AFMC Chemistry Mock Test - 1 - NEET MCQ

When ethernal vapours are passed on heated , Aluminia ether compound is mainly formed. Therefore, A is the correct option. 

On acidic hydrolysis of sodium phenoxide , gives phenol . This process of preparation of phenol from chloro benzene is known as Dow process . The Dow process is an aromatic nucleophilic substitution reaction . The reaction is carried out through active benzyne inter mediate formation

CH3COOH (acetic acid) cannot reduce Fehling solution while HCOOH, HCHO and CH3CHO reduce Fehling solution due to the presence of CHO group

Deuterium is an isotope of hydrogen and atomic no. of hydrogen is 1 so the electronic configuration of deuterium is 1s¹

19(X) = 1s2 2s2 2p6 3s2 3p6 4s1
so M shell means 3rd shell has 8 electrons
21(Y) = 1s2 2s2 2p6 3s2 3p6 4s2 3d1
so M shell has 9 electrons
25(Z) = 1s2 2s2 2p6 3s2 3p6 4s2 3d5
so M shell has 13 electrons hence the order is Z>Y>X

There are two gonadotrophic hormone: follicle stimulating hormone (FSH) and luteinizing hormone (LH), in both males and females. In males, FSH promotes spermatogenesis in the seminiferous tubules, which also release the hormone inhibin. Inhibin acts to inhibit luteinizing hormone secretion by the anterior pituitary gland

Two methyl free radical combine to form ethane , this electrolysis method(kolbes electrolysis) is used for preparation of even number of carbon containing alkanes.

In CO₂​, O = C = O is the structural formula and C is sp hybridised. CO₂​ is linear molecule.
In H₂​O, Oxygen is sp³ hybridised and shape is angular. 
In BeCl₂​, Be is  sp hybridised with no lone pairs and is a linear molecule.

3H₂ + N₂ → 2NH₃
∴ 3V 1V → 2V
Total initial volume = 3V + 1V = 4V
Final volume = 2V
Hence, ratio of initial and final volume will be 2 : 1

Equilibrium constant depends on temperature and is independent of the presence of a catalyst. It is also independent of concentrations, pressures and volumes of reactants and products.

As N has extra stable half-filled electronic configuration (1s² 2s² 2p³) , therefore it is difficult to remove an electron from nitrogen and ionisation potential of N is higher.

In the conversion of ice to water and water to water vapour entropy increases at both steps therefore these conversions are spontaneous.

Orange 1 is red organic compound known as azo dyes.

The size of cation is always smaller than the corresponding atom. This is because, due to the removal of electron (or electrons) from the neutral atom, the number of electrons in the cation decreases, but its nuclear charge remains the same as that of the atom. As a result, the force of attraction by the nucleus on the electrons increases, and the size of the atom decreases. Similarly, the size of anion is always larger than the corresponding atom due to the small effective nuclear charge and large screening effect.

An oxidising agent itself undergoes reduction. Its oxidation number decreases. When H₂​ is converted to hydride ion H⁻, it itself is reduced and acts as oxidisng agent.

In the following reactions, hydrogen is acting as an oxidising agent.

With lithium to give lithium hydride

H₂​+2Li→2LiH

In the following reactions, hydrogen is acting as a reducing agent.

With iodine to give hydrogen iodine

H_2​+I₂​→2HI

With nitrogen to give ammonia

3H₂​+N₂​→2NH₃​

With sulphur to give hydrogen sulphide

H₂​+S→H_2​S

Neopentane is the only compound which has neither secondary nor tertiary hydrogen as the centre carbon's valency is satisfied by 4 other carbons (methyl groups) and not by hydrogen atoms.

Oxidation no.of Na = 1
oxidation no. of O = -2
let oxidation no of S = x
2(1) + 4(x) + 6(-2) = 0
2 + 4x - 12 = 0
4x = 10
x = 2.5

NaCl as it increase the hydration & rearrangment process of the reaction of the constituent materials.

Pyrolusite is manganese dioxide (MnO₂) and is an oxide ore of manganese. It is a black, amorphous appearing mineral, often with a granular, fibrous, or columnar structure.

Mg and Li have similar properties due to diagonal relationship. They behave similarly due to same polarising power which depends on the ratio of ionic charge to ionic radius, in short they have same ionic potential

Baeyer's reagent is alkaline KMnO₄​, it reacts with unsaturated hydrocarbon (alkene, alkyne, etc.) and decolourises its pink colour. And silver nitrate reacts with acidic hydrogen of alkyne and makes white precipitate. Among the given options, methane and ethane are alkanes, so they don't react with either solution.

 Ethylene is unsaturated but doesn't have acidic hydrogen, so it react with Baeyer's reagent but does not react with silver nitrate. Alkyne reacts with both reagents.

According to standard electrode, Ba,Pb and Sn have lower reduction potential than H⁺ so, they can reduce it to H²​ but as Hg has higher reduction potential than H⁺ so, it can not reduce it.

n = 45 / 15 = 3,
Amount left =
1 / 2³ [A₀] = 1 / 8 [A_o] = 12.5%