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150 Questions MCQ Test BITSAT Mock Tests Series & Past Year Papers | Test: BITSAT Mock Test- 4

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Test: BITSAT Mock Test- 4 - Question 1

In a transformer the primary has 500 turns and secondary has 50 turn. 100 volts are applied to the primary coil, the voltage developed in the secondary will be

Test: BITSAT Mock Test- 4 - Question 2

An oil drop carrying a charge q has a mass m kg. It is falling freely in air with terminal speed ν. The electric field required to make the drop move upwards with the same speed is

Test: BITSAT Mock Test- 4 - Question 3

If six identical cells each having an e.m.f of 6V are connected in parallel, the E.M.F of the combination is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 3

Test: BITSAT Mock Test- 4 - Question 4

Which of the following statements is correct

Test: BITSAT Mock Test- 4 - Question 5

An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If lengths and radii of the wires are in the ratio of 4 : 3 and 2 : 3, then ratio of the currents passing through the wires will be

Test: BITSAT Mock Test- 4 - Question 6

A nucleus ruptures into two nuclear parts which have their velocity ratio equal to 2:1. What will be the ratio of their nuclear radius

Test: BITSAT Mock Test- 4 - Question 7

The positron was discovered in the year

Test: BITSAT Mock Test- 4 - Question 8

A uniform chain of length 'L' hangs partly from a table which is kept in equilibrium by friction. The maximum length that can stand without slipping is l then coefficient of friction between the table and the chain is

Test: BITSAT Mock Test- 4 - Question 9

A series combination of R,L,C is connected to an a.c. source. If the resistance is 3Ω and the reactance is 4Ω, the power factor of the circuit is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 9

 

Test: BITSAT Mock Test- 4 - Question 10

If r represents the radius of the orbit of the satellite of mass m moving around the planet of mass M, then velocity of the satellite ν is obtained from the relation

Test: BITSAT Mock Test- 4 - Question 11

An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will be

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 11

Test: BITSAT Mock Test- 4 - Question 12

An electric dipole has the magnitude of its charge as q, and its dipole moment is p. It is placed in a uniform electric field E. If its dipole moment is along the direction of the field, then force acting on it and its potential energy are respectively

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 12

Test: BITSAT Mock Test- 4 - Question 13

At constant volume the specific heat of a gas is 3R/2, then the value of 'γ' will be

Test: BITSAT Mock Test- 4 - Question 14

Newton's law of cooling holds good only, if the temperature difference between the body and its surrounding is

Test: BITSAT Mock Test- 4 - Question 15

A proton and an electron both moving with the same velocity ν enter into a region of magnetic field directed perpendicular to the velocity of the particles. They will now move in circular orbits such that

Test: BITSAT Mock Test- 4 - Question 16

The material used for permanent magnet should have

Test: BITSAT Mock Test- 4 - Question 17

The normal density of gold is ρ and its bulk modulus is K. The increase in density of a lump of gold, when a pressure P is applied uniformly on all sides, is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 17

The decrease in volume of gold is ΔV = VP/ K .....(i)
If m is the mass of gold, its density ρ = m V . Due to a decrease ΔV in volume, the increase Δρ in the density is
Δρ = m/ ΔV = ρV/ ΔV
or ΔV = ρV/ Δρ .....(ii)
Equating (i) and (ii) we get Δρ = ρK/ P

Test: BITSAT Mock Test- 4 - Question 18

The surface tension of soap solution is 25*10⁻3 N-m⁻1. The excess pressure inside a soap bubble of diameter 1 cm is

Test: BITSAT Mock Test- 4 - Question 19

The co-ordinates of a moving particle at any time 't' are given by x = αt3 and y = βt3. The speed of the partcle at time 't' is given by

Test: BITSAT Mock Test- 4 - Question 20

A hollow sphere has radius 6.4 m. Minimum velocity required by a motor cyclist at bottom to complete the circle will be

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 20 Min velocity to complete vertical circle is V= √5gR =√5*10*6.4 =17.7 m/s approx
Test: BITSAT Mock Test- 4 - Question 21

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g = 9.8 m/s)

