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BITSAT Logical Reasoning Test - 10 - JEE MCQ


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20 Questions MCQ Test BITSAT Mock Tests Series & Past Year Papers 2025 - BITSAT Logical Reasoning Test - 10

BITSAT Logical Reasoning Test - 10 for JEE 2024 is part of BITSAT Mock Tests Series & Past Year Papers 2025 preparation. The BITSAT Logical Reasoning Test - 10 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Logical Reasoning Test - 10 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Logical Reasoning Test - 10 below.
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BITSAT Logical Reasoning Test - 10 - Question 1

In the given letter series, some of the letters are missing. Choose the correct alternatives.

ae__u__oaua__oue__au__eo__

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 1

aeoueoau | aeoueoau | aeou

Hence, correct answer is oeeoau.

BITSAT Logical Reasoning Test - 10 - Question 2

Directions: Given below are two statements followed by two conclusions numbered I and II. You have to take the given two statements to be true even if they seem to be at variance from commonly known facts. Read the conclusions and then decide which of them logically follow(s) from the given statements, disregarding commonly known facts.

Statements:
All girls are boys.
No boy is teacher.

Conclusions:
I.
No teacher is girl.
II. No girl is teacher.

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 2


Both conclusions follow.

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BITSAT Logical Reasoning Test - 10 - Question 3

In the following question, four figures are given. Out of them, find the set of three figures that can be joined to form a right triangle

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 3

On joining the figures a, c and d, we get

Therefore, it is the correct option.

BITSAT Logical Reasoning Test - 10 - Question 4

Directions: The following question consists of a pair of words, which have a certain relationship with each other. Select the alternative which bears the same relationship as the original pair of words does.

Disabuse : Error

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 4

The first word leads to elimination of the second word. 'Disabuse' means to free someone of 'error', misconception, or fallacy and 'discredit' means to deprive one of one's reputation. Option 2 shares the same relation and is the correct answer.
(1) - 'Persevere' means to continue in a course of action even in the face of difficulties. 'Dereliction' means shameful failure to fulfil one's obligations.
(3) - 'Exonerate' means to absolve (someone) from blame for a fault or wrongdoing. 'Addiction' is an unrelated word.
(4) - 'Asperse' means to attack or criticize someone's reputation or integrity. 'Imperfection' is an unrelated word.
(5) - 'Parry' means to ward off (a weapon or attack) with a countermove. 'Blitz' means an intensive or sudden military attack.
Except 2, none of the other pairs bear the same analogy as the original pair of words.

BITSAT Logical Reasoning Test - 10 - Question 5

Choose the odd numeral pair from among the following:

(a) 18 - 31, (b) 23 - 36, (c) 62 - 79, (d) 47 - 60

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 5

As

But,

So, 62 - 79 is different from the others.
Hence, this is the required solution.

BITSAT Logical Reasoning Test - 10 - Question 6

In the following question, select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 6

The given numbers are :

In the first column, adding the first three numbers, we get

Similarly, for the second column, we get

Similarly, for the third column, we get

So, the answer is 20.

BITSAT Logical Reasoning Test - 10 - Question 7

Six roads lead to a country. They are indicated by letters X, Y, Z and digits 1, 2, 3. When there is a storm, Y is blocked. When there are floods, X, 1 and 2 will be affected. When road 1 is blocked, Z is blocked as well. At a time when there are both floods and storms, which road(s) can be used?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 7

Due to the storm, road Y is blocked.
Due to the floods, roads X, 1 & 2 are affected.
Hence, road Z also gets blocked.
At a time when there are both floods and storms, X, Y, Z, 1 and 2 can not be used.
So, only road 3 can be used.

BITSAT Logical Reasoning Test - 10 - Question 8

Examine the following statements:
I. Either A and B are of the same age or A is older then B.
II. Either C and D are of the same age or D is older than C
III. B is older than C.

Which one of the following conclusions can be drawn from the above statements?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 8

(1) A ≥ B
(2) D ≥ C
(3) B > C
Then either B & D are of same age or B is older than D and  A  is older than D.
Thus A will older than C.

