT Chemistry Test - 6 - Question 29

Wood charcoal is used to decolourise sugar because it

BITSAT Chemistry Test - 6 - Question 30

A deep brown gas is formed by mixing two colourless gases which are

BITSAT Chemistry Test - 6 - Question 31

The correct order of increasing stability is

BITSAT Chemistry Test - 6 - Question 32

Which one is metaboric acid?

BITSAT Chemistry Test - 6 - Question 33

The polymer which has amide linkage is

BITSAT Chemistry Test - 6 - Question 34

Graphite is

BITSAT Chemistry Test - 6 - Question 35

Which of the following does not illustrate the anomalous properties of Li?

BITSAT Chemistry Test - 6 - Question 36

Which of the following carbonates decomposes readily at low temperatures?

BITSAT Chemistry Test - 6 - Question 37

From a salt solution of Cu, 0.534 g of Mg displaces 1.415 g of Cu. If equivalent weight of Mg is 12, then equivalent weight of Cu will be

BITSAT Chemistry Test - 6 - Question 38

The volume of 2.8g of carbon monoxide at 27oC and 0.821 atm pressure is (R = 0.0821 lit atm mol⁻1K⁻1)

BITSAT Chemistry Test - 6 - Question 39

Volume of 0.1 M K₂Cr₂O₇ required to oxidise 35 ml of 0.5 M FeSO₄ solution is

BITSAT Chemistry Test - 6 - Question 40

A liquid is found to scatter a beam of light but leaves no residue when passed through the filter paper. The liquid can be described as a/an

Use Code STAYHOME200 and get INR 200 additional OFF
Use Coupon Code
Information about BITSAT Chemistry Test - 6 Page
In this test you can find the Exam questions for BITSAT Chemistry Test - 6 solved & explained in the simplest way possible. Besides giving Questions and answers for BITSAT Chemistry Test - 6, EduRev gives you an ample number of Online tests for practice