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 21

Interval of ball throw = 2 sec
If we want that minimum three (more than two) ball remain in air then time of flight of first ball must be greater than 4 sec
T > 4 sec
2u/g > 4 sec
⇒ u > 19.6 m/s
For u = 19.6. First ball will just strike the ground(in sky)
Second ball will be at highest point (in sky)
Third ball will be at point of projection or at ground (not in sky)

Test: BITSAT Mock Test- 4 - Question 22

A solid of density ρ₁ is floating in a liquid of density ρ₂. If ν is the volume of solid submerged in the liquid and V is the total volume of the solid, the ν/V is equal to

Test: BITSAT Mock Test- 4 - Question 23

A body of mass 2 kg has an initial velocity of 3 metres per second along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body from O after 4 seconds will be

Test: BITSAT Mock Test- 4 - Question 24

The normal magnifying power of a simple microscope is 6. The focal length of the convex lens used is

Test: BITSAT Mock Test- 4 - Question 25

Two simple pendulums of length 0.5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed... oscillations

Test: BITSAT Mock Test- 4 - Question 26

A convex lens has a focal length f. It is cut into two parts along a line perpendicular to principal axis. The focal length of each part will be

Test: BITSAT Mock Test- 4 - Question 27

A dics of radius 1 m is rotating with an angular velocity of 10 rad-s⁻1. The linear velocity of the dics on a point 0.5 m from its centre is

Test: BITSAT Mock Test- 4 - Question 28

To make the frequency double of a spring oscillator, we have to

Test: BITSAT Mock Test- 4 - Question 29

A man is sitting with folded hands on a revolving table. Suddenly, he stretches his arms. Angular speed of table would

Test: BITSAT Mock Test- 4 - Question 30

The current inside a copper voltameter

Test: BITSAT Mock Test- 4 - Question 31

If the moment of inertia of a wheel, having radius of gyration 60 cm, is 360 kg-m2, then mass of the wheel is

Test: BITSAT Mock Test- 4 - Question 32

Consider the following statements:
Assertion (A) : The internal energy of an ideal gas does not change during an isothermal process
Reason (R) : The decrease in volume of a gas is compensated by a corresponding increase in pressure when its temperature is held constant
Of these statements :

Test: BITSAT Mock Test- 4 - Question 33

In adiabatic expansion

Test: BITSAT Mock Test- 4 - Question 34

Weber is the unit of

Test: BITSAT Mock Test- 4 - Question 35

In soap bubble, colouration is obtained when illuminated by white light due to

Test: BITSAT Mock Test- 4 - Question 36

If ratio of amplitude of two waves is 4:3, then ratio of maximum and minimum intensity is

Test: BITSAT Mock Test- 4 - Question 37

Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be, (υ = 300 m/s)

Test: BITSAT Mock Test- 4 - Question 38

A particle is subjected to two mutually perpendicular simple harmonic motions such that its x and y coordinates are given by x = 2 sin ωt y = 2 sin (ωt + π/4) The path of the particle will be

Test: BITSAT Mock Test- 4 - Question 39

The force constant of a spring is k. And that of another spring of the same material is 2 k. If both the springs are streched through the same distance, then ratio between the works done by the springs is

Test: BITSAT Mock Test- 4 - Question 40

Two masses of 'M' and '4M' are moving with equal kinetic energy. The ratio of their linear moments is

Test: BITSAT Mock Test- 4 - Question 41

The reaction of Ethanol with H₂SO₄ does not give

Test: BITSAT Mock Test- 4 - Question 42

The equation ∆x.∆p ≥ h/4π shows

Test: BITSAT Mock Test- 4 - Question 43

Which of the following reactions is used for detecting presence of carbonyl group ?

