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# VITEEE Physics Test - 1

## 40 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests | VITEEE Physics Test - 1

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This mock test of VITEEE Physics Test - 1 for JEE helps you for every JEE entrance exam. This contains 40 Multiple Choice Questions for JEE VITEEE Physics Test - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this VITEEE Physics Test - 1 quiz give you a good mix of easy questions and tough questions. JEE students definitely take this VITEEE Physics Test - 1 exercise for a better result in the exam. You can find other VITEEE Physics Test - 1 extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

### In a transformer 220 A.C. voltage is increased to 2200 volts. If the number of turns in the secondary are 2000, then the number of turns in the primary will be

Solution:
Number of turns in primary coil ( Np ) = ?

Number of turns in Secondary coil ( Ns ) = 2000

Voltage in primary coil ( Ep ) = 220 V

Voltage in secondary coil ( Es ) = 2200 V .

Now, using formula:  Ep/Es = Np/Ns

Substituting values, we get,

220/2200 = Np/2000

=> Np = 200 turns .
QUESTION: 2

Solution:
QUESTION: 3

### Two wires of same metal have the same length but their cross sections are in the ratio 3:1. They are joined in series. The resistance of the thicker wire is 10 Ω. The total resistance of the combination is

Solution: QUESTION: 4

If elements with principal quantum number n > 4 were not allowed in nature, then, the number of possible elements would be

Solution:
QUESTION: 5

If a cell of constant electromotive force produces the same amount of heat during the same time in two independent resistances R₁ and R₂, when connected separately one after the other, across the cell, then the internal resistance of the cell is

Solution:

Solution :- Here current through the resistance R1 is I1 = ε/(r+R1)

and current through the resistance R2 is I2 = ε/(r+R2).

Also, the heat produced due to passage of current through both the resistances is same.

Hence, Q = (I1)^2R1 = (I2)^2R2

Using the values of I1 and I2 in above equation we get (ε/(r+R1))^2 R1 = (ε/(r+R2))^2 R2

where, ε is the emf and r is the internal resistance of battery.

ε^2 R1 / (r+R1)^2 = ε^2 R1 / (r+R1)^2

r^2(R1−R2) = R1R2((R1−R2​)

r^2= R1R2

∴ r = (R1R2)^1/2

QUESTION: 6

A wire of radius r has resistance R. If it is stretched to a radius of 3r/4, its resistance becomes

Solution:
QUESTION: 7

Optical fibres uses the phenomenon of

Solution:
QUESTION: 8

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is

Solution:

Energy required = 1 2 CV2 = 1 2 ε0 E2Ad

QUESTION: 9

Determine the current drawn from a 12 v supply with internal resistance 0.5Ω by the infinite network shown in the figure . Each resistor has Ω resistance Solution:

Let the equivalent resistance of the network be x×1

Rs=1+1+1+1

x = xΩ

The effective resistance x and 1Ω are in parallel Now, the resistance Rp,1Ω and 1Ω are in series. For infinite resistance  neglecting the negative value,

Resistance of the network Total resistance of the circuit = 2.732 + 0.5 = 3.232Ω

Current  QUESTION: 10

A cell whose e.m.f. is 2V and internal resistance is 0.1Ω, is connected with a resistance of 3.9Ω. The voltage across the cell terminal will be

Solution:

Solution :- EMF of the cell(E) =2 V

internal resistance(r)= 0.1 V

External resistance(R)=3.9 V

V=IR

=(E÷(R+r))×R

=(2÷(3.9+0.1))×3.9

=1.95 V

Therefore potential difference across the terminals of the cell = 1.95V

QUESTION: 11

In an electron gun, the electrons are accelerated by the potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will be

Solution:
QUESTION: 12

A bar magnet dropped into a coil of a conducting wire, along its axis, will fall with an acceleration

Solution:
QUESTION: 13

A generator at a utility company produces 100 A of current at 4000 V. The voltage is stepped up to 240000 V by a transformer before it is sent on a high voltage transmission line. The current in transmission line is

Solution:
QUESTION: 14
A 220 V, 1000 watt bulb is connected across a 110 V mains supply. The power consumed will be
Solution:
QUESTION: 15

What is the cause of "Greenhouse effect"?

