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Test: Lanthanoids & Actinoids - NEET MCQ


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10 Questions MCQ Test Chemistry Class 12 - Test: Lanthanoids & Actinoids

Test: Lanthanoids & Actinoids for NEET 2024 is part of Chemistry Class 12 preparation. The Test: Lanthanoids & Actinoids questions and answers have been prepared according to the NEET exam syllabus.The Test: Lanthanoids & Actinoids MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Lanthanoids & Actinoids below.
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Test: Lanthanoids & Actinoids - Question 1

Which of the following group contain mostly radioactive elements ?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 1

The actinoids are said to be most radioactive metals because in this group all the metals have very oxidation number and are very rare metals found on earth and it has all the elements radioactive in its group and it has most radioactive metal uranium in it's group.

Test: Lanthanoids & Actinoids - Question 2

 Mischmetal is an alloy of:

Detailed Solution for Test: Lanthanoids & Actinoids - Question 2

The correct answer is option A

Misch metal, alloy consisting of about 50 percent cerium, 25 percent lanthanum, 15 percent neodymium, and 10 percent other rare-earth metals.

Test: Lanthanoids & Actinoids - Question 3

What is the most common oxidation state for actinoids?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 3

The correct answer is option A
The most common oxidation state of actinide is +3. It is obtained when one 6d and two 7s electrons are lost. The general electronic configuration of actinides may be written as [Rn]5f1−146d0−17s2.

Test: Lanthanoids & Actinoids - Question 4

The electronic configuration of Eu 3+ ion is:

Detailed Solution for Test: Lanthanoids & Actinoids - Question 4

The correct answer is option D
Atomic number of Eu is 63 so electronic configuration of Eu is, Eu=[xe] 4f9 Hence,Eu+3=[xe]4f6

Test: Lanthanoids & Actinoids - Question 5

A member of the lanthanoid series which is well known to exhibit +4 oxidation state is:

Detailed Solution for Test: Lanthanoids & Actinoids - Question 5

The correct answer is option C
Cerium
Electronic configuration of Ce=[Xe]4f15d16s2
Formation of Ce+4 is favoured by its noble gas configuration due to which it shows +4 oxidation state.
It can be easily converted into Ce+3, due to which Ce+4 acts as an oxidising agent.

Test: Lanthanoids & Actinoids - Question 6

How many elements belong to lanthanide series?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 6

The lanthanide are f-block elements which contain seven f-orbitals . The maximum electrons can be filled in f-orbitals are 14. Hence, lanthanide have total 14 elements.

Test: Lanthanoids & Actinoids - Question 7

 In which of the following oxidation states La achieve the noble gas configuration?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 7

In +3 oxidation state Lanthanum(La) achieves the noble gas configuration.

Test: Lanthanoids & Actinoids - Question 8

 Which of the following statement is true?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 8

The correct answer is option C
The 5f orbitals (in case of actinoids) have a poorer shielding effect than 4f orbitals (in lanthanoids). Thus, the effective nuclear charge experienced by electron in valence shells in case of actinoids is greater than that in lanthaniods.

Test: Lanthanoids & Actinoids - Question 9

 The common oxidation state of the elements of lanthanoids series is:

Detailed Solution for Test: Lanthanoids & Actinoids - Question 9

The correct answer is Option A
Lanthanides show variable oxidation states. The most stable oxidation state of Lanthanides is +3. They also show +2 and +4 oxidation states due to the presence of either half filled or completely filled or empty 4f subshell.
 

Test: Lanthanoids & Actinoids - Question 10

In which of the following oxidation state Cerium achieves the noble gas configuration?

Detailed Solution for Test: Lanthanoids & Actinoids - Question 10

Any atom exhibit oxidation state in which it is found to be stable. It is second element of Lanthanide series having atomic number 58. General electronic configuration is
[Xe] 4f1 5d1 6s2.
Lanthanide are very less electronegative. Their electronegative value is nearly equal to s-block elements. So they can lose electrons to form cation. When Cerium loses 4 e-, it will acquire fully field electronic configuration of Xenon (2,8,18,18,8). As fully filed or half filed electronic configuration possesses extra stability.
Therefore, Cerium exhibits +4 oxidation state.

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