BITSAT Logical Reasoning Test - 10 - Question 9

Seven men, A, B, C, D, E, F and G are standing in a queue in that order. Each one is wearing a cap of a different colour like violet, indigo, blue, green, yellow, orange and red not particularly in that order. D is able to see in front of him green and blue but not violet. E can see violet and yellow, but not red. G can see caps of all colours other than orange, if E is wearing an indigo coloured cap, then the colour of the cap worn by F is

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 9

A person can see caps of all persons standing in front of him but can't see his own cap and caps of persons standing behind him.

Given that E wears indigo cap.
D is able to see in front of him green and blue, but not violet which means the people in front of D i.e., A or B or C wore green or blue and people after D and including himself i.e., D or E or F or G wore violet. E can see violet and yellow but not red.

Clearly, D is wearing violet cap and A/B/C wore green/blue/yellow not necessarily in that order. G can see caps of all colours other than orange which means he is the last person in the row, he can see all caps except his. So, we can say G is wearing orange cap.

So, we can summarise all this information in a table

Finally, we are left with red cap which means F is wearing it.

BITSAT Logical Reasoning Test - 10 - Question 10

The president of a club is appointing nice officials A, B, C, D, E, F, G, H and I to serve on three committees to study three different aspects of activities of the club. There will be a Games Committee, a Food Service Committee and an Entertainment Committee. The appointments must respect the following:

Each committee must have exactly three members.
No person can serve on more than one committee.
H must serve on the entertainment committee.
C and D must serve on the same committee.
A and B cannot serve on the same committee.
E cannot serve on the same committee as I.
F must serve on the committee as B or H or both B and H.

If B and G serve on the Game Committee, which of the following must serve on the Food Service Committee?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 10


Left Members are ADEC and I.
Now A and B should be separate. Let us assume that A is in Entertainment committee and C and D have to be together so we place them in food committee. E and I have to be separate so we can place E in entertainment committee.
Hence D is in the food committee

BITSAT Logical Reasoning Test - 10 - Question 11

A, B, C, D and E are standing in a line facing north. C stands in the middle. B and E cannot stand with C. A is not standing to the right of C. Who is standing second from the left end? 

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 11

Here a linear seating arrangement has been given, and we have to find out the person who is standing second from the left end.
So, the arrangement can be seen as follows:

So, as per the arrangement, we can see that the first and last places can be assumed for only B and E, and for the third and fourth position.
So, the correct answer is A which is in the second position.

BITSAT Logical Reasoning Test - 10 - Question 12

A, B, C, D, E and F, not necessarily in that order, are sitting on six regularly placed chairs around a round table. It is observed that A is between D and F. C is opposite to D. D and E are not on neighbouring chairs. Which one of the following pairs must be sitting on neighbouring chairs?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 12


Based on the given data, the above figure can be drawn. The pairs A and B, B and F, and F and C are clearly not neighbours. As it can be seen from the figure, C and E are sitting on the neighbouring chairs.

BITSAT Logical Reasoning Test - 10 - Question 13

In a group of six women, there are four tennis players, four post-graduates in Sociology, one post-graduate in Commerce and three Bank employees. Vimala and Kamala are among the Bank employees while Amala and Komala are unemployed. Komala and Nirmala are among the tennis players. Amala, Kamala, Komala and Nirmala are post-graduates in Sociology of whom two are Bank employees. If Shyamala is a post-graduate in Commerce who among the following is both a tennis player and a bank employee?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 13

Let’s list down the information given in the question in tabular format.

Clearly, Nirmala is both a bank employee and a tennis player.
Hence, the correct answer is Nirmala.

BITSAT Logical Reasoning Test - 10 - Question 14

Six friends A, B, C, D, E and F are seated in a circle facing centre. If F is between A and D, C is between E and B, E is not between D and C, and D is second to the left of C. Which one of the following is the position of D? 

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 14

According to the given statements, A, B, C, D, E will be seated around the circle as follows-
F is seated between A and D. C is between E and B. E is not between D and C and D is second to the left of C. Let's fix C first and then place D. So, E will be on the right of C and B on the left of C. Thus, F will be on the left of D and A will be on the left of D.

Clearly, D is sitting second to the right of A.
Hence, this is the correct answer.

