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Test: Single Correct MCQs: The p-Block Elements | JEE Advanced


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62 Questions MCQ Test Chemistry for JEE | Test: Single Correct MCQs: The p-Block Elements | JEE Advanced

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Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 1

The reddish brown coloured gas formed when nitric oxide is oxidised by air is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 1

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 2

The temporary hardness of water due to calcium carbonate can be removed by adding –

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 2

Temporary hardness of water is due to presence of bicarbonates of Ca and Mg and it is removed by adding Ca(OH)2 to hard water and precipitating these soluble bicarbonates in the form of insoluble salts.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 3

Which of the following is most stable to heat

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 3

Due to highest bond dissociation energy.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 4

White P reacts with caustic soda. The products are PH3 and NaH2PO2. This reaction is an example of

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 4

It is redox reaction. (i) Oxidation n umber in cr eases dur in g oxidation reaction and decreases during reduction reaction.
(ii) In a neutralisation reaction acids and bases  reacts together to form salt and water.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 5

A solution of KBr is treated with each of the following.

Which one would liberate bromine

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 5

∵ Cl2 is more reactive than bromine.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 6

Which of the following is coloured

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 6

All are colourless gases.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 7

Lead pencil contains

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 8

Ammonia can be dried by

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 8

None; it reacts with all given compounds. It forms addition compounds with them.
It can be dried over any metal oxide.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 9

HBr and HI reduce sulphuric acid, HCl can reduce KMnO4 and HF can reduce

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 9

HI and HBr (in that order) are the strongest reducing hydracids and hence they reduce H2SO4. HCl is quite stable and hence is oxidised by strong oxidising agent like KMnO4. HF is not a reducing agent. In the smallest F– ion, the electron which is to be removed during oxidation is closest to the nucleus and therefore most difficult to be removed. Therefore, HF is a poor reducing agent.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 10

Which of the following statements about anhydrous aluminium chloride is correct?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 10

AlCl3 exists as a dimer (Al2Cl6). It is a strong Lewis acid as it has an incomplete octet and has a tendency to gain electrons. AlCl3 undergoes hydrolysis easily and forms an acidic solution.
AlCl3 + 3H2O → Al(OH)3 + 3HCl

Option (c) is true that AlCl3 sublimes at 100ºC under vacuum.
AlCl3 is a Lewis acid.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 11

Moderate electrical conductivity is shown by

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 11

Graphite shows moderate electrical conductivity due to the presence of unpaired or free fourth valence electron on each carbon atom.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 12

Chlorine acts as a bleaching agent only in presence of

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 12

Bleaching action of chlorine is only in presence of moisture where nascent oxygen is displaced from H2O.
Cl2 + H2O → HCl + HClO (unstable) HClO → HCl + | O |

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 13

Nitrogen dioxide cannot be obtained by heating :

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 13

Only nitrates of heavy metals and lithium decompose on heating to produce NO2.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 14

A gas that cannot be collected over water is :

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 14

SO2 is highly soluble in water and therefore cannot be collected over water.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 15

The compound which gives off oxygen on moderate heating is :

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 15

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 16

The bonds present in N2O5 are :

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 16

The structure clearly shows the presence of covalent and co-ordinate bonds.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 17

Which of the following oxides of nitrogen is a coloured gas?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 17

NO2 is reddish brown coloured gas. Rest of the oxides are colourless.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 18

Amongst the trihalides of nitrogen which one is least basic?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 18

Least basic trihalogen of nitrogen is NF3 because of the highest electronegativity of fluorine.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 19

Bromine can be liberated from potassium bromide solution by the action of

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 19

Chlorine is stronger oxidising agent than bromine therefore, chlorine water will liberate bromine from KBr solution.

2 KBr + Cl2 → 2 KCl + Br2

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 20

There is no S–S bond in :

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 20

In  there is an S–O–S bond unlike in other.
So S–S bond is absent as can be seen from the structure drawn.


Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 21

In P4O10 each P atom is linked with .......... O atoms

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 21

In P4O10, each P atom is linked to 4 oxygen atoms as can be confirmed by its structure. It is linked to three oxygen atoms by single bond and with one oxygen atom by double bond. [For structure refer to Q.11 of Section A]

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 22

H2SO, cannot be used to prepare HBr from NaBr as it 

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 22

HBr is not prepared by heating NaBr with conc. H2SO4 because HBr is a strong reducing agent and reduce H2SO4 to SO2 and is itself oxidised to bromine.
NaBr + H2SO4 —→ NaHSO4 + HBr H2SO4 + 2HBr —→ SO2 + Br2 + 2H2O

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 23

Hydrolysis of one mole of peroxodisulphuric acid produces

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 23


Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 24

Which of the following statements is correct for CsBr3?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 24

CsBr3 may be represented as Cs+Br3

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 25

KF combines with HF to form KHF2. The compound contains the species.

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 25

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 26

Sodium thiosulphate is prepared by

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 26

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 27

Which of the following halides is least stable and has doubtful existence?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 27

Due to inert pair effect.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 28

Which one of the following oxides is neutral?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 28

CO is an example of neutral oxide.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 29

Which one of the following species is not a pseudohalide?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 29

The species called as pseudohalide ions are these are monovalent and made by electronegative atoms. They possess properties similar to halide ion. The corresponding dimers of these pseudohalide ions are called pseudohalogens. RCOO is not is pseudohalide.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 30

One mole of calcium phosphide on reaction with excess water gives

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 30

Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3 ; i.e 2 moles of phosphine are produced.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 31

On heating ammonium dichromate, the gas evolved is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 31

(NH4)2Cr2O7 → N2 + Cr2O3 + 4H2O

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 32

In the commercial electrochemical process for aluminium extraction the electrolyte used is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 32

Al2O3 is electrolyte, while  Na3AlF6 is used to decrease the melting point of Al2O3 and to increase the conductivity.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 33

In compounds of type ECl3, where E = B, P, As or Bi, the angles Cl – E– Cl for different E are in the order

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 33

In BCl3, H = 1/2 (3 + 3 + 0 - 0) = 3 ; sp2 hybridization (bond angle = 120°) similarly PCl3 AsCl3 and BiCl3 are found to have sp3 hybridized central atom with one lone pair of electrons on the central atom. The bond angle < 109°28', since the central atoms belong to the same group, the bond angle of the chlorides decreases as we go down the group. Thus the order of bond angle is,  BCl3 > PCl3 > AsCl3 > BiCl3.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 34

Electrolytic reduction of alumina to aluminium by HallHeroult process is carried out

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 34

Cryolite reduces the melting temperature.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 35

The number of P – O – P bonds in cyclic metaphosphoric acid is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 35

In cyclic metaphosporic acid number of P–O–P bonds is three.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 36

Ammonia can be dried by

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 36

NH3 does not react with CaO while other reacts with NH3

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 37

The number of S - S bonds in sulphur trioxide trimer (S3O9) is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 37

In sulphur trioxide trimer S3O9 (also called g-sulphur trioxide) two sulphur atoms are linked to each other via O atoms, hence there is no S –S bond.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 38

Polyphosphates are used as water softening agents because they

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 38

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 39

For H3PO3 and H3PO4 the correct choice is:

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 39

The structure of H3PO3 is as follows: There are only two –OH groups and hence dibasic. The oxidation number of P in this acid is +3. Whereas P can have +5 oxidation state also. Therefore, H3PO3 can be oxidised which means H3PO3 is a reducing agent.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 40

H3BO3 is:

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 40

The central boron atom in boric acid, H3BO3 is electrondeficient.
NOTE : Boric acid is a Lewis acid with one p–orbital vacant. There is no d-orbital of suitable energy in boron atom. So, it can accommodate only one additional electron pair in its outermost shell.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 41