Test: BITSAT Mock Test- 4 - Question 44

Electronic configuration of deuterium atom is

Test: BITSAT Mock Test- 4 - Question 45

The reaction, CH₂ = CH-CH₃ + HBr → CH₃CHBr - CH₃ is

Test: BITSAT Mock Test- 4 - Question 46

In the process of nitration, the electrophile formed is

Test: BITSAT Mock Test- 4 - Question 47

The four bonds in methane are directed in space at an angle of

Test: BITSAT Mock Test- 4 - Question 48

The most stable carbonium ion is:

Test: BITSAT Mock Test- 4 - Question 49

The reason for double helical structure of DNA is operation of

Test: BITSAT Mock Test- 4 - Question 50


The final product 'C' in the above reaction is

Test: BITSAT Mock Test- 4 - Question 51

Sweetest sugar is

Test: BITSAT Mock Test- 4 - Question 52

Given : C + 2S→CS₂ ; ∆H = 117 KJ
C + O₂→CO₂; ∆H = -393 KJ
S + O₂→ ; ∆H = -297 KJ
The heat of combustion of CS₂ to form CO₂ and SO₂ is

Test: BITSAT Mock Test- 4 - Question 53

The bond angle around the central atom is maximum for

Test: BITSAT Mock Test- 4 - Question 54

In which of the following case,does the reaction go farthest completion ?

Test: BITSAT Mock Test- 4 - Question 55

The rate of reaction is doubled for every 10o rise in temperature. The increase in reaction rate as a result of temperature rise from 10o to 100o is

Test: BITSAT Mock Test- 4 - Question 56

The hybird propellant consists of

Test: BITSAT Mock Test- 4 - Question 57

In an electrochemical cell, if Eo is the EMF of the cell involving 'n' mole of electrons, then ∆Go is

Test: BITSAT Mock Test- 4 - Question 58

Which of the following has least electron affinity?

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 58

Ar is an inert gas and the atoms of these elements have completely filled subshells.As a result, there is no room in their valence orbitals and the additional electron has to be placed in an orbital of next higher shell.

Test: BITSAT Mock Test- 4 - Question 59

The geometry of the compound [Pt(NH₃)₂Cl₂] is

Test: BITSAT Mock Test- 4 - Question 60

Nickel is purified by

Test: BITSAT Mock Test- 4 - Question 61

When acidified solution of K₂Cr₂O₇ is shaken with aqueous solution of FeSO₄, then

Test: BITSAT Mock Test- 4 - Question 62

4gram of hydrocarbon on complete combustion gave 12 • 571 gram of CO2 and 5 •143 gram of water. What is the empirical formula of the hydrocarbon

Test: BITSAT Mock Test- 4 - Question 63

The equivalent conductance of NaCl, HCl and C₂H₅COONa at infinite dilution are 126.45, 426.16 and 91 ohm⁻1 cm2 respectively. The eq. conductance of C₂H₅COOH is

Test: BITSAT Mock Test- 4 - Question 64

What is formed when calcium carbide reacts with heavy water?

Test: BITSAT Mock Test- 4 - Question 65

Acidic hydrogens are present in

Test: BITSAT Mock Test- 4 - Question 66

Isomers have essentially identical :

Test: BITSAT Mock Test- 4 - Question 67

sym-Tetrabromoethane on heating with Zn gives

Test: BITSAT Mock Test- 4 - Question 68

The pink colour of phenolphthalein, in alkaline medium, is due to

Test: BITSAT Mock Test- 4 - Question 69

BCl₃ is planar molecule because in this molecule boron is

Test: BITSAT Mock Test- 4 - Question 70

In graphite, electrons are

Test: BITSAT Mock Test- 4 - Question 71

Bio-gas and producer gas are made up of

Test: BITSAT Mock Test- 4 - Question 72

H₂S gas when passed through a solution of cations containing HCl precipitates the cations of second Group of qualitative analysis, but not those belonging to fourth Group. It is because

Test: BITSAT Mock Test- 4 - Question 73

Which of the following is amphoteric?

Test: BITSAT Mock Test- 4 - Question 74

In the extraction of sodium by Down's process, cathode and anode are respectively.

Test: BITSAT Mock Test- 4 - Question 75

Which is an example of thermosetting polymer?

