NEET Exam  >  NEET Tests  >  Chemistry Class 12  >  31 Year NEET Previous Year Questions: Electrochemistry - 1 - NEET MCQ

31 Year NEET Previous Year Questions: Electrochemistry - 1 - NEET MCQ


Test Description

23 Questions MCQ Test Chemistry Class 12 - 31 Year NEET Previous Year Questions: Electrochemistry - 1

31 Year NEET Previous Year Questions: Electrochemistry - 1 for NEET 2024 is part of Chemistry Class 12 preparation. The 31 Year NEET Previous Year Questions: Electrochemistry - 1 questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Electrochemistry - 1 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Electrochemistry - 1 below.
Solutions of 31 Year NEET Previous Year Questions: Electrochemistry - 1 questions in English are available as part of our Chemistry Class 12 for NEET & 31 Year NEET Previous Year Questions: Electrochemistry - 1 solutions in Hindi for Chemistry Class 12 course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt 31 Year NEET Previous Year Questions: Electrochemistry - 1 | 23 questions in 45 minutes | Mock test for NEET preparation | Free important questions MCQ to study Chemistry Class 12 for NEET Exam | Download free PDF with solutions
31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 1

The equilibrium constant of the reaction:

E° = 0.46 V at 298 K is [2007]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 1

or  Kc = Antilog 15.57 = 3.7 × 1015 ≈ 4 × 1015

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 2

On the basis of the following E° values, the strongest oxidizing agent is : [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 2

For the strongest oxidizing agent, the oxidizing potential should be least. Here, the oxidizing potential of Fe+2 is less than that of [Fe(CN)6​]4−. Therefore, Fe+2 is stronger oxidizing agent than [Fe(CN)6​]4−. Also, the stronger oxidizing agent should easily reduce itself. Here, Fe+3 is easily reduced than Fe+2. Therefore, among all the four, Fe+3 is the stronger oxidizing agent.

1 Crore+ students have signed up on EduRev. Have you? Download the App
31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 3

Kohlrausch’s law states that at : [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 3

Kohlrausch ’s Law states that at infinite dilution, each ion migrates independently of its co-ion and contributes to the total equivalent conductance of an eletrolyte a definite share which depends only on its own nature.
From this definition we can see that option (d) is the correct answer.

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 4

Standard free energies of formation (in kJ/mol) at 298 K are – 237.2, – 394.4 and – 8.2 for H2O(l), CO2(g) and pentane (g), respectively. The value E°cell for the pentane-oxygen fuel cell is :  [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 4

Writing the equation for pentane-oxygen fuel cell at respective electrodes and over all reaction, we get At Anode:

At Cathode:

Calculation of ΔG° for the above reaction

ΔG° = [5×(–394.4) + 6× (–237.2)]
– [–8.2]
= – 1972.0 – 1423.2 + 8.2 = – 3387.0 kJ
= – 3387000 Joules.
From the equation we find n = 32

Using the relation,

and substituting various values, we get

Thus option (c) is correct answer.

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 5

Given: [2009]

Electrode potential, Eo for the reaction,  will be :

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 5

   = – 2 × F × 0.337
 = – 0.674 F        ....(i)

  = – 1 × F × – 0.153
  =  0.153 F     ....(ii)

On adding eqn (i) & (ii)

Here n = 1       Δ Eo = + 0.52 V

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 6

Al 2O3 is reduced by electrolysisat low potentials and high currents. If  4.0 × 104 amperes of current is passed through molten Al2O3 for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency. At. mass of Al = 27 g mol–1) [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 6

Now since 96500 C liberates 9 g of Al

8.64 × 108  C liberates 

   = 8.1 × 104 g of Al

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 7

The equivalent conductance of  solution ofa weak monobasic acid is 8.0 mhos cm2 and at infinite dilution is 400 mhos cm2. The dissociation constant of this acid is: [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 7

Degree of dissociation

= 1.25 x 10-5

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 8

For the reduction of silver ions with copper metal, the standard cell potential was found to be + 0.46 V at 25°C. The value of standard Gibbs energy, ΔG0 will be (F = 96500 C mol –1)

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 8

Here, n = 2 ,  

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 9

An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to: [2010]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 9

Dilution of strong electrolytes increases ionisation, hence ionic mobility of ions which in turn increases equivalent conductance of the solution.

