SRMJEE Mock Test - 2 (Medical) - JEE MCQ

In a medium of higher refractive index, a convex lens diverges a parallel beam of light, thus behaving a diverging lens.
Hence, μ₁ < μ₂.

The refractive index of glass prism is:
= =
, where v is the speed of the light in glass.
v =

From the mirror formula, we have

^{1/f = 1/v + 1/u} ...(i)
where v is the image distance and u is the object distance.
Differentiating Eq. (i), we get
0 = - 1/v₂ dv - 1/u²du
⇒ dv = - v²/u² du ...(ii)
Given, du = b
∴ dv = - v²/u²  × b
From Eq. (i), we have

⇒
∴ ...(iii)
From Eqs. (ii) and (iii), we get
dv = -b
Hence, size of the image is .

Rate of decay = 

[Let w  is weight of ¹⁴⁰La, then ]

w = 1.79 × 10⁻⁶ g

Motion is uniformly accelerated.

Given:
Initial velocity, u = 0
Acceleration, a = a
Velocity at time t = n is v = v

Therefore, the distance traveled in n seconds is given by:

s = ut + (1/2) a t²
Since u = 0, we get:
s = (1/2) a n² ...(i)

Let the distance traveled in (n − 2) seconds be s₁.

Using the equation s = ut + (1/2) a t², we get:
s₁ = 0 + (1/2) a (n − 2)²
Expanding,
s₁ = (1/2) a (n² − 4n + 4) ...(ii)

Now, the distance traveled in the last two seconds is S:

S = s − s₁
Substituting values from (i) and (ii):
S = (1/2) a n² − (1/2) a (n² − 4n + 4)
Simplifying,
S = (1/2) a (4n − 4)
S = 2a (n − 1) ...(iii)

Since the options are given in terms of v, we need to eliminate a from equation (iii).

Using the equation v = u + at, we get:
v = 0 + an
Thus, a = v/n

Substituting this in equation (iii):
S = 2v (n − 1) / n

Lenz's law of electromagnetic induction corresponds to the law of conservation of energy.
According to Lenz's law, the direction of emf induced in the coil is such that it opposes the change in magnetic flux responsible for its production. Thus, it denotes the law of conservation of energy.

For triangle ΔABC, A + 90° + (90° − i) = 180°

Or, i = A

Now, the complementary angle at point D, θ = 2i

∴ θ = 2A

Only option (b) satisfies this.

According to Kepler's law

T² ∝ r³

∴ T₂ = 40 hr

The maximum height attained by the ball thrown upwards is given as:

H_max = 60 + H'

where H' is the vertical height attained by the ball due to its velocity.

H' = (u²) / (2g) = (20²) / (2 × 10) = 20 m

⇒ H_max = 60 + 20 = 80 m

Hence, the maximum height attained by the ball from the ground is 80 m.

From the law of equipartition of energy law, the total kinetic energy of the gas is KE = f/2nRT, which is proportional to the temperature.
At absolute zero temperature, kinetic energy of the gas molecules becomes zero, but they may possess some potential energy, so we cannot say that absolute zero degree temperature is zero energy temperature.
The RMS speed of a gas is given by .
For different gases or at different temperature, it will be different. But it does not depend on the pressure.
From the ideal gas equation, PV = nRT, two different gases at same temperature, pressure and volume will have the same number of moles and same number of molecules.

sForinusoidal alternating current or triangualr and square wave alternating current the average value for a period is always zero.

But in case of following currnet peak value will not be equal to rms value.

If AC is the square wave then all these three options are possible. i.e.,

I_rms = I_av = I₀, here I₀ is peak value

Neoprene is synthetic rubber. It is a polymer of chloroprene and is resistant to the action of oils, gasoline and other solvents.

In the above molecule, the central atom xenon undergo sp³ hybridisation, hence, the pi bonds are due to p orbitals of oxygen and d orbitals of xenon.

In the above molecule, the central atom sulphur undergo sp³ hybridisation, hence, the pi bond is pπ−dπ bond.

In the above molecule, the central atom sulphur undergo sp² hybridisation, hence, out of three pi bonds one pi bond is pπ−pπ bond and other two are pπ−dπ bonds.

In the above molecule, the central atom chlorine undergo sp³ hybridisation, hence, the two pi bonds are pπ−dπbonds.

For zero order kinetics

⇒R = R_O − kt

Stability order decide by
(A) Octet rule
(B) Polar Resonating Structure < Non- Polar Resonating Structure
(C) Negatively charge OH is high E.N. Atom and positively charge OH less E.N. atom.

H₂O → H₂ + 1/2O₂
During electrolysis, volumes of O₂ and H₂ liberated are in the ratio of 1 : 2 Hence, volume of H₂ liberated
= 2 × 2.24dm³
= 4.48dm³

The transition period between the M-phase of Meiosis I and M-phase II during which no replication of DNA occurs is called interkinesis.

Bivalent or tetrad formation takes place during the zygotene stage of prophase I, after synapsis has occurred and homologous chromosomes form pairs. However, the bivalent is distinct only in the next stage, pachytene.

Nucleolus is a dense, rounded, dark-staining, granular structure without a limiting membrane. It consists largely of RNAs and proteins. Nucleolus syntesizes and stores RNA. It also receives ribosomal proteins from the cytoplasm for storage. It forms ribosomal subunits by wrapping the RNAs with nitosomal proteins. The ribosomal subunits later have the nucleus through the nuclear pores.

In most fungi the structural polysaccharide of cell wall is chitin. In plant cells cell wall is made up of cellulose.

The correct matching of respiratory capacities with their respiratory volumes are:

Sickle-cell anaemia is caused by a point mutation in the hemoglobin gene, where the amino acid glutamic acid is replaced by valine at position 6 in the β-globin chain.

The primary goal of gene therapy is to introduce a normal gene into the patient's cells to compensate for the defective gene responsible for a hereditary disease. This can help correct or mitigate the effects of the disease. Gene therapy does not necessarily involve removing the defective gene, using stem cells to replace all defective cells, or creating antibodies to target defective genes

Required pair of letters are as follows:
(i) BA−  No letter between B and A

(ii) G(A)I− 1 letter between G and I

(iii) R(GAI)N - 3 letter between R and N

(iv) ED− No letter between E and D

Clearly, there are 4 such pairs.

Hence, D is the correct option. 

'Call a spade a spade' is an idiom that means to call something by its right name; to speak frankly about something, even if it is unpleasant.  
For example:
a) He failed the exam twice. If you were to call a spade a spade, then you would not push him to give it again.
b) Parents are often reluctant to see any faults in their children. However, it is always better to call a spade a spade. Hence, the correct option is "to speak plainly".

A long time ago, on a big tree in the lap of the mountain, lived a bird named Sindhuka. It was a rather special bird because its droppings turned into gold as soon as they hit the ground.
The following is possibly the most appropriate title for the story : 
The Bird with the Gold Dropping