JEE  >  Chemistry for JEE  >  Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced Download as PDF

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced


Test Description

37 Questions MCQ Test Chemistry for JEE | Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced for JEE 2023 is part of Chemistry for JEE preparation. The Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced questions and answers have been prepared according to the JEE exam syllabus.The Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced MCQs are made for JEE 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced below.
Solutions of Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced questions in English are available as part of our Chemistry for JEE for JEE & Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced solutions in Hindi for Chemistry for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced | 37 questions in 80 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE for JEE Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you?
Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 1

The reagent with which both acetaldehyde and acetone react easily is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 1

Fehling solution, Schiff’s reagent & Tollen’s reagent react only with aldehydes but Grignard reagents react both with aldehydes and ketones.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 2

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 2

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 3

The Cannizzaro reaction is not given by

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 3

TIPS/Formulae : The compound containing α-H atom does not undergo Cannizzaro's reaction.
Acetaldehyde does not undergo Cannizzaro reaction since it has a-H atoms while formaldehyde, trimethylacetaldehyde and benzaldehyde undergo Cannizzaro reaction since they do not contain α-hydrogen atoms.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 4

The compound that will not give iodoform on treatment with alkali and iodine is :

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 4

TIPS/Formulae :

Iodoform test is given by compounds having –COCH3 group.
In acetone –COCH3 group is present. Further ethanol and isopropyl alcohol get oxidised to acetaldehyde and acetone respectively (both having –COCH3 group) in presence of I2 and they in turn give the test. Thus only diethyl ketone does not give this test.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 5

Polarisation of electrons in acrolein may be written as

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 5

NOTE : –CHO produces –R effect i.e. it withdraws electrons from the double bond or from a conjugated system towards itself.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 6

The enolic form of acetone contains

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 6

No. of σ bonds in enolic form : 3 + 1 + 1 + 1 + 1 + 2 = 9
No. of π bonds in enolic form : 1
No. of lone pairs of electrons in enolic form = 2

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 7

m-Chlorobenzaldehyde on reaction with conc. KOH at room temperature gives

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 7

NOTE : m-Chlobenzaldehyde does not contains α-H atom. It is an example of Cannizzaro reaction

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 8

Hydrogenation of benzoyl chloride in the presence of Pd on BaSO4 gives

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 8

NOTE : This reaction is kn own as Rosen mun d's reaction.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 9

The organic product formed in the reaction

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 9

TIPS/FORMULAE :

LiAlH4 is a reducing agent, it reduces –COOH group to –CH2OH group.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 10

The reaction products of 

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 10

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 11

In the Cannizzaro reaction given below,

the slowest step is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 11

The possible mechanism is



NOTE : The slowest step is the transfer of hydride to the carbonyl group as shown in step (ii).

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 12

When propionic acid is treated with aqueous sodium bicarbonate, CO2 is liberated. The ‘C’ of CO2 comes from

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 12

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 13

The enol form of acetone, after treatment with D2O, gives.

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 13

Remember that α - H's of carbonyl group are easily replaced by D of D2O

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 14

Which one of the following will most readily be dehydrated in acidic condition ?

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 14

Compound (a) undergoes dehydration easily as the product obtained is conjugated and thus more stable.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 15

Benzoyl chloride is prepared from benzoic acid by

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 15

Benzoyl chloride is prepared from benzoic acid be SOCl2.
|C6H5 COOH + SOCl2 → C6H5COCl + SO2 + HCl

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 16

The appropriate reagent for the following transformation is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 16

Zn(Hg), HCl cannot be used when acid sensitive group like –OH is present, but NH2NH2, OH can be used.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 17

A mixture of benzaldehyde and formaldehyde on heating with aqueous NaOH solution gives

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 17

TIPS/Formulae : Both compounds do not contain a-hydrogen hence undergo Crossed Cannizzaro reaction.
Initially OH- attacks at the carbonyl carbon of HCHO than that of PhCHO because carbonyl carbon of HCHO is
(i) more el ectrophilic
(ii) less sterically hindered to give hydroxyalkoxide which acts as hydride donor in next step to give sodium formate.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 18

The product of acid hydrolysis of P and Q can be distinguished by

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 18

TIPS/Formulae : Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.


Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 19

Major product is :

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 19


               

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 20

Ethyl ester  The product P will be

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 20

Recall that, esters react with excess of Grignard reagents to form 3º alcohols having at least two identical alkyl groups corresponding to Grignard reagent.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 21

An enantiomerically pure acid is treated with a racemic mixture of an alcohol having one chiral carbon. The ester formed will be

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 21

The optically active acid will react with d and l forms of alcohol present in the racemic mixture at different rates to form two diastereomers in unequal amounts leading to optical activity of the product.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 22

The correct order of reactivity of PhMgBr with

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 22

TIPS/Formulae :
Reaction  of PhMgBr with carbonyl compounds is an example of nucleophilic addition on carbonyl group which increases with the increase in electron-deficiency of carbonyl carbon.

Thus acetaldehyde is most reactive while C6H5COC6H5 least

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 23

How will you convert butan-2-one to propanoic acid?

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 23

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 24

The compound (X) is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 24

TIPS/Formulae : This reaction is an example of “Perkin reaction”.
The compound X should be (CH3CO)2O.
In this step the carbanion is obtained by removal of an α–H atom from a molecule of an acid anhydride, the anion of the corresponding acid acting as a necessary base.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 25

4-Methylbenzenesulphonic acid reacts with sodium acetate to give

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 25

This is simply an acid-base reaction.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 26

In the following reaction sequence, the correct structures of E, F and G are

 [* implies 13C labelled carbon)

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 26


Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 27

The correct acidity order of the following is    

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 27

Car boxylic acid is stronger acid th an phenol. The presence of electron withdrawing group (e.g. Cl) increases acidic strength, while presence of electron donating group (e.g. CH3) decreases acidic strength.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 28

In the reaction

the structure of the product T is :

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 28


Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 29

The compounds P, Q and S

were separately subjected to nitration using HNO3/H2SO4 mixture. The major product formed in each case respectively, is :

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 29




(Benzene ring having –O– is activated)

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 30

The major product of the following reaction is    

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 30


Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 31

The carboxyl functional group (– COOH) is present in

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 31


Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 32

The major product H of the given reaction sequence is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 32



                     

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 33

The compound that undergoes decarboxylation most readily under mild condition is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 33

β-Ketoacids undergo decarboxylation easily.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 34

The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 34

Carbolic acid (Phenol) is weaker acid than carbonic acid and hence does not liberate CO2 on treatment with aq. NaHCO3 solution.

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 35

The major product in the following reaction is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 35

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 36

The correct order of acidity for the following compounds is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 36




∴ acidity order is I > II > III > IV

Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 37

The major product of the following reaction sequence is

Detailed Solution for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced - Question 37



322 videos|586 docs|368 tests
Use Code STAYHOME200 and get INR 200 additional OFF
Use Coupon Code
Information about Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced Page
In this test you can find the Exam questions for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Single Correct MCQs: Aldehydes, Ketones & Carboxylic Acids | JEE Advanced, EduRev gives you an ample number of Online tests for practice