SRMJEE Mock Test - 5 (Medical) - JEE MCQ

Equivalent circuit of the given circuit is

Between points C and D resistors 2Ω, 2Ω and 2Ω are in series, therefore their equivalent resistance,
R' = 2 + 2 + 2 = 6Ω
Resistors R` and 6Ω are In parallel, therefore their equivalent resistance is given by

R" = 3Ω
Now between points A and B, 1Ω, 3Ω and 1Ω are in series
Therefore, resultant resistance is
R = 1 + 3 + 1 = 5Ω

For the parallel plate capacitor, the capacitance is given by:

When the battery is disconnected, the charge remains constant. As the separation between the plates is increased, the capacitance decreases, and voltage across the capacitor will increase as we have:

Magnetic flux ^φ = BA ...(i)
and also F = ilB or B = F/il...(ii)
Now, from Eqs. (i) and (ii)
=
Dimensions of
=
= [ML² T^-2 I^-1]

A photocell employs photoelectric effect to convert change in the intensity of illumination into a change in photoelectric current.
When light of suitable frequency illuminates a metal surface, electrons are emitted from the metal surface. These photo(light)-generated electrons are called photoelectrons. The emission of electrons causes flow of electric current in the circuit.
In the photo-cell, the collector is maintained at a positive potential with respect to emitter, so that electrons ejected from it are attracted towards the collector. Keeping the frequency of the incident radiation and the potential fixed, the intensity of light is varied and the resulting photoelectric current is measured each time. It is found that the photocurrent increases linearly with intensity of incident light. The photocurrent is directly proportional to the number of photoelectrons emitted per second.

Let the temperature of common interface be T℃ Rate of heat flow

In steady state, the rate of heat flow should be same in whole system ie,

Hence, heat flow from composite slab is

[from Eq. (i)]

Accordingly, 

By comparing Eqs. (ii) and (iii), we get

⇒ f = 1/3

Let us consider the cross-sectional area of the cylinder as A and length of the cylinder as L.

If the piston moves by 5 cm5 cm, the length of one side of the cylinder will be,

(L/2 + 5) and of the other side, (L/2 − 5).

Pressure on each side of the piston will be increased and will be equal, i.e., P = constant, when the piston is stopped by moving 5 cm.

Now the piston remains in mechanical equilibrium. 

Here, 

P = Constant
and V ∝ T

On solving this equation,

Hence, the answer is L= 64.6 cm

For an LR circuit, we know:

tan ϕ = X_L / R

where:

• ϕ = Phase angle between current and emf
• X_L = Inductive reactance
• R = Resistance

According to the question:

ϕ = 45° ⇒ tan 45° = 1

We know that X_L = ωL, so:

X_L = R ⇒ ωL = R

Since ω = 2πf, we have:

R = 2πνL = 2 × π × 50 × 0.2 = 62.8 Ω

Initially, the force between the charges is given by,

After contact, the charges gets equally distributed between the two particles, such that, the charge on each is 

For a zero-order reaction, - (d[A]/dt) = k
Thus, [A]_t – [A]₀ = –kt

For a spontaneous process, ΔG₀ must be negative.
According to thermodynamics, ΔH° and ΔS° may be positive or negative, but ΔG° must be negative for a spontaneous reaction.

For a reduction process to be spontaneous, the Gibbs free energy change (ΔG^∘) must be negative.

The Reimer-Tiemann reaction is a reaction where phenol (C₆H₆OH) reacts with chloroform (CHCl₃) in the presence of a base (typically NaOH) to form salicylaldehyde (2-hydroxybenzaldehyde).

Intermediate Formed:
During the Reimer-Tiemann reaction, the key intermediate that forms is a carbene. Specifically, a dichlorocarbene (CCl₂) is generated when chloroform reacts with the base. This carbene reacts with the phenol to form the desired product, salicylaldehyde.
So, the intermediate formed in the Reimer-Tiemann reaction is a carbene.
Correct Answer: (C) Carbene.

Among the given reagents, only NaOH + Br₂ converts −CONH₂ group to −NH₂ group, thus it is used for converting acetamide to methyl amine. 

This reaction is called Hoffman bromide degradation reaction. Amine produced in this reaction has one carbon atom less than that in reactant amide.

1. Understanding Spermatogenesis:
- Spermatogenesis is the process of sperm formation that occurs in the male reproductive system, specifically in the seminiferous tubules of the testes.

2. Identifying Key Hormones:
- The process of spermatogenesis is regulated by several hormones. The main hormones involved are Follicle Stimulating Hormone (FSH), Luteinizing Hormone (LH), and testosterone.

3. Role of FSH:
- FSH is secreted by the anterior lobe of the pituitary gland. Its primary role in spermatogenesis is to stimulate the Sertoli cells in the testes, which support and nourish developing sperm cells.

4. Role of LH:
- LH, also secreted by the anterior pituitary gland, stimulates the Leydig cells in the testes to produce testosterone. This hormone is crucial for the overall process of spermatogenesis.

5. Role of Testosterone:
- Testosterone, produced by the Leydig cells, is essential for the development of male secondary sexual characteristics and also plays a significant role in the maturation of sperm.

6. Conclusion:
- The correct answer to the question is that spermatogenesis and sperm differentiation are under the control of both FSH and testosterone. Therefore, the correct option is "FSH and testosterone."