Test: BITSAT Mock Test- 4 - Question 76

The movement of solvent molecules through a semipermeable membrane is called

Test: BITSAT Mock Test- 4 - Question 77

KO2 (potassium super oxide) is used in oxygen cylinders in space and submarines because it

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 77

Because it absorbs CO2 and increases O2 concentration according to the following reaction

4KO2 + 2CO2 → 2K2CO3 + 3O2

Test: BITSAT Mock Test- 4 - Question 78

Copper metal adopts ccp arrangement, the co-ordination number of Cu is

Test: BITSAT Mock Test- 4 - Question 79

An organic compound having carbon and hydrogen has 80% carbon. The empirical formula of the hydrocarbon is

Test: BITSAT Mock Test- 4 - Question 80

Crystalloids differ from colloids mainly in respect of

Test: BITSAT Mock Test- 4 - Question 81

In the expansion of [(x2)-(2x)]10 coefficient of x16 is

Test: BITSAT Mock Test- 4 - Question 82

The area bounded by the curve y = x and y = x3 is

Test: BITSAT Mock Test- 4 - Question 83

The tangent line x=0 to the circles x2+y2-2x-6y+9 touches y-axis at the point

Test: BITSAT Mock Test- 4 - Question 84

Given the circles x2 + y2 - 4x - 5 = 0 and x2 + y2 + 6x - 2y + 6 = 0. Let P be a point (α, β) such that the tangents from P to both the circles are equal. Then

Test: BITSAT Mock Test- 4 - Question 85

If |z| = 4 and arg z = (5π/6), then the value of z is

Test: BITSAT Mock Test- 4 - Question 86

The differential equation of family of curves y=Ae3x+Be5x where A,B are constants, is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 86

THe given equation is y = Ae3x + Be5x .....(1)
Differentiating w.r.t. x, we get y' = 3Ae3x + 5Be5x .....(2)
Differentiating again w.r.t. x, we get y" = 9Ae3x + 25Be5x .....(3)
[Now we find Ae3x and Be5x from (2) and (3)]
Multiplying (2) by 5 and subtracting (3) from the result 5y' - y" = 6Ae3x
or Ae3x = 1/6 (5y' - y")
Multiplying (2) by 3 and subtracting the result form (3), y" - 3y' = 10Be5x
or Be5x = 1/10 (y" - 3y')
Substituting the values of Ae3x and Be5x in (1), we get

Test: BITSAT Mock Test- 4 - Question 87

The solution of the equation (1-x2)dy+xydx=xy2dx is

Test: BITSAT Mock Test- 4 - Question 88

If f(x)=cosx, 0≤x≤(π/2), the value of 'c' for which f(x) satisfies Mean Value theorem is

Test: BITSAT Mock Test- 4 - Question 89

Find the sum of the series

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 89

Sum of the given series:

 

Test: BITSAT Mock Test- 4 - Question 90

The latus rectum of the hyperbola 16x2 - 9y2 = 144 is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 90

Test: BITSAT Mock Test- 4 - Question 91

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 91

Correct Answer :- b

Explanation :  y = 1/4(log(1+x)−log(1−x)) − 1/2tan-1x

dy/dx = 1/4 [2/(1−x2)) − 1/2(1+x2)) 

​= 1/4(2/(1−x2) − (1/2)*1/(1+x2))

= 1/2[((1+x2) − (1−x2))/(1−x4)]

= x2/(1−x4)

Test: BITSAT Mock Test- 4 - Question 92

From the top and the foot of a house h metres high the angles of elevation of the top of a tower are β and α respectively, then the height of the tower is

Test: BITSAT Mock Test- 4 - Question 93

If y = y(x) and [(2 + sin x)∕(y + 1)(dy∕dx)] = -cos x, y(0) = 1, then y (π∕2) equals

Test: BITSAT Mock Test- 4 - Question 94

The area of the region bounded by the curves y = |x-2|, x = 1, x = 3 and the x-axis is

Test: BITSAT Mock Test- 4 - Question 95

The order and degree of the differential equation (d4y/dx4) = y + (dy/dx)4 are respectively

Test: BITSAT Mock Test- 4 - Question 96

Cos⁻1(1/2) + 2 sin⁻1(1/2) is equal to

Test: BITSAT Mock Test- 4 - Question 97

If f(x) is a differentiable function such that f : R → R and f(1/n) = 0 ∀ n ≥1, n ∈ I, then

