VITEEE Physics Test - 1


40 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests | VITEEE Physics Test - 1


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This mock test of VITEEE Physics Test - 1 for JEE helps you for every JEE entrance exam. This contains 40 Multiple Choice Questions for JEE VITEEE Physics Test - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this VITEEE Physics Test - 1 quiz give you a good mix of easy questions and tough questions. JEE students definitely take this VITEEE Physics Test - 1 exercise for a better result in the exam. You can find other VITEEE Physics Test - 1 extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

In a transformer 220 A.C. voltage is increased to 2200 volts. If the number of turns in the secondary are 2000, then the number of turns in the primary will be

Solution:
Number of turns in primary coil ( Np ) = ? 

Number of turns in Secondary coil ( Ns ) = 2000 

Voltage in primary coil ( Ep ) = 220 V 

Voltage in secondary coil ( Es ) = 2200 V .

Now, using formula:  Ep/Es = Np/Ns

Substituting values, we get,

220/2200 = Np/2000 

=> Np = 200 turns . 
QUESTION: 2

In a photo electric experiment the maximum velocity of photo electons emitted

Solution:
QUESTION: 3

Two wires of same metal have the same length but their cross sections are in the ratio 3:1. They are joined in series. The resistance of the thicker wire is 10 Ω. The total resistance of the combination is

Solution:
QUESTION: 4

If elements with principal quantum number n > 4 were not allowed in nature, then, the number of possible elements would be

Solution:
QUESTION: 5

If a cell of constant electromotive force produces the same amount of heat during the same time in two independent resistances R₁ and R₂, when connected separately one after the other, across the cell, then the internal resistance of the cell is

Solution:

 Answer :- d

Solution :- Here current through the resistance R1 is I1 = ε/(r+R1)

and current through the resistance R2 is I2 = ε/(r+R2).

Also, the heat produced due to passage of current through both the resistances is same.

Hence, Q = (I1)^2R1 = (I2)^2R2

Using the values of I1 and I2 in above equation we get (ε/(r+R1))^2 R1 = (ε/(r+R2))^2 R2 

where, ε is the emf and r is the internal resistance of battery.

ε^2 R1 / (r+R1)^2 = ε^2 R1 / (r+R1)^2

r^2(R1−R2) = R1R2((R1−R2​)

r^2= R1R2

∴ r = (R1R2)^1/2

QUESTION: 6

A wire of radius r has resistance R. If it is stretched to a radius of 3r/4, its resistance becomes

Solution:
QUESTION: 7

Optical fibres uses the phenomenon of

Solution:
QUESTION: 8

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is

Solution:

Energy required = 1 2 CV2 = 1 2 ε0 E2Ad

QUESTION: 9

Determine the current drawn from a 12 v supply with internal resistance 0.5Ω by the infinite network shown in the figure . Each resistor has Ω resistance

Solution:

Let the equivalent resistance of the network be x×1

Rs=1+1+1+1

x = xΩ

The effective resistance x and 1Ω are in parallel

 

Now, the resistance Rp,1Ω and 1Ω are in series.

For infinite resistance

applying the quadratic formula

neglecting the negative value,

Resistance of the network

Total resistance of the circuit = 2.732 + 0.5 = 3.232Ω

Current 

QUESTION: 10

A cell whose e.m.f. is 2V and internal resistance is 0.1Ω, is connected with a resistance of 3.9Ω. The voltage across the cell terminal will be

Solution:

Answer :- c

Solution :- EMF of the cell(E) =2 V

internal resistance(r)= 0.1 V

External resistance(R)=3.9 V

V=IR

=(E÷(R+r))×R

=(2÷(3.9+0.1))×3.9

=1.95 V

Therefore potential difference across the terminals of the cell = 1.95V

QUESTION: 11

In an electron gun, the electrons are accelerated by the potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will be

Solution:
QUESTION: 12

A bar magnet dropped into a coil of a conducting wire, along its axis, will fall with an acceleration

Solution:
QUESTION: 13

A generator at a utility company produces 100 A of current at 4000 V. The voltage is stepped up to 240000 V by a transformer before it is sent on a high voltage transmission line. The current in transmission line is

Solution:
QUESTION: 14
A 220 V, 1000 watt bulb is connected across a 110 V mains supply. The power consumed will be
Solution:
QUESTION: 15

What is the cause of "Greenhouse effect"?

Solution:
QUESTION: 16

Consider the situation in the figure. The work done in taking a point charge from P to Ais WA, from P to B is WB and from P to C is WC.
 

