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Test: Isomerism in Coordination Compounds - NEET MCQ


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25 Questions MCQ Test Chemistry Class 12 - Test: Isomerism in Coordination Compounds

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Test: Isomerism in Coordination Compounds - Question 1

Which of the following compounds will show facial and meridional isomerism?
(A)[Co(NH3)3Cl3]
(B)[Co(acac)3
(C)[Co(dien)(NO2)3]
 (D)[Co(gly)3]

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 1

Test: Isomerism in Coordination Compounds - Question 2

Which of the following types of octahedral complexes will exhibit geometrical isomerism (where, M = metal, a, b = achiral ligands)?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 2

Octahedral complexes of formula [Ma4b2] in which the two ligands b may be oriented cis or trans to each other, e.g.

Geometrical isomers (cis and trans) of [Co(NH3)4CI2]+.

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Test: Isomerism in Coordination Compounds - Question 3

Which of the following can exhibit linkage isomerism?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 3

Ligand which can ligate through two different atoms is called ambidentate ligand. NO2- ion can coordinate either through nitrogen or through oxygen to a central metal atom/ion.


Hence, ligand show linkage isomerism, e.g. the complex [Co(NH3)5(NO2)]CI2 which is obtained as the red form, in which the nitrite ligand is bound through oxygen (—ONO) and as the yellow form, in which the nitrite ligand is bound through nitrogen (— NO2). 

Test: Isomerism in Coordination Compounds - Question 4

What type of isomerism is shown by [Co(NH3)4Br2]Cl?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 4

The complex [Co(NH3)4Br2]CI show geometrical and ionisation isomerism.

Test: Isomerism in Coordination Compounds - Question 5

Which of the following does not show optical isomerism?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 5

Due to symmetry in the complex [Co(NH3)3CI3], it failed to show optical isomerism. The type of coordination entity show fac and mer isomerism or geometrical isomerism.


The facial (fac) and meridional (mer) isomers of [Co(NH3)3CI3]. 

Test: Isomerism in Coordination Compounds - Question 6

The ionisation isomer of [Cr(H2O)4 CI(NO2)]CI is

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 6

Ionisation isomerism is due to the exchange of groups between the complex ion and the ions outside it, e.g. [Cr(H2O)4CI(NO2)CI] and [Cr(H2O)4CI2]NO2 show ionisation isomerism. 

Test: Isomerism in Coordination Compounds - Question 7

Which of the following complex species is not expected to exhibit optical isomerism?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 7

[CoNH3CI3] do not exhibit optical isomerism. Optical isomerism is shown by M(AA)2X2 type, M(AA)3 type , [M(AA) B2X2] type complexes containing hexadentate ligand and MLa Lb Lc Ld Left type.

Test: Isomerism in Coordination Compounds - Question 8

The complex [Co(NH3)6[Cr(C2O4)3] and [Cr(NH3)6[Co(C2O4)3] exhibit

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 8

Coordination isomerism is possible when both positive and negative ions of a salt are complex ions and two isomers differ in distribution of ligands in the cation and the anion.

Test: Isomerism in Coordination Compounds - Question 9

Which of the following exhibit cis-trans isomerism?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 9

All the three compounds, i.e. [PtCI2(NH3)2], [PdCl2Brl] and [Pt(NH3)(py)(CI)(Br)] exhibit cis and trans isomerism.

Test: Isomerism in Coordination Compounds - Question 10

Which of the following is considered to be an anticancer species?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 10

cis platin is used as anticancer drug.

*Multiple options can be correct
Test: Isomerism in Coordination Compounds - Question 11

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. 

Linkage isomerism is/are shown by

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 11

Linkage isomerism occurs when two or more atoms in a monodentate ligand may function as a donor, i.e. when an ambidentate ligand is present. e.g. , CN- and SCN-.

*Multiple options can be correct
Test: Isomerism in Coordination Compounds - Question 12

Which is/are correct pair?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 12

K[Ag(CN)2]show linkage isomerism.
[CrCI(NH3)5] I2 show ionisation isomerism.
[PtCI4I2] show geometrical isomerism.

*Multiple options can be correct
Test: Isomerism in Coordination Compounds - Question 13

Coordination isomerism is/are shown by

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 13

This type of isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex.

*Multiple options can be correct
Test: Isomerism in Coordination Compounds - Question 14

Which of the following show geometrical isomerism?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 14

Due to symmetry in the complex [Cu(NH3)4]CI2, it fails to show geometrical isomerism but all others show.