Test: BITSAT Mock Test- 4 - Question 98

Test: BITSAT Mock Test- 4 - Question 99

If A and B are square matrices of order 3 such that ∣A∣ = -1, ∣B∣ = 3, then ∣3 AB∣ =

Test: BITSAT Mock Test- 4 - Question 100

The system of equation x+y+z = 2, 3x-y+2z = 6 and 3x+y+z = -18 has

Test: BITSAT Mock Test- 4 - Question 101

The ratio of the altitude of the cone of greatest volume which can be inscribed in a given sphere to the diameter of the sphere is

Test: BITSAT Mock Test- 4 - Question 102

If a, b, c are distinct positive real numbers and a2 + b2 + c2 = 1, then ab + bc + ca is

Test: BITSAT Mock Test- 4 - Question 103

The combined equation of bisector of angles between lines represented by (x2+y2)√3=4xy is

Test: BITSAT Mock Test- 4 - Question 104

The tangents at the points on the parabola y2 = 4ax are at right angles if

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 104

Test: BITSAT Mock Test- 4 - Question 105

If P S P ′ is a focal chord of the parabola y2 = 4 a x and SL is its semi latus-rectum then S P , S L , S P ′ are in

Test: BITSAT Mock Test- 4 - Question 106

The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of there parallel lines is :

Test: BITSAT Mock Test- 4 - Question 107

In a Poisson distribution mean is 16, then S.D. is

Test: BITSAT Mock Test- 4 - Question 108

Two cards are drawn successively with replacement from a pack of 52 cards. The probability of drawing two aces is

Test: BITSAT Mock Test- 4 - Question 109

How many words are formed from the letters of the word EAMCET so that two vowels are never together?

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 109

 

Test: BITSAT Mock Test- 4 - Question 110

In Δ A B C , if 3 a = b + c , then cot B/2 • cot C/2 =

Test: BITSAT Mock Test- 4 - Question 111

In a Δ A B C , the correct formulae among the following are:

Test: BITSAT Mock Test- 4 - Question 112

If α,β,γ are the roots of the equation x3+4x+1 = 0 then (α+β)⁻1 + (β+γ)⁻1 + (γ+α)⁻1 is equal to

Test: BITSAT Mock Test- 4 - Question 113

The fourth, seventh and tenth terms of a G.P. are p, q and r respectively, then

Test: BITSAT Mock Test- 4 - Question 114

Sin⁻1(3/5) + tan⁻1(1/7) is equal to

Test: BITSAT Mock Test- 4 - Question 115

If a, b, c are in A.P., then 10ax+10, 10bx+10, 10cx+10, x ≠ 0 are in

Test: BITSAT Mock Test- 4 - Question 116

The quadratic function f (x) whose graph goes through the points (-1, 4), (1, 0) and (2, 1) is

Test: BITSAT Mock Test- 4 - Question 117

The length of the sub normal to the parabola y2=4ax at any point is equal to

Test: BITSAT Mock Test- 4 - Question 118

The line passing through points (1,0) and (-2,√3) makes following angle with x-axis

Test: BITSAT Mock Test- 4 - Question 119

The angle between the lines (x - 1)/1 = (y - 1)/1 = (z - 1)/2 and (x - 1)/(- √3 - 1) = (y - 1)/(√3 - 1) = (z - 1)/4 is

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 119

Correct Answer :- C

Explanation : cosθ = |(a1a2 + b1b2 + c1c2)/(a12 + b12 + c12)1/2 * (a22 + b22+ c22)½|

=> (x-x1)/a = (y-y1)/b = (z-z1)/c

a1 = 1             b1 = 1     c1 = 2

a2 = -√3-1        b2 = √3-1  c2 = 4

a1a2 + b1b2 + c1c2 = -√3 - 1 + √3 - 1 + 8 

=> 6

cosθ = |6/[(1+1+4)1/2 * (3+2√3+1+3-2√3+1+16)1/2|

cosθ = |6/[√6*√24]|

cosθ = 6/√144

cosθ = 6/12

cosθ = 1/2

θ = π/3

Test: BITSAT Mock Test- 4 - Question 120

If A (1,2,3),B(-1,-1,-1) be the pts., then the distance AB is

Test: BITSAT Mock Test- 4 - Question 121

The number of roots of the equation 2 sin2θ + 3 sin θ + 1 = 0 in 0,2 π is

Test: BITSAT Mock Test- 4 - Question 122

The equation 3sin2x + 10cosx - 6 = 0 is satisfied if

Test: BITSAT Mock Test- 4 - Question 123

cos20o cos40o cos80o=

Test: BITSAT Mock Test- 4 - Question 124

Find the Antonym of the word occurring in the sentence in capital letter as per the context.
The criminal was known to the police by VARIOUS names.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 124

