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VITEEE PCME Mock Test - 5 - JEE MCQ


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30 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests - VITEEE PCME Mock Test - 5

VITEEE PCME Mock Test - 5 for JEE 2024 is part of VITEEE: Subject Wise and Full Length MOCK Tests preparation. The VITEEE PCME Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 5 below.
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VITEEE PCME Mock Test - 5 - Question 1

The rate of change of the volume of a sphere w.r.t. its surface area, when the radius is 2cm, is

VITEEE PCME Mock Test - 5 - Question 2

A real value of x will satisfy the equation
[((3 - 4 i x)/( 3 + 4i x))] = α - iβ ( α ,β real),if

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VITEEE PCME Mock Test - 5 - Question 3

VITEEE PCME Mock Test - 5 - Question 4

The area bounded by the curve y = (x + 1)2, y = (x - 1)2 and the line y = 1/4 is

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 4

Given curves are
(x + 1)2 = y .....(1)
and (x - 1)2 = y .....(2)
Axis of parabola (1) is x = - 1 and vertex is (- 1, 0) and it meets y-axis at (0,1)
Axis of parabola (2) is x = 1 and vertex is (1, 0) and it cuts y - axis at (0, 1)
When y = 1/4
from (2), x - 1 =   1/2
∴ x = 1/2 , 3/2
∴ C ≡ ( 1/2 , 1/4 )
Required area = 2 area BACB

VITEEE PCME Mock Test - 5 - Question 5

All the roots of the equation zn cos θo + zn − 1 cos θ1 + … + cos θn = 2 , where θo , θ1 , θ2 , … , θn ∈ R will satisfy

VITEEE PCME Mock Test - 5 - Question 6

where [x] denotes the greatest integer less than or equal to x, is continuous at x = 2, then the value of a is equal to

VITEEE PCME Mock Test - 5 - Question 7

 , then the value of x is

VITEEE PCME Mock Test - 5 - Question 8

If f(x)   = tanx/x , x ≠ 0 ; f x = 1, x = 0 , then the function at x = 0 is

VITEEE PCME Mock Test - 5 - Question 9

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 9

Multiply R1, R2, R3 by a, b, c respectively and divide by abc
Take abc common from C3 so that C1, C3 are identical

VITEEE PCME Mock Test - 5 - Question 10

A solution of the differential equation x (dy/dx)2 + (y-x) dy/dx - y = 0 is

VITEEE PCME Mock Test - 5 - Question 11

y = A ex + B e2x  + C e3x  satisfies the diferential equation

VITEEE PCME Mock Test - 5 - Question 12

The solution of differential equation (dy/dx)=[(1+y2)/(1+x2)] is

VITEEE PCME Mock Test - 5 - Question 13

If y=log logx, ey(dy/dx)=

VITEEE PCME Mock Test - 5 - Question 14

Which equation has the solution y=A sinx+B cosx?

VITEEE PCME Mock Test - 5 - Question 15

If f : A → B is a bijective function then f-1 ο f=

VITEEE PCME Mock Test - 5 - Question 16

∫ [sin(logx) + cos(logx)] dx =

VITEEE PCME Mock Test - 5 - Question 17

∫x cos x dx =

VITEEE PCME Mock Test - 5 - Question 18

If tan-1 x + tan-1 y + tan-1 z = π/2 , then 1 - xy - yz - zx =

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 18

Let tan-1 x = A, tan-1 y = B, tan-1 z = C,
Then x = tan A, y = tan B, z = tan C, A + B + C = π/2
A + B + C = π/2
⇒ tan (A + B + C) is not defined
⇒ 1 - S2 = 0
⇒ 1 - tan A tan B - tan B tan C - tan C tan A = 0
⇒ 1 - xy - yz - zx = 0

VITEEE PCME Mock Test - 5 - Question 19

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 19

if x is 1+h answer would be 2
if x is 1-h answer would be-2
so clearly limit does not exist

VITEEE PCME Mock Test - 5 - Question 20

VITEEE PCME Mock Test - 5 - Question 21

These questions are based on the following information. P, Q, R, S and T sit around a table. P sits two seats to the left of R and Q sits two seats to the right of R.

Q. If S is not sitting next to Q, who is sitting between Q and S?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 21

P sits two seats to the left of R, and Q sits two seats to the right of R. We can represent this information in the diagram below.

If S is not next to Q, then the seating arrangement is fixed as follows.

Now P is between Q and S. Choice (b)

VITEEE PCME Mock Test - 5 - Question 22

These questions are based on the following information. P, Q, R, S and T sit around a table. P sits two seats to the left of R and Q sits two seats to the right of R.