Solution:

WA = WB = WC

Points A, B and C lie at the same distance from the charge q, i.e. they are lying on an equipotential surface. So, work done in moving a charge from A to B (WAB) or B toC (WBC) is zero.
Hence, work done in bringing a charge from P to A  = WA,
from P to B, WB = WA+WAB = WA
and from P to C, WC = WA + WAB + WBC = WA​

Hence, WA = WB = WC 

QUESTION: 17

A dust particle of mass 10-3 gm is stationary between the plates of a horizontal parallel plate capacitor of 0 .016m separation which is connected to a voltage of 100V. How many fundamental charges (e = 1.6 x 10-19 C)   the dust particle carries

Solution:
QUESTION: 18
An electron of charge e coulomb passes through a potential difference of V volt. Its energy in joule will be
Solution:
QUESTION: 19

A capacitor of capacity C1 is charged upto V volt and then connected to an unchanged capacitor of capacity C2. The potential difference across each capacitor will be

Solution:

Charge on first capacitor = q1 = C11
Charge on second capacitor = q2 = 0
When they are connected, in parallel the total charge
q = q1 + q2
∴ q = C11
and capacitance, C = C1 + C2
Let V' be the common potential difference across each capacitaor, then q = CV'
∴ V' = q C = C1V/ C1 + C2

QUESTION: 20

A charge q is placed at the corner of a cube of side l. The electric flux passing through the cube is

Solution:


Eight cubes, each side l, are required to form a Gaussian surface
So that the charge q at the corner of a small cube appears at the centre of the bigger cube
According to Gauss's law, the electric flux through the bigger cubes = q ∈ 0
Hence the electric flux through the given small cube = q 8∈ 0

QUESTION: 21

Dielectric constant of a medium is unity. Its permittivity will be:

Solution:

--

QUESTION: 22

If a current is passed in a spring, it

Solution: Two conductors will attract each other if they have current flowing in same direction. in a spring each loop has current flowing in same direction resulting in contraction of the spring.
QUESTION: 23

The phenomena in which proton flips is

Solution:
QUESTION: 24

The first atomic reactor was constructed by

Solution:
QUESTION: 25

The average binding energy of the nucleon is

Solution:
QUESTION: 26

If in a photoelectric experiment, the wavelength of incident radiation is reduced from 6000Å to 4000Å, then

Solution:
Ans : (B)
ϕ=hcλ−eV∘ϕ= work function of a particular metal will remain constant
If λ = incident radiation wavelength is increased,
V∘ = stopping potential also has to increase to keep ϕ constant.
QUESTION: 27

When a centimeter thick surface is illuminated with light of wavelength λ, stopping potential is V. When the same surface is illuminated by light of wavelength 2 λ, stopping potential is V/3. Threshold wavelength for metallic surface is

Solution:
Let the threshold wavelength = λ
the energy required by photo electrons to escape = h c/λ
e V + hc/λ = hc/l
e V/3 + hc/λ = hc/2l
=>  h c/l = 4/3 * eV
=>  hc/λ = 1/3 * eV 
=>   λ = 4 l
QUESTION: 28

In Ramsden's eye-piece, the distance from the eye lens at which the image due to objective of focal length f is formed is

Solution:
The distance of image fanned by the objective lens from the eye lens = 2F/3 + F/4 
= 8F + 3F/12
= 11F/12
QUESTION: 29

Which of the following spectrum have all the frequencies from high to low frequency range ?

Solution:
QUESTION: 30

While a collector emitter voltage is constant in a transistor, the collector current changes by 8.2 m A .When the emitter current changes by 8.3 m A, the value of forward current ratio hfe is

Solution:
QUESTION: 31

When the p-end of the p-n junction is connected to the negative terminal of the battery and the n-end to the positive terminal of the battery, then the p-n junction behaves like

Solution:
QUESTION: 32

Potential barrier developed in a junction diode opposes

Solution:
QUESTION: 33

In semiconductors, at the room temperature

Solution:
QUESTION: 34

In a semiconductor the separation between conduction band and valence band is of the order of

Solution:
QUESTION: 35

When the electrical conductivity of a semiconductor is due to the breaking of its covalent bonds, then the semiconductor is said to be

Solution:
QUESTION: 36

P-N junction diode is reverse biased when

Solution:
QUESTION: 37

Huygen's wave theory of light can not explain

Solution:
QUESTION: 38

Bright colours exhibited by spider's web, exposed to sun light are due to

Solution:
QUESTION: 39

An astronout is looking on earth's surface from a sapce shuttle at an altitude of 500 km. Assuming that the astronaut's pupils' diameter is 5 mm and the wavelength of visible light is 500 nm, the astronaut will be able to resolve linear objects of the size of about

Solution:
QUESTION: 40

A train is approaching a platform with a velocity ν. The frequency heard by an observer standing at the station is

Solution:

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