'Various' means several and different

Test: BITSAT Mock Test- 4 - Question 125

Find the Antonym of AMBLE.

Test: BITSAT Mock Test- 4 - Question 126

Fill in the blank with appropriate word.
Even in today's modern society, people.....god to bring rains.

Test: BITSAT Mock Test- 4 - Question 127

Fill in the blank with appropriate word.
The passengers and crew members of the aeroplane had a.......escape when it was taking off from the runway.

Test: BITSAT Mock Test- 4 - Question 128

Choose the one which can be substituted for the given words/sentences :
The doctrine that human souls pass from one body to another at the time of death

Test: BITSAT Mock Test- 4 - Question 129

Let is a unit vector such that eq uals

Test: BITSAT Mock Test- 4 - Question 130

If are any three mutually perpendicular vectors of equal magnitude a then is equal to

Test: BITSAT Mock Test- 4 - Question 131

Choose the one which can be substituted for the given words/sentences :
Cutting for stone in the bladder

Test: BITSAT Mock Test- 4 - Question 132

Spot the error.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 132

'It is not only our duty' instead of 'Not only it is our duty'

Test: BITSAT Mock Test- 4 - Question 133

Spot the error.

Test: BITSAT Mock Test- 4 - Question 134

Spot the error.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 134

Correct answer is as the cost of the latter was much less

Test: BITSAT Mock Test- 4 - Question 135

Find the Synonym of the word occurring in the sentence in capital letter as per the context.
The article was so well written that it MERITED careful study.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 135

Merit as a verb means to earn or to deserve
Merit as a noun means to superior quality or worth; excellence.

Test: BITSAT Mock Test- 4 - Question 136

Find the Synonym of the word occurring in the sentence in capital letter as per the context.
Very few of our batsman have any real CONSISTENCY.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 136

Meaning of Consistent - A harmonious uniformity or agreement or constancy among things or parts or events.

Test: BITSAT Mock Test- 4 - Question 137

Complete the analogous pair.
Paddy : Field : : Steel : ?

Test: BITSAT Mock Test- 4 - Question 138

Group the following figures into three classes on the basis of identical properties.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 138

1,7,8 are all undivided geometrical figures.
3,5,6 are geometrical figures divided into two parts.
2,4,9 are geometrical figures divided into four parts.

Test: BITSAT Mock Test- 4 - Question 139

In this letter series, some of the letters are missing. Choose the correct letter given below -
c _ ac _ aa _ aa _ bc _ bcc

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 139

The series is ccacc/aabaa/bbcbb/cc

Test: BITSAT Mock Test- 4 - Question 140

Choose the word which is least like the other words in the group .

Test: BITSAT Mock Test- 4 - Question 141

Find out the term in the number series which is wrong.
1, 5, 14, 30, 55, 93

Test: BITSAT Mock Test- 4 - Question 142

Find the missing character.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 142

In the first column, 17-11=25-19=6.
In the second column, 12-6=34-28=6.
Let the missing number in the third column be x.
Then, x-8=19-11=8 or x=16.

Test: BITSAT Mock Test- 4 - Question 143

Please go through following and answer question no.128 to no.131

The prisoner awaited his chance. For three solid years he had schemed for this opportunity . Now that escape seemed so near at hand, those three years lost some of their monotony . But he would never forget the lashes, the close confinement, low diet , and worse still the mental strain of those black days . Suddenly the warden did what he had hoped . He stopped to unlock the lower padlock. With a dull thud he slumped forward with keys in his hands. Swiftly the prisoner seized his keys, unlocked the cell, and ran into the courtyard. It took him four seconds to reach the rope-ladder secretly placed there by his accomplices , five more to clamber over the wall, and three more to jump into the waiting car to be whisked away to freedom . Even though he was guilty , the prisoner felt he had paid for his crime, for the man he had robbed three years ago was still a millionaire .