BITSAT Logical Reasoning Test - 10 - Question 15

Answer the questions on the basis of the following information:

A, B, C, D, E, F and G are members of a club. Everyone likes to go to the club only one day in a week (but not necessarily in this sequence Mon, Tues, Wed, Thurs, Fri, Sat and Sunday). They have cars manufactured by different companies (but not necessarily in this sequence Maruti, Ford, Honda, Toyota, Tata, Mahindra, Fox Wagon). C likes to go to club on Wednesdays and his car is neither Tata nor Fox Wagon. E does not like to go to the club on Mondays, and he has a Toyota car. One who likes to go to the club on Fridays, has a Honda car. One who has a Mahindra car, likes to go to club on Tuesdays. D likes to go to the club on Saturdays. F likes to go to club on Thurdays while B doesn't have a Mahindra car. Tell the following:

Who likes to go to club on Tuesdays?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 15

The table below shows who likes to go to clubs on which day and the car they have. Look closely for the answer.

From the above table, it is clear that A likes to go the clubs on Tuesday whereas B goes on Friday, C on Wednesday, D on Saturday, E on Sunday, F on Thursday and G on Monday. So, the required answer is A as per this above table and he/she  has Mahindra car.

BITSAT Logical Reasoning Test - 10 - Question 16

On the basis of two figures of dice, you have to tell what number will be there at the bottom, if 5 is at the top?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 16

In this question, we have given two dices. Now, we have to find out the number on the opposite side of the number given in the question.
From the figure, first observed the common number between two dices.
Hence, 2 is the common number between the two dices, so arrange the number by rotating the numbers in the clockwise direction from the common number e.g 2. And the other two pairs thus formed will be the opposite.
Now,
From figure 1 − 2 4 1
From figure 2 − 2 6 3
Here, 4 is opposite to 6 and 1 is opposite to 3.5 is the only number left so if 5 is at the top then 2 is at the bottom.
Hence, the correct answer is option B.

BITSAT Logical Reasoning Test - 10 - Question 17

The given two positions are of the same dice whose each surface bears a number among 1, 2, 3, 4, 5, and 6. What number is at the opposite of 3 in the figure shown below?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 17

In this question, we have given two dices.
We have to find out the number on the opposite side of the number given in the question.
From the figure, observed the common number between two dices.
5 is the common number between the two dices, so arrange the number by rotating the numbers in the clockwise direction from the common number e.g 5.
The other two pairs thus formed will be the opposite.
Now,
From figure 1 − 5 6 2
From figure 2 − 5 1 4
Here, 3 will be the opposite of 5.
So, 5 is the correct option.
Hence, the correct answer is option C.

BITSAT Logical Reasoning Test - 10 - Question 18

Which number is on the face opposite to face having number 1?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 18

In this question, we have given three dices.
Now, we have to find out the number on the opposite side of the number given in the question.
From all the figure, we made a complete figure by taking one of the figures, which satisfy all three figure.

Thus 2 is opposite to 6. (from the first and second figure).
4 is opposite to 5. (from the first and last figures).
Hence, 1 is opposite to 3.
So, the correct answer is option B.
Thus, the option B is the correct answer.

BITSAT Logical Reasoning Test - 10 - Question 19

Which alphabet will come on the opposite surface of which alphabet F will appear?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 19

In this question, we have given three dices. Now, we have to find out the letter on the opposite side of the letter given in the question.
From all the three-figure, we took first as a reference figure and made the main figure as follows.

Using 1st and 3rd figure we get A opposite to D.
Using the second and third figure we get E opposite to B.
Hence, C comes opposite to F.
So, the correct answer is option C.

BITSAT Logical Reasoning Test - 10 - Question 20

Two positions of a dice are shown below. Identify the number at the bottom when the top is 3?

Detailed Solution for BITSAT Logical Reasoning Test - 10 - Question 20

In this question, we have given two dices. Now, we have to find out the number on the opposite side of the number given in the question.
From the figure, first observed the common number between two dices.
Hence, 6 is the common number between the two dices, so arrange the number by rotating the numbers in the clockwise direction from the common number e.g. 6. And the other two pairs thus formed will be the opposite.
Now,
From figure 1−6 4 5
From figure 2−6 1 3
Here, 4 is opposite to 1 and 5 is opposite to 3. So, if 3 is at the top then 5 is at the bottom.
Hence, this is the correct answer.

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