Q. If a new person U joins the group such that the initial conditions for the seating arrangement should be observed and also a new condition that U does not sit next to R be satisfied, then which of the following statements is true?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 22

P sits two seats to the left of R, and Q sits two seats to the right of R. We can represent this information in the diagram below.

On the basis of the diagram that we drew, we find that to accommodate U we have to create a new slot between P and Q.

Hence, choice (c) is the correct answer. Choice (c)

VITEEE PCME Mock Test - 5 - Question 23

These questions are based on the following information. P, Q, R, S and T sit around a table. P sits two seats to the left of R and Q sits two seats to the right of R.

Q. If a new person U joins the group such that the initial conditions for the seating arrangement should be observed and also a new condition that U does not sit next to P, S or T be satisfied, then who will be the neighbours of P (one on either side)?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 23

P sits two seats to the left of R, and Q sits two seats to the right of R. We can represent this information in the diagram below.

We create a new slot for the sixth person. But since U will not sit next to P, S or T, he will have to sit between R and Q. The arrangement will then look as follows:

As we can see from the diagram, the neighbours of P will be T and S.

VITEEE PCME Mock Test - 5 - Question 24

Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)


Q. What is the difference between the peak hydel power production and the least Hydel Power Production ?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 24

Difference between the peak hydel power production and the least hydel power production = 180 - 100 = 80 million watts
So, option (4) is correct.

VITEEE PCME Mock Test - 5 - Question 25

Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)

Q. In which year is the total power production (thermal + hydel) the greatest?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 25

Total power production (thermal and hydel) in 1990 = 140 + 140 = 280 million watts
Total power production (thermal and hydel) in 1991 = 140 + 180 = 320 million watts
Total power production (thermal and hydel) in 1992 = 100 + 120 = 220 million watts
Total power production (thermal and hydel) in 1993 = 150 + 130 = 280 million watts
Total power production (thermal and hydel) in 1994 = 155 + 145 = 300 million watts
Total power production (thermal and hydel) in 1995 = 153 + 141 = 294 million watts
Total power production (thermal and hydel) in 1996 = 145 + 145 = 290 million watts
The total power production is the greatest in 1991, i.e. 320 million watt.

VITEEE PCME Mock Test - 5 - Question 26

Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)

Q. What is the average thermal power production for the period 1990-1996?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 26

Required average = = 141.85 million watts

Hence, option (4) is correct.

VITEEE PCME Mock Test - 5 - Question 27

Directions: Study the following graph carefully and answer the question given below.

Q. If the population of a city is 35,000 and the average income of a person in that city is Rs. 25,000 per annum, then what is the total amount of tax paid by all the persons of that city?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 27

Tax paid by one person of that city = 8/100 x 25,000 = Rs. 2000

Total tax paid by all the persons of that city = 2000 × 35,000 = Rs. 70,000,000

VITEEE PCME Mock Test - 5 - Question 28

In some code, letters a, b, c, d and e represent numbers 2, 4, 5, 6 and 10. We just do not know which letter represents which number. Consider the following relationships:

I. a + c = e,
II. b – d = d and
III. e + a = b

Which of the following options are true?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 28

We have a + c = e so possible summation 6+4=10 or 4+2 = 6.
Also b = 2d so possible values  4 = 2 * 2 or 10 = 5 * 2.
So considering both we have b = 10 , d = 5, a= 4 ,c = 2, e = 6.
Hence the correct option is B .

VITEEE PCME Mock Test - 5 - Question 29

The sum of the first 100 natural numbers, 1 to 100 is divisible by: 

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 29

The sum of the first 100 natural numbers is:

=  (n * (n + 1)) / 2
=  (100 * 101) / 2
=  50 * 101

101 is an odd number and 50 is divisible by 2.
Hence, 50 * 101 will be divisible by 2.

VITEEE PCME Mock Test - 5 - Question 30

In a four-digit number, the sum of the first 2 digits is equal to that of the last 2 digits. The sum of the first and last digits is equal to the third digit. Finally, the sum of the second and fourth digits is twice the sum of the other 2 digits. What is the third digit of the number?

Detailed Solution for VITEEE PCME Mock Test - 5 - Question 30

Let the 4 digit no. be xyzw.
According to given conditions we have x + y = z + w, x + w = z, y + w = 2x + 2z.
With help of these equations, we deduce that y = 2w, z = 5x.
Now the minimum value x can take is 1 so z = 5 and the no. is 1854, which satisfies all the conditions. Hence option A.

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