Assertion & Reason Test: d & f-Block Elements


10 Questions MCQ Test Chemistry Class 12 | Assertion & Reason Test: d & f-Block Elements


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Attempt Assertion & Reason Test: d & f-Block Elements | 10 questions in 20 minutes | Mock test for NEET preparation | Free important questions MCQ to study Chemistry Class 12 for NEET Exam | Download free PDF with solutions
QUESTION: 1

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Cu2+ iodide is not known.

Reason (R): Cu2+ oxidises I– to iodine.

Solution: Cu2+ oxidises iodide to iodine hence cupric iodide is converted to cuprous iodide.
QUESTION: 2

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Separation of Zr and Hf is difficult.

Reason (R): Because Zr and Hf lie in the same group of the periodic table.

Solution: Separation of Zr and Hf is difficult as both have the same size.
QUESTION: 3

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Transition metals have low melting points.

Reason (R): The involvement of greater number of (n – 1)d and ns electrons in the interatomic metallic bonding.

Solution: Transition metals have high melting points because of the involvement of greater number of (n – 1)d and ns electrons in the interatomic metallic bonding.
QUESTION: 4

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion: Separation of Zr and Hf is difficult.

Reason: Because Zr and Hf lie in the same group of the periodic table.

Solution: Separation of Zr and Hf is difficult as both have same size.
QUESTION: 5

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Chemistry of Actinoids is more complicated than Lanthanoids.

Reason (R): Actinoid elements are radioactive in nature.

Solution: Chemistry of actinoids is more complicated than Lanthanoids because actinoids are radioactive elements having relatively short half-lives.
QUESTION: 6

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): The highest oxidation state of osmium is +8.

Reason (R): Osmium is a 5d-block element.

Solution: The highest oxidation state of osmium (Os) is +8. It is due to its ability to expand octet by using its all 8 electrons.
QUESTION: 7

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Cu cannot liberate hydrogen from acids.

Reason (R): Because it has positive electrode potential.

Solution: Copper (Cu) does not liberate hydrogen from acids due to the presence of positive electrode potential.
QUESTION: 8

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Transition metals have high melting point.

Reason (R): Transition metals have completely filled d-orbitals.

Solution: Transition metals have high melting points because of the involvement of greater number of (n – 1)d and ns electrons in the interatomic metallic bonding.
QUESTION: 9

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Chromium is an actinoid.

Reason (R): In Chromium, 3d orbitals are filled.

Solution: Chromium is a transition element and it belongs to 3d series because in chromium, 3d orbitals are filled.
QUESTION: 10

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Cerium (Ce) exhibits +4 oxidation state.

Reason (R): Ce4+ has 4f4 electronic configuration which is less stable.

Solution: Cerium exhibits +4 oxidation state because Ce4+ has 4f0 electronic configuration which is most stable.
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