Test: Isomerism in Coordination Compounds - Question 15

Which of the following statements is/are correct?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 15

Geometrical isomerism is not observed in complexes of coordination number 4 having tetrahedral geometry. The platinumglycinato complex [ Pt(gly)2 show geometrical isomerism (cis and trans form).

Test: Isomerism in Coordination Compounds - Question 16

Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data etc. Two questions related to the paragraph have been given. Each has only one correct answer among the four given options (a) ,(b), (c) and (d).

Passage

Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, grey sphere represents NH3 and unshaded sphere represents Br.

Q.

The oxidation state and coordination number of cobalt in the complex [Co(NH3)4Br2]+ are

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 16

For O.S:

X + 0 + 2(-1) = 1

X = 3

Coordination number is the number of molecules linked to the central atom.

Hence B is the correct answer.

Test: Isomerism in Coordination Compounds - Question 17

Passage

Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, grey sphere represents NH3 and unshaded sphere represents Br.

Q. 

Which of the structures is identical?

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 17

Structure (a) = structure (c) and, structure (b) = structure (d)

Test: Isomerism in Coordination Compounds - Question 18

Matching List Type

Direction (Q, Nos. 18 and 19) Choices for the correct combination o f elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.

Q. 

Match the Column ! with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 18

[Co(NH3)4CI2]+ exhibits geometrical isomerism.
cis-[Co(en)2CI2]+ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH3)5(NO2)]CI2 because of the presence of ambidentate (NO2) ligand exhibit linkage isomerism. [Co(NH3)6][Cr(CN)6] exhibits coordination isomerism because here, cation and anion both are complex.

(i) → (s), (ii) →(p), (iii) → (t), (iv) → (r)

Test: Isomerism in Coordination Compounds - Question 19

Match the Column I with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 19

(i) → (r,s), (ii) → (p,q,t), (iii) → (p,q,t), (iv) → (r,s)

*Answer can only contain numeric values
Test: Isomerism in Coordination Compounds - Question 20

One Integer Value Correct Type

Direction (Q. Nos. 20-24) This section contains 5 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q. 

Total number of geometrical isomers for the complex [RhCI(CO)(PPh3)(NH3)] is


Detailed Solution for Test: Isomerism in Coordination Compounds - Question 20

For a complex of the type MABCD, three geometrical isomers are possible.

*Answer can only contain numeric values
Test: Isomerism in Coordination Compounds - Question 21

The total number of isomers of [Co(en)2CI2]+ is


Detailed Solution for Test: Isomerism in Coordination Compounds - Question 21

The complex has cis and trans isomers. The c/s has non-superimposable mirror images. Hence, total are 3.

*Answer can only contain numeric values
Test: Isomerism in Coordination Compounds - Question 22

The total number of possible isomers for the complex compound [Cull(NH3)4][PtlICI4]


Detailed Solution for Test: Isomerism in Coordination Compounds - Question 22

[Cu(NH3)3CI][Pt(NH3)CI3], [Cu(NH3)CI3][Pt(NH3)3CI]
[Cu(NH3)4] [PtCI4], [Pt(NH3)4] [CuCI4]

*Answer can only contain numeric values
Test: Isomerism in Coordination Compounds - Question 23

The number of geometrical isomers possible for Cr(NH3)3CI3 are


Detailed Solution for Test: Isomerism in Coordination Compounds - Question 23

This is [Ma3b3] type of complex and this has two geometrical isomers called facial (fac isomer) and meridional (mer isomer).

*Answer can only contain numeric values
Test: Isomerism in Coordination Compounds - Question 24

For square planar complex of platinum (II), [Pt(NH3)(Br)(CI)py]2+, how many isomeric forms are possible?


Detailed Solution for Test: Isomerism in Coordination Compounds - Question 24

[Mabcd] type complexes exist in three isomeric forms. 


Test: Isomerism in Coordination Compounds - Question 25

Statement Type

Direction ( Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below. 

Q. 

Statement I : Complexes of MX6 and MX5L type do not show geometrical isomerism. Assume that X and L are unidentate.

Statement Il : Geometrical isomerism is not shown by complexes of coordination number 6.

Detailed Solution for Test: Isomerism in Coordination Compounds - Question 25

MX6 and MX5L type complexes do not exhibit geometrical isomerism, cis [Co(en)2CI2]+ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH3)5(NO2)]CI2 because of the presence of ambidentate (NO2) ligand exhibit linkage isomerism. [CoNH3)6][Cr(CN)6] exhibits coordination isomerism because here cation and anion both are complex.

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