Q. For what crime had the prisoner been punished ?

Test: BITSAT Mock Test- 4 - Question 144

Please go through following and answer question no.128 to no.131

The prisoner awaited his chance. For three solid years he had schemed for this opportunity . Now that escape seemed so near at hand, those three years lost some of their monotony . But he would never forget the lashes, the close confinement, low diet , and worse still the mental strain of those black days . Suddenly the warden did what he had hoped . He stopped to unlock the lower padlock. With a dull thud he slumped forward with keys in his hands. Swiftly the prisoner seized his keys, unlocked the cell, and ran into the courtyard. It took him four seconds to reach the rope-ladder secretly placed there by his accomplices , five more to clamber over the wall, and three more to jump into the waiting car to be whisked away to freedom . Even though he was guilty , the prisoner felt he had paid for his crime, for the man he had robbed three years ago was still a millionaire .

Q. When had the crime been committed ?

Test: BITSAT Mock Test- 4 - Question 145

Please go through following and answer question no.128 to no.131

The prisoner awaited his chance. For three solid years he had schemed for this opportunity . Now that escape seemed so near at hand, those three years lost some of their monotony . But he would never forget the lashes, the close confinement, low diet , and worse still the mental strain of those black days . Suddenly the warden did what he had hoped . He stopped to unlock the lower padlock. With a dull thud he slumped forward with keys in his hands. Swiftly the prisoner seized his keys, unlocked the cell, and ran into the courtyard. It took him four seconds to reach the rope-ladder secretly placed there by his accomplices , five more to clamber over the wall, and three more to jump into the waiting car to be whisked away to freedom . Even though he was guilty , the prisoner felt he had paid for his crime, for the man he had robbed three years ago was still a millionaire .

Q. Who slumped forward with a dull thud ?

Test: BITSAT Mock Test- 4 - Question 146

Please go through following and answer question no.128 to no.131

The prisoner awaited his chance. For three solid years he had schemed for this opportunity . Now that escape seemed so near at hand, those three years lost some of their monotony . But he would never forget the lashes, the close confinement, low diet , and worse still the mental strain of those black days . Suddenly the warden did what he had hoped . He stopped to unlock the lower padlock. With a dull thud he slumped forward with keys in his hands. Swiftly the prisoner seized his keys, unlocked the cell, and ran into the courtyard. It took him four seconds to reach the rope-ladder secretly placed there by his accomplices , five more to clamber over the wall, and three more to jump into the waiting car to be whisked away to freedom . Even though he was guilty , the prisoner felt he had paid for his crime, for the man he had robbed three years ago was still a millionaire .

Q. How many seconds did it take for the prisoner to regain his freedom ?

Test: BITSAT Mock Test- 4 - Question 147

Please go through following and answer question no.145 to no.146

Select the correct mirror image of the figure (X) from amongst the given alternatives.

Q. 

Test: BITSAT Mock Test- 4 - Question 148

Please go through following and answer question no.145 to no.146

Select the correct mirror image of the figure (X) from amongst the given alternatives.

Q.

Test: BITSAT Mock Test- 4 - Question 149

Please go through following and answer question no.147 to no.148

Each of the following questions consists of five Problem figures marked 1,2,3,4 and 5 followed by five Answer figures marked A,B,C,D and E . Select a figure from the Answer figures which will continue the same series as given in the Problem figures.

Q.

Detailed Solution for Test: BITSAT Mock Test- 4 - Question 149

The symbol gets vertically inverted and laterally inverted alternately. It also moves in ACW direction through distances equal to two half-sides (of square boundary) and three half-sides alternately.

Test: BITSAT Mock Test- 4 - Question 150

Please go through following and answer question no.147 to no.148

Each of the following questions consists of five Problem figures marked 1,2,3,4 and 5 followed by five Answer figures marked A,B,C,D and E . Select a figure from the Answer figures which will continue the same series as given in the Problem figures.

Q. 

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