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Test: Heredity And Variation 8 - From Past 28 Years Questions


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25 Questions MCQ Test Biology 31 Years NEET Chapterwise Solved Papers | Test: Heredity And Variation 8 - From Past 28 Years Questions

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Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 1

What contribute to the success of Mendel ?

[1988]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 1

Consideration of one character with two contrasting conditions at one time contributed to Mendel's success in proposing the laws of inheritance of traits. His choice of experimental plant as pea and use of statistical methods also contributed to his success.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 2

Haploids are able to express both recessive and dominant alleles/mutations because there are

[1988]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 2

In haploid organisms every gene, irrespective of dominant or recessive and every mutation finds expression because there is only one allele for each gene in the haploid individual. Recessive allele is able to express as there is no alternative dominant allele for producing its masking effect on recessive allele.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 3

A mother in a family of five daughters is expecting her sixth baby.  The chance of its being a son is

[1988]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 3

Humans have 22 pairs of autosomes and 1 pair of sex chromosomes which are XX in females and XY in males. So, everytime the chances of son or daughter is 50-50% depending upon which sex chromosome is contributed by father in sperm.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 4

Mutations used in agriculture are commonly

[1988]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 4

Induced mutations are produced in response to external factors of chemicals called mutagens. In agriculture mutagens are used to induce desired mutations in crop plants.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 5

Diploid chromosome number in humans is

[1989]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 5

Chromosomes occur in homologous pairs. Somatic cells have diploid number of chromosomes. Humans have 23 pairs i.e. 46 chromosomes. 22 pairs of autosomes and 1 pair of sex chromosomes ie. XX in females and XY in males.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 6

Two linked genes a and b show 20 % recombination. The individuals of a dihybrid cross between + +/ + + × ab/ab shall show gametes

[1989]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 6

Two linked genes a and b show 20% recombination. The individuals of a dihybrid cross between + + / + + × ab/ ab shall show gametes + + 40 : ab40: + a 10 : +b : 10.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 7

Triticale has been evolved by intergeneric hybridization between

[1989, 2001]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 7

Triticale is a man made cereale produced by crossing two generate wheat (Triticum) and rye (Secale). Hexaploid Triticale was obtained by crossing Triticum durum and Secale cereale.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 8

A normal green male maize is crossed with albino female. The progeny is albino because

[1989]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 8

Besides nucleus some genes are also present in the cytoplasm of the female parent, these genes are called plasmogenes. In the given example the progeny is albino because of inheritance of plastids from female parent.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 9

tt mates with Tt. What will be characteristic of offspring ?

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 9

On mating tt with Tt, 50% individual offsprings are recessive and 50% are heterozygous dominant.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 10

ABO blood group system is due to

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 10

A gene may have more than two alternative forms occupying the same locus on a chromosome such alleles are known as multiple alleles and the phenomenon is turned as multiple allelism. ABO blood group has 3 alleles. IO, IA or A, IB or B.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 11

In a genetic cross having recessive epistasis, F2 phenotypic ratio would be

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 11

In recessive epistasis, the recessive alleles suppress the expression of a trait. Recessive epistasis is a type of intergenic interaction in which one non allelic gene can produce its effect independently in the dominant state but second gene can produce its effect when they are present together. Here homozygous recessive allele for a gene mask the expression of dominant allele of another gene.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 12

Cross between AaBB and aaBB will form

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 12

AaBB × aaBB on crossing gives 50% individuals having genotype AaBB and 50% individuals having genotype aaBB.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 13

An octamer of 4 histones complexed with DNA forms

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 13

Nucleosomes are oblate spherical structure having an octamer of four histone proteins (constituting 2 molecules of each type).

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 14

Both husband and wife have normal vision though their fathers were colour blind. The probability of their daughter becoming colour blind is

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 14

The probability of the daughter becoming colour blind arises only when the father is also colour blind.
Husband – XY Wife – XXC (wife is carrier because her father is colour blind)

So, probability of their daughter becoming colour blind is 0%.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 15

Which one is a hereditary disease ?

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 15

Phenylketonuria is a human genetic disorder in which the body does not contain the enzyme phenylalanine hydroxylase, necessary to metabolize phenylalanine to tyrosine, and converts phenylalanine instead to phenylpyruvic acid. As PKU is an autosomal recessive genetic disorder each parent must have at least one defective allele of the gene for PAH, and the child must inherit a defective allele from each parent. As such, it is possible for a parent with a PKU phenotype to have a child without PKU if the other parent possesses at least one functional allele of the gene for PAH. A child of two parents with the PKU phenotype will always receive two defective alleles so will always have PKU. The gene for PAH is located on chromosome 12, at location  12q22-q24.2.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 16

Haemophilia is more common in males because it is a

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 16

Haemophilia is a sex linked recessive trait  carried by X chromosome (also known as bleeder’s disease).

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 17

Bateson used the terms coupling and repulsion for linkage and crossing over. Name the correct parent of coupling type alongwith its cross repulsion

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 17

Bateson and Punnett (1906) discovered coupling and repulsion in sweet pea (Lathyrus odoratus).

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 18

In Down’s syndrome of a male child, the sex complement is

[1990]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 18

Down’s syndrome is due to trisomy of 21st chromosome and is an autosomal abnormality.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 19

Red (RR) Antirrhinum is crossed with white (WW) one. Offspring RW are pink. This is an example of

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 19

Incomplete dominance is the phenomenon of none of the alleles being dominant, with the effect that the hybrid produced by crossing two pure individuals is a mixture between the parents.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 20

The allele which is unable to express its effect in the presence of another is called

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 20

The allele which can not impressits effect in the hybrid or in the presence of dominant allele is termed as recessive. It is denoted by small letter.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 21

Blue eye colour is recessive to brown eye colour. A brown eyed man whose mother was blue eyed marries a blue-eyed women. The children shall be

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 21

The brown eyed man will have the genotype Bb and his wife bb. Hence Bb × bb = Bb : bb. Hence ratio is 1 : 1.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 22

A dihybrid condition is

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 22

Dihybrid condition involves simultaneous inheritance of two pairs of mendelian factors or genes.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 23

Mendel’s last law is

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 23

According to the law of Independent Assortment, alleles of different characters located in different pairs of homologous chromosomes are independent of one another in their separation or segregation during gamete formation.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 24

First geneticist/ father of genetics was

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 24

Gregor Johann Mendel formulated the laws of heredity and is regarded as the father of genetics.

Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 25

The contrasting pairs of factors in Mendelian crosses are called

[1991]

Detailed Solution for Test: Heredity And Variation 8 - From Past 28 Years Questions - Question 25

Two allelomorphs are the different forms of a gene which are responsible for different expression of same characters, e.g. for colour of flower is R and r.

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