Solution:
QUESTION: 16

Consider the situation in the figure. The work done in taking a point charge from P to Ais WA, from P to B is WB and from P to C is WC. Solution:

WA = WB = WC

Points A, B and C lie at the same distance from the charge q, i.e. they are lying on an equipotential surface. So, work done in moving a charge from A to B (WAB) or B toC (WBC) is zero.
Hence, work done in bringing a charge from P to A  = WA,
from P to B, WB = WA+WAB = WA
and from P to C, WC = WA + WAB + WBC = WA​

Hence, WA = WB = WC

QUESTION: 17

A dust particle of mass 10-3 gm is stationary between the plates of a horizontal parallel plate capacitor of 0 .016m separation which is connected to a voltage of 100V. How many fundamental charges (e = 1.6 x 10-19 C)   the dust particle carries

Solution:
QUESTION: 18
An electron of charge e coulomb passes through a potential difference of V volt. Its energy in joule will be
Solution:
QUESTION: 19

A capacitor of capacity C1 is charged upto V volt and then connected to an unchanged capacitor of capacity C2. The potential difference across each capacitor will be

Solution:

Charge on first capacitor = q1 = C11
Charge on second capacitor = q2 = 0
When they are connected, in parallel the total charge
q = q1 + q2
∴ q = C11
and capacitance, C = C1 + C2
Let V' be the common potential difference across each capacitaor, then q = CV'
∴ V' = q C = C1V/ C1 + C2

QUESTION: 20

A charge q is placed at the corner of a cube of side l. The electric flux passing through the cube is

Solution:

Eight cubes, each side l, are required to form a Gaussian surface
So that the charge q at the corner of a small cube appears at the centre of the bigger cube
According to Gauss's law, the electric flux through the bigger cubes = q ∈ 0
Hence the electric flux through the given small cube = q 8∈ 0

QUESTION: 21

Dielectric constant of a medium is unity. Its permittivity will be:

Solution:

--

QUESTION: 22

If a current is passed in a spring, it

Solution: Two conductors will attract each other if they have current flowing in same direction. in a spring each loop has current flowing in same direction resulting in contraction of the spring.
QUESTION: 23

The phenomena in which proton flips is

Solution:
QUESTION: 24

The first atomic reactor was constructed by

Solution:
QUESTION: 25

The average binding energy of the nucleon is

Solution:
QUESTION: 26

If in a photoelectric experiment, the wavelength of incident radiation is reduced from 6000Å to 4000Å, then

Solution:
Ans : (B)
ϕ=hcλ−eV∘ϕ= work function of a particular metal will remain constant
If λ = incident radiation wavelength is increased,
V∘ = stopping potential also has to increase to keep ϕ constant.
QUESTION: 27

When a centimeter thick surface is illuminated with light of wavelength λ, stopping potential is V. When the same surface is illuminated by light of wavelength 2 λ, stopping potential is V/3. Threshold wavelength for metallic surface is

Solution:
Let the threshold wavelength = λ
the energy required by photo electrons to escape = h c/λ
e V + hc/λ = hc/l
e V/3 + hc/λ = hc/2l
=>  h c/l = 4/3 * eV
=>  hc/λ = 1/3 * eV
=>   λ = 4 l
QUESTION: 28

In Ramsden's eye-piece, the distance from the eye lens at which the image due to objective of focal length f is formed is

Solution:
The distance of image fanned by the objective lens from the eye lens = 2F/3 + F/4
= 8F + 3F/12
= 11F/12
QUESTION: 29

Which of the following spectrum have all the frequencies from high to low frequency range ?

Solution:
QUESTION: 30

While a collector emitter voltage is constant in a transistor, the collector current changes by 8.2 m A .When the emitter current changes by 8.3 m A, the value of forward current ratio hfe is

Solution: QUESTION: 31

When the p-end of the p-n junction is connected to the negative terminal of the battery and the n-end to the positive terminal of the battery, then the p-n junction behaves like

Solution:
QUESTION: 32

Potential barrier developed in a junction diode opposes

Solution:
QUESTION: 33

In semiconductors, at the room temperature

Solution:
QUESTION: 34

In a semiconductor the separation between conduction band and valence band is of the order of

Solution:
QUESTION: 35

When the electrical conductivity of a semiconductor is due to the breaking of its covalent bonds, then the semiconductor is said to be

Solution:
QUESTION: 36

P-N junction diode is reverse biased when

Solution:
QUESTION: 37

Huygen's wave theory of light can not explain

Solution:
QUESTION: 38

Bright colours exhibited by spider's web, exposed to sun light are due to

Solution:
QUESTION: 39

An astronout is looking on earth's surface from a sapce shuttle at an altitude of 500 km. Assuming that the astronaut's pupils' diameter is 5 mm and the wavelength of visible light is 500 nm, the astronaut will be able to resolve linear objects of the size of about

Solution: QUESTION: 40

A train is approaching a platform with a velocity ν. The frequency heard by an observer standing at the station is

Solution: