The products of reaction of alcoholic silver nitrite with ethyl bromide are
TIPS/Formulae : Silver nitrite, being a salt of nitrous acid, occurs in two tautomeric forms.
ion from AgNO2 may exist in two tautomeric forms, –O – N = O (nitrite ion) forming alkyl nitrites, and (nitro group) forming nitroalkanes.
2 C2H5Br + 2AgNO2 → C2H5NO2 + C2H5ONO + 2 AgBr
Reaction of with a mixture of Br2 and KOH gives R-NH2 as the main product. The intermediates involved in this reaction are :
This is an example of Hoffmann degradation of amides.
When nitrobenzene is treated with Br2 in presence of FeBr 3, the major product formed is m-bromonitrobenzene.
Statements which are related to obtain the m-isomer are
TIPS/Formulae : Nitro group decreases the electron density at the meta-position in comparison to ortho and para position due to –I and –M effects.
The above intermediate is a resonance hybrid of three structures, hence is more stable than the corresponding intermediate from ortho and paraattack
Examine the following two structures for the anilinium ion and choose the correct statement from the ones given below:
In Ist structure N has complete octet , whereas in IInd structure N has 10e in its valence shell.
Because of 1 double and 3 single bonds of N.
p-Chloroaniline and anilinium hydrochloride can be distinguished by
TIPS/Formulae : Anilinium hydrochloride has ionisable chlorine whereas chlorobenze has non ionizable chlorine. Thus anilium hydrochloride gives white precipitate of AgCl with AgNO3.
In chloroaniline, –Cl is directly attached to benzene ring, hence it is non-reactive.
Among the following compounds, which will react with acetone to give a product containing > C = N–bond ?
Benzenediazonium chloride on reaction with phenol in weakly basic medium gives
A positive carbylamine test is given by
NOTE : Only primary amines give carbylamine test.
Hence 2,4-dimethylanilinc and p-methyl–benzylamine both give this test.
In the reaction 2X + B2H6 → [BH2(X)2]+ [BH4]– the amine(s) X is (are)
Lower amines like NH3, CH3NH2 and (CH3)2NH break diborane molecule unsymmetrically, while larger amines like (CH3)3N, C5H5N break diborane in symmetrical manner.
Hydrogen bonding plays a central role in the following phenomena
In ice, water molecules are excessively H-bonded giving a cage-like structure which is lighter than water.
Primary amines are more basic than tertiary amine, because the protonated 1° amines are extensively H-bonded and hence more stable than the corresponding protonated 3° amines.
Acetic acid undergoes dimerisation in benzene.
In the reaction shown below, the major product(s) formed is/ are
group is acetylated by acetic anhydride in methylene chloride (solvent). Note that —CONH2 group does not undergo acetylation because here lone pair of electrons is delocalised.
The major product of the reaction is
In the following reactions, the major product W is
In the following reactions, the product S is
The product(s) of the following reaction sequence is(are)