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This mock test of Test: Integrated Rate Equation for Class 12 helps you for every Class 12 entrance exam.
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QUESTION: 1

The half life of a first order reaction is equal to:

Solution:

The correct answer is Option C

For a first-order reaction, the half-life is given by: t_{1/2} = 0.693/k

QUESTION: 2

For zero order reaction, linear plot was obtained for [A] vs t, the slope of the line is equal to:

Solution:

For zero order reaction the rate equation is [A] = -kt + [Ao]

Thus the slope of the line is -ko

QUESTION: 3

The first order rate constant for the decomposition of N_{2}O_{5} is 6.2 x 10^{-4} sec^{-1}. The t_{1/2} of the decomposition reaction is

Solution:

The correct answer is option B

t_{1/2} = k0.693

= 0.693/(6.2 × 10^{− 4}) = 1117.7s

QUESTION: 4

Find the overall order of a reaction whose rate constant is k = 3x10^{-4} s^{-1}

Solution:

The correct answer is option D

Units:- for K can be calculated by (Mole)^{1-n} (Litre )^{n-1} Time ^{-1}...

Here,n is the order of the reaction ....

On substituting n = 1.

We get, K units as;

K = (Mole)^{1-1}( Litre)^{1-1} sec^{-1}.

K=sec-1.......

QUESTION: 5

Which of the following represents the expression for the 3/4^{th} life of a first order reaction?

Solution:

The correct answer is option A

As we know, for a first order reaction,

QUESTION: 6

The type of reaction that gives constant half life is

Solution:

The correct answer is Option A

For first order reaction, the half-life period is independent of initial concentration.

For first order reaction, the half-life period expression (t1/2) is given by the expression t1/2= , where k is the rate constant.

QUESTION: 7

The half life period of first order reaction is 15 min. Its rate constant will be equal to

Solution:

The half life of a reaction is 15 min

So,

Here we go..

Formula to be used :

K =0.693/t = 0.693/15

__= 0.462/10 = 0.0462 min^-1

QUESTION: 8

For zero order reaction, the integrated rate equation is:

Solution:

QUESTION: 9

The half life of a zero order reaction is equal to:

Solution:

[A] = -kt + [A]_{0}

Here, [A] = [A_{0}]/2

[A]_{0}/2 = -kt + [A]_{0}

kt = [A]_{0} - [A]0/2

t = [A]_{0}/2k

t_{1/2} = [A]_{0}/2k

QUESTION: 10

If [A] is the concentration of reactant A at any time t and [A_{o}] is the concentration at t=0, then for the first order reaction the rate equation can be written as:

Solution:

### Integrated Rate Equation for Zeroth order Reactions

Video | 04:24 min

### Integrated Rate Equation for First order Reactions

Video | 05:05 min

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