NEET  >  31 Year NEET Previous Year Questions: Motion in a Straight Line - 1

# 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1

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## 16 Questions MCQ Test Physics Class 11 | 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 for NEET 2023 is part of Physics Class 11 preparation. The 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 MCQs are made for NEET 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 below.
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31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 1

### A particle moving along x-axis has acceleration f, at time t, given by , where f0 and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle’s velocity (vx) is [2007]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 1

Here,

where C is the constant of integration.
At t = 0, v = 0.

If f = 0, then

Hence, particle's velocity in the time interval t = 0 and t = T is given by

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 2

### The distance travelled by a particle starting from rest and moving with an acceleration 4/3ms-2 , in the third second is:

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 2

Distance travelled in the nth second is given by

put u = 0,

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 3

### A particle shows distance - time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point:                              [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 3

The slope of the graph   is maximum at C and hence the instantaneous velocity is maximum at C.

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 4

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms–1 to 20 ms–1 while passing through a distance 135 m in t second. The value of t is: [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 4

Initial velocity, u = 10 ms–1
Final velocity, v = 20 ms–1
Distance, s = 135 m
Let, acceleration = a
Using the formula, v2 = u2 + 2as

Now, using the relation, v = u + at

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 5

A bus is moving with a speed of 10 ms–1 on a straight road. A scooterist wishes to overtake the bus in 100 s. If the bus is at a distance of 1 km from the scooterist, with what speed should the scooterist ch ase the bus? [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 5

Let v be the relative velocity of scooter w.r.t bus as v = vS– vB

=   10 + 10 = 20 ms–1

∴ velocity of scooter = 20 ms–1

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 6

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 6

u = 0, t1=10s, t2 = 20s

Using the relation,

Acceleration being the same in two cases,

S2 = 4S1

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 7

A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 7

Clearly distance moved by 1st bal l in 18s = distance moved by 2nd ball in 12s.
Now, distance moved in 18 s by 1st

= 90 x 18 = 1620 m

Distance moved in 12s by 2nd ball

∴ 1620 = 12 v + 5 x 144

⇒    v = 135 – 60 = 75 ms –1

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 8

A particle h as in itial velocity and has acceleration . It's speed after 10 s is:

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 8

⇒ ux = 3 units, uy = 4 units

ax = 0.4 units, ay = 0.3 units

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 9

A particle moves a distance x in time t according to equation x = (t + 5)-1. The acceleration of particle is proportional to [2010]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 9

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 10

A man of 50 kg mass is standing in a gravity free space at a height of 10 m  above the floor. He throws a stone of 0.5 kg  mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be:

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 10

No external force is acting, there fore, momentum is conserved.
By momentum conservation, 50u + 0.5 × 2 = 0 where u is the velocity of man.

Negative sign of u shows that man moves upward.
Time taken by the stone to reach the ground

∴ when the stone reaches the floor, the distance of the man above floor = 10.1 m

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 11

A boy standing at the top of a tower of 20m height drops a stone. Assuming g = 10 ms–2, the velocity with which it hits the ground is [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 11

Here, u = 0

We have, v2 = u2 + 2gh

= 20 m/s

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 12

A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 12

Average acceleration

< a > = 5 m/sec2

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 13

A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 13

Let the total distance covered by the particle be 2s. Then

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 14

The motion of a particle along a straight line is described by equation : [2012] x = 8 + 12t – t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 14

x = 8 + 12t – t3
The final velocity of the particle will be zero, because it retarded.
V = 0 + 12 – 3t2 = 0
3t2 = 12
t = 2 sec
Now the retardation

a [t = 2] = – 12 m/s2 retardation = 12 m/s2

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 15

A stone falls freely  under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is [NEET 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 15

⇒  h2 = 375

31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 16

The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = . The displacement of the particle when its velocity is zero, will be [NEET Kar. 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Motion in a Straight Line - 1 - Question 16

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## Physics Class 11

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