(Me)2SiCl2 on hydrolysis will produce

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 41

TIPS/FORMULAE :
It appears at the first sight that Me2SiCl2 on hydrolysis will produce Me2Si(OH)2 which ultimately upon loss of water, will form Me2Si = O.
But silicon atom, because of its very large size in comparison to oxygen, is unable to form π-bond. Thus, the product of hydrolysis is polymeric in nature.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 42

Total number of lone pair of electrons in XeOF4 is 

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 42

In XeOF4, Xenon is sp3d2 hybridised and has one lone pair.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 43

The acid having O – O bond is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 43

Among oxyacids of sulphur, only Caro’s acid (H2SO5) and Marshall’s acid (H2S2O8) have the O – O linkage.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 44

Pb and Sn are extracted from their chief ores by 

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 44

Tin can be extracted only by carbon reduction method, while lead can be extracted by self as well as carbon reduction method.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 45

Name of the structure of silicates in which three oxygen atoms of [SiO4]4– are shared.

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 45

Two dimensional sheet structures are formed when three oxygen atoms of each [SiO4]4– tetrahedral are shared.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 46

Which is the most thermodynamically stable allotropic form of phosphorus?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 46

The ignition temperature of black phosphorus is highest among all its allotropes, hence is most stable.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 47

Which of the following is not oxidized by O, ?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 47

In KMnO4 manganese is already present in its highest possible oxidation state i.e. +7.So no further oxidation is possible.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 48

Blue liquid which is obtained on reacting equimolar amounts of two gases at -30°C is?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 48

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 49

When PbO2 reacts with conc. HNO3 the gas evolved is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 49

PbO2 is a powerful oxidizing agent and liberate O2 when treated with acids.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 50

How can the following reaction be made to proceed in forward direction?

B(OH)3 + NaOH  NaBO2 + Na[B(OH)4] + H2O

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 50

cis-1,2-diol for ms ch elated complex ion with th e product, [B(OH)4] causing the reaction to proceed in forward direction.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 51

The percentage of p-character in the orbitals forming P – P bonds in P4 is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 51

In P4, the P–P linkage is formed by sp3–sp3 hybridised orbital overlapping. So the percentage of p-character will be 75%.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 52

Aqueous solution of Na2S2O3 on reaction with Cl2 gives –

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 52

The following reaction occurs

Na2S2O3 + 4Cl2 + 5H2O → 2 NaHSO4 + 8HCl.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 53

The reaction of P4 with X leads selectively to P4O6. The X is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 53

 

Here N2 acts as a diluent and thus retards further oxidation. Reaction of P4 under other three conditions.

(c) In moist air, P4O6 is hydrolysed to form H3PO3

(d) In presence of NaOH,

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 54

Extra pure N2 can be obtained by heating

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 54

Ba (N3)2 → Ba+ 3N2

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 55

Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen?

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 55

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 56

The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are respectively

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 56

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 57

The shape of XeO2F2 molecule is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 57

XeO2F2 has tr igonal bipyramidal geometry, due to presence of lone pair of electrons on equitorial position, its shape is see-saw.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 58

Concentrated nitric acid, upon long standing, turns yellow brown due to the formation of

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 58

The slow decomposition of HNO3 is represented by the eqn.

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 59

The product formed in the reaction of SOCl2 with white phosphorous is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 59

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 60

Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme shown below is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 60

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 61

The increasing order of atomic radii of the following Group 13 elements is

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 61

Atomic r adii increases on moving down a gr oup.
However due to poor shielding effect of d orbit, atomic radius of Ga is smaller than Al (anomaly). Thus the correct order is  Ga < Al < In < Tl

Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 62

In the following reaction sequence in aqueous solution, the species X, Y and Z, r espectively, are

Detailed Solution for Test: Single Correct MCQs: The p-Block Elements | JEE Advanced - Question 62

So, X, Y and Z are [Ag (S2O3)2]3–, Ag2S2O3 and Ag2S respectively.

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