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31 Year NEET Previous Year Questions: Redox Reactions - NEET MCQ


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16 Questions MCQ Test Chemistry Class 11 - 31 Year NEET Previous Year Questions: Redox Reactions

31 Year NEET Previous Year Questions: Redox Reactions for NEET 2024 is part of Chemistry Class 11 preparation. The 31 Year NEET Previous Year Questions: Redox Reactions questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Redox Reactions MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Redox Reactions below.
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31 Year NEET Previous Year Questions: Redox Reactions - Question 1

Which substance serves as reducing agent in the following reaction ? [1994]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 1

The element undergo oxidation itself and reduces others is known as reducing agent.
In this reaction O. N. of Ni Changes from 0 to + 2 and hence Ni acts as a reducing agent.

31 Year NEET Previous Year Questions: Redox Reactions - Question 2

Phosphorus has the oxidation state of + 3 in

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 2

O.N. of P in H3PO3 (phosphorous acid) 3 × 1 + x + 3 × (– 2) = 0 or x = + 3 In orthophosphoric acid (H3PO4) O.N. of P is + 5, in hypophosphorous acid (H3PO2) it is + 1 while in metaphosphoric acid (HPO3), it is + 5,

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31 Year NEET Previous Year Questions: Redox Reactions - Question 3

In which of the following reactions, there is no change in valency ? [1994]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 3


In this reaction, none of the elements undergoes a change in oxidation number or valency.

31 Year NEET Previous Year Questions: Redox Reactions - Question 4

The oxidation number of chromium in potassium dichromate is [1995]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 4

Let x = oxidation no. of Cr in K2Cr2O7.
∴ (2 × 1) + (2 × x) + 7 (– 2) = 0
or 2 + 2x – 14  = 0 or x = + 6.

31 Year NEET Previous Year Questions: Redox Reactions - Question 5

The loss of electron is termed as [1995]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 5

Losing of electron is called oxidation,

31 Year NEET Previous Year Questions: Redox Reactions - Question 6

The oxide, which cannot act as a reducing agent, is[1995]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 6

Carbon has the maximum oxidation state of + 4, therefore carbon dioxide (CO2) cannot act as a reducing agent.

31 Year NEET Previous Year Questions: Redox Reactions - Question 7

Which of the following involves a redox reaction?

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 7

(not redox reaction)

here oxidation of N2 & reduction of O2 is taking place

(not redox reaction)

31 Year NEET Previous Year Questions: Redox Reactions - Question 8

The oxidation number of phosphorus in pyrophosphoric acid is [1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 8

Pyrophosphoric acid H4P2O7  
Let oxidation state of phosphorus is x(4 × 1 + (– 2) × 7 + 2 x) = 0
∴ 2x = 10   or  x = +5

31 Year NEET Previous Year Questions: Redox Reactions - Question 9

The following redox reaction is balanced by which set of coefficients ? [1999]


Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 9

operate eq. (1) × 4 + eq. (2) × 1

31 Year NEET Previous Year Questions: Redox Reactions - Question 10

A compound contains atoms of three elements A, B and C. If the oxidation number of A is +2, B is +5, and that of C is –2, the possible formula of the compound is : [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 10

Oxidation number of a compound must be 0.
Using the values for A, B and C in the four options we find that A3(BC4)2 is the answer.
Check : (+2)3 + [(+5)+4(–2)]2 = 6 + (5–8)2 = 0

31 Year NEET Previous Year Questions: Redox Reactions - Question 11

Zn gives H2 gas with H2SO4 and HCl but not with HNO3 because [2002]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 11

Zinc gives H2 gas with dil H2SO4/HCl but not with HNO3 because in HNO3, NO3 ion is reduced and give NH4NO3, N2O, NO and NO2 (based upon the concentration of HNO3)

Zn is on the top position of hydrogen in electrochemical series. So Zn displaces H2 from dilute H2SO4 and HCl with liberation of H2.

31 Year NEET Previous Year Questions: Redox Reactions - Question 12

The oxidation states of sulphur in the anions SO32–, S2O42– and S2O62– follow the order [2003]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 12

The correct answer is option B
Oxidation state of S2​O42−
2(x) + 4(−2) = −2
 2x = 8 − 2
 2x = 6
  x = 3
Oxidation state of SO32−
x + 3(−2) = −2
 x = 6 − 2
 x = 4
Oxidation state of S2​O62−
2(x) + 6(−2) = −2
 2x = 12 − 2
 2x = 10
   x = 5
So the oxidation state of sulphur in the anions S2​O42−​, S2​O42−​ and S2​O62−​ follows the order.S2​O42−​ < SO32−​ < S2​O62−​.
 

31 Year NEET Previous Year Questions: Redox Reactions - Question 13

Oxidation numbers of P in PO43 , of S in SO42– and that of Cr in Cr2O72–  are respectively [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 13

(i) Sum of oxidation states of all atoms = charge of ion.
(ii) oxidation number of oxygen = -2
Let the oxidation state of P in PO43- is x.
 PO43- 

x + 4 (-2) = - 3
x-8 = - 3
x = +5

Let the oxidation state of S in SO42- is y
y + 4(-2) = -2
y-8 = - 2
y = +6

Let the oxidation state of Cr in Cr2O72- is z.
2 x z+7(-2) = -2
2z-14 = - 2
z=+6
Hence, oxidation state of P, S and Cr are +5, +6 and +6

31 Year NEET Previous Year Questions: Redox Reactions - Question 14

When Cl2  gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from : [2012]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 14

The correct answer is Option B.

 

The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

3Cl2 ​+ 6NaOH ⟶ NaClO3 ​+ 5NaCl + 3H2​O

 Oxidation number of Cl is 0 in Cl2, −1 in NaCl and +5 in NaClO3

​So, the oxidation number of chlorine changes from Zero to -1 and Zero to +5.

31 Year NEET Previous Year Questions: Redox Reactions - Question 15

A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated. During the reaction which element undergoes maximum change in the oxidation number ? [2012]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 15

i.e. maximum change in oxidation number is observed in Cl (+5 to –1).

31 Year NEET Previous Year Questions: Redox Reactions - Question 16

Standard reduction potentials of the half reactions are given below :

The strongest oxidising and reducing agents respectively are : [2012 M]

Detailed Solution for 31 Year NEET Previous Year Questions: Redox Reactions - Question 16

Higher the value of reduction potential higher will be the oxidising power whereas the lower the value of reduction potential higher will be the reducing power.

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