Final Answer: FSH and testosterone.

• GIFT (Gamete Intra-Fallopian Transfer) involves placing gametes (ova and sperm) directly into the fallopian tube, where natural fertilization can occur (Column II, 3).

• IVF (In Vitro Fertilization) involves fertilizing eggs in the lab and then transferring embryos with more than 8 blastomeres into the uterus (Column II, 1).

• ICSI (Intra-Cytoplasmic Sperm Injection) involves injecting sperm directly into an ovum (Column II, 2).

• IUI (Intra-Uterine Insemination) involves introducing sperm into the uterus or vagina (Column II, 4).

Thus, the correct matches are:
(a) - 3
(b) - 1
(c) - 2
(d) - 4

The structural gene (z) of the lac operon codes for β-galactosidase. It is responsible for the hydrolysis of polysaccharides. The ‘y’ genes code for permease. It increases the permeability of a cell to β-galactosidase. The ‘a’ genes code for transacetylase.

In the lac operon, gene y codes for permease, which increases cell permeability to β-galactosides. Gene z codes for β-galactosidase, and gene a for transacetylase.

• In human females, menstruation is repeated at an average interval of about 28/29 days, and the cycle of events starting from one menstruation till the next one is called the menstrual cycle.
• One ovum is released (ovulation) during the middle of each menstrual cycle.
• The cycle starts with the menstrual phase, when menstrual flow occurs and it lasts for 3-5 days. The menstrual phase is followed by the follicular phase.
• During this phase, the primary follicles in the ovary grow to become a fully mature Graafian follicle and simultaneously, the endometrium of uterus regenerates through proliferation.
• The growth of superficial and middle layer of endometrium occurs from the 5^th to 14^th day of the cycle under the influence of estrogen.

Centrosome is an organelle usually containing two cylindrical structures called centrioles. They are surrounded by amorphous pericentriolar materials. Both the centrioles in a centrosome lie perpendicular to each other in which each has an organisation like the cartwheel. They are made up of nine evenly spaced peripheral fibrils of tubulin protein. Each of the peripheral fibrils is a triplet. The adjacent triplets are also linked.

Enzyme may be broadly classified into two types depending on their chemical composition-simple enzymes and conjugated enzymes are wholly made up of proteins and any additional substance or group is absent, e.g., pepsin, trypsin, etc. Conjugated enzymes (or holoenzymes) are formed of two parts -a protein part called apoenzyme and a non-protein part named co-factor. The complete conjugated enzyme consisting of an apoenzyme and a co-factor is called holoenzyme. Holoenzyme is the functional unit of enzyme.

Co-factor may be inorgainc or roganic in nature. Catalytic activity is lost when co-factor is removed from the enzyme which indicates that it plays a crucial role in catalytic activity of enzymes.

Clarias gariepinus, the African catifish has been illegally introduced for aquaculture in India. It is threatening native catfishes of Indian rivers.

The primary purpose of a seed bank in conservation efforts is:

B: To store seeds of endangered plant species for long-term preservation.

Seed banks are used to conserve seeds from various plant species, especially those that are endangered, rare, or at risk of extinction, ensuring their long-term preservation for future restoration or replanting efforts.

The human heart completes one double circulation (pulmonary and systemic) per heartbeat. With an average heart rate of 72 beats per minute, the heart completes approximately 72 double circulations per minute.
Thus, the correct answer is seventy-two.

Reticulate venation is a characteristic of dicotyledonous leaves, where veins form a web-like network with a prominent midrib and interconnected smaller veins. Monocotyledonous leaves typically exhibit parallel venation, and isobilateral leaves (common in monocots) do not specifically characterize reticulate venation. Thus, the correct answer is A.

Systemic circulation involves the flow of oxygenated blood from the heart to the body’s tissues and the return of deoxygenated blood to the heart. In option D, blood flows from the left atrium to the left ventricle, through the aorta and arteries to the tissues, and returns via veins to the right atrium, accurately representing systemic circulation. Options A, B, and C include incorrect pathways involving the pulmonary artery or illogical heart chamber sequences.

• Imbricate aestivation is found in Cassia
• Valvate aestivation is found in Calotropis
• Vexillary aestivation is found in Bean
• Twisted aestivation is found in cotton

Calvin used the radioactive isotope of carbon (14C) of Chlorella. He observed that after second exposure of Chlorella in presence of 14 CO2, the radioactive isotope of carbon was found mainly in 3-phosphoglyceric acid (PGA). This clearly indicated that the three carbon compound 3- phosphoglyceric acid was the first stable product photosynthesis and the carbon from the CO2 is fixed in the preparation of the photosynthates.
Hence, the correct answer is 'PGA'.

Topic in NCERT: Photosynthesis in higher plants

Line in NCERT: "the first product identified was 3-phosphoglyceric acid or in short pga."

The phrase “more money chases fewer goods” means that when there is more money in the market and fewer goods available, the prices of goods increase due to higher demand. Option B captures this idea, as fewer goods require more money to compete for them, driving up prices.

The third cause of inflation (cartel restricting supply) is temporary because higher prices encourage competitors to enter the market, increasing supply and driving prices down, as per economic theory. Thus, option D is correct.