BITSAT Mock Test - 5 - JEE MCQ

When a variable force acts on a particle while it moves from point A to B, say along the path shown in the figure, work done by the force on the particle is given by

To form a stationary wave, waves y and y' must travel in opposite directions.
Wave y = a cos (kx - ωt) travels along the positive x-direction.
Waves y' = -a cos (kx - ωt) and y' = -a sin (kx - ωt) in choices (2) and (4) travel along positive x-direction.
Hence choices (2) and (4) are not possible. Choice (1) is also incorrect becasue at x = 0
y' = a sin ωt and y = a cos (-ωt) = a cos ωt
Therefore, the resultant displacement at x = 0 which is y + y' = a sin ωt + a cos ωt is not zero, i.e. these waves do not produce a node at x = 0.
Choice (3) is correct because at x = 0, y + y' = 0.

As the path difference is
Corresponding phase difference is

if the Intensity of the source is
Then the intensity of the interference pattern is given by

Between t = 0 and t = 2s, the speed of the body is v = slope of the (x - t) graph between t = 0 and t = 2s, i.e.,

At t = 2s, the velocity of the body is reversed and it moves in the opposite direction with a speed = -1 ms^-1. Therefore,
Impulse = change in momentum
= mv - (-mv) = 2mv
= 2 × 0.4 kg × 1 ms^-1
= 0.8 kg ms^-1 = 0.8 Ns
Hence, the correct choice is (3).

The growth of current in an LR circuit is given by

where I₀ is the maximum current. The energy stored at time t is

We are required to find the time at which the energy stored is one-fourth the maximum value, i.e. when


i.e.
Using this in Eq. (1), we get

or
or log_e(2), which is choice (2).

Since the block moves with a constant velocity, no net force acts on it. Therefore, the horizontal component F cos θ of force F must balance with the friction force, i.e. f_r = F cos θ. Also

Which is choice (2).

In two dimensional sheet silicates, three oxygen atoms each of unit are shared.

Cyclic silicates are obtained by sharing two oxygen atoms each of tetrahedron.

Chain silicates are formed by sharing of two oxygen atoms each of unit.

For Lyman series,
Hence, for to be the smallest, n should be the greatest (i.e. ).

= 1.097 x 10^-2 nm^-1

The correct order of boiling points is: Trimethylamine < Ethylmethylamine < Propylamine
This is because branched isomers have a lesser surface area and a lower boiling point.

Hence, option 2 is correct.

In the given passage, it is highlighted that exercise is crucial. It also highlights how various birds and animals take care of this aspect in their little activities - "I think nature is the best physical instructor." So, option (2) best explains it.

The series is following the pattern:
11² - 2 = 119
12² - 3 = 141
13² - 4 = 165
14² - 5 = 191
15² - 6 = 219
16² - 7 = 249

D + 4 = H, H + 5 = M, M + 6 = S
E + 4 = I, I + 5 = N, N + 6 = T
F + 4 = J, J + 5 = O, O + 6 = U

The figure rotates 45° in the anticlockwise direction. The blank circle attached to the head of the figure is changed from shaded to unshaded or vice-versa. Also, the angled line attached to the figure goes to the other side. After following this pattern, Answer figure (c) is obtained.

Rosy likes yellow and is a student. Mary and Andy like purple and blue, respectively, and neither of them is a teacher. The inspector likes blue, which means Andy is the inspector.

Lily likes brown. The librarian likes green.

Mary and Andy like purple and blue, respectively, and neither of them is a teacher. One of the five is a principal. Mary could not be the teacher, so Mary is the principal and Lily is the teacher.

So, the teacher likes brown colour.
Hence, option 2 is correct.

Rosy likes yellow and is a student. Mary and Andy like purple and blue, respectively, and neither of them is a teacher. The inspector likes blue, which means Andy is the inspector.

Lily likes brown. The librarian likes green.

Mary and Andy like purple and blue, respectively, and neither of them is a teacher. One of the five is a principal. Mary could not be the teacher, so Mary is the principal and Lily is the teacher.

'Rosy - Teacher' is a wrong pair. Rosy is a student.
Hence, option 4 is correct.

5 × 3 × 4 × 2 = = 12
5 × 6 × 3 × 2 = = 18
5 × 2 × 9 × 2 = = 18
Correct option is (4).

Second is the special property of the first. Wool is warm and spring is elastic.

=
⁼
=
= {log_e a + log_e b + log_e c + log_e d

x⁶ - 1 = 0
(x³)² - 1 = 0
or, (x³ - 1)(x³ + 1) = 0
As we know, (x³ - 1) = 0
or, (x - 1)(x² + x + 1) = 0
∴ The roots are 1, ω and ω².
Similarly when (x³ + 1) = 0
or, (x + 1)( x² - x + 1 ) = 0
Then x = -1, x = - ω and x = - ω²
Hence, x = 1, -1, ω, ω² , - ω and - ω²
(Where, ω = )