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 10

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2 (SO4)3, Given that and are the equivalent conductances at infinite dilution of the respective ions? [2010]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 10

Equivalent conductance of an electrolyte at infinite dilution is given by the sum of equivalent conductances of the respective ions at infinite dilution.
∴ Correct choice : (c)

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 11

Consider the following relations for emf of a electrochemical cell:                           [2010]
(i) emf of cell = (Oxidation potential of anode) – (Reduction potential of cathode)
(ii) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(iii) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(iv) emf of cell = (Oxidation potential of anode) – (Oxidation potential of cathode)
Which of the above relations are correct?

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 11

Option (b) and (d) are correct
∴ Correct choice : (a)

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 12

Standard electrode potential of three metals X, Y and Z are – 1.2 V, + 0.5 V and – 3.0 V, respectively. The reducing power of these metals will be : [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 12

As the value of standard reduction potential decreases the reducing power increases i.e.,

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 13

The electrode potentials for [2011]

are + 0.15 V and + 0.50, respectively. The value of E° Cu 2+ / Cu will be :

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 13

⇒ 0.325

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 14

Standard electrode potential for Sn4+ / Sn2+ couple is + 0.15 V and that for the Cr3+ / Cr couple is – 0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be : [2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 14

= 0.15 – (– 0.74)
= + 0.89 V

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 15

If the E°cell for a given reaction has a negative value, then which of the following gives the correct relationships for the values of ΔG° and Keq ?[2011]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 15

Standard Gibbs free energy is given as ΔG°

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 16

A solution contains Fe2+, Fe3+ and Iions. This solution was treated with iodine at 35°C. E° for Fe3+ / Fe2+ is + 0.77 V and E° for I2/2I = 0.536 V.The favourable redox reaction is : [2011 M]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 16

= 0.77 – 0.536
= 0.164 V
So, reaction will taken place.

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 17

Limiting molar conductivity of NH4OH

  is equal to : [2012]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 17

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 18

Molar conductivities  at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol–1 respectively.  for CH3COOH will be : [2012 M]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 18

 = 91 + 425.9 – 126.4 = 390.5

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 19

A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ? [NEET 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 19

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 20

At 25°C molar conductance of 0.1 molar aqueous solution of ammonium hydroxide is 9.54 ohm-1 cm2mol-1 and at infinite dilution its molar conductance is 238 ohm-1 cm2 mol-1. The degree or ionisation of ammonium hydroxide at the same concentration and temperature is :[NEET 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 20

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 21

A button cell used in watches function s as following

If half cell potentials are :

The cell potential will be : [NEET 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 21

Cell = E°OP + E°RP = 0.76 + 0.314 = 1.10 V

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 22

How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes (1 Faraday = 96,500 C; Atomic mass of Co = 59 u) [NEET Kar. 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 22

Applying,

Equivalent weight of cobalt (II) = 59/2
I = 10 A
Time (t) = 109 min = 109 × 60 sec
Substituting these values we get,

31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 23

Consider the half-cell reduction reaction :

The E° for the reaction  and possibility of the forward reaction are, respectively [NEET Kar. 2013]

Detailed Solution for 31 Year NEET Previous Year Questions: Electrochemistry - 1 - Question 23

ΔE° =  E°red + E°oxd = – 1.81 – 1.51
= – 2.69
Since ΔE° is negative 
∴    ΔG = –nFE°, ΔG will have positive value so, forward reaction is not possible.

135 videos|347 docs|182 tests
Information about 31 Year NEET Previous Year Questions: Electrochemistry - 1 Page
In this test you can find the Exam questions for 31 Year NEET Previous Year Questions: Electrochemistry - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for 31 Year NEET Previous Year Questions: Electrochemistry - 1, EduRev gives you an ample number of Online tests for practice

Up next

135 videos|347 docs|182 tests
Download as PDF

Up next