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Test: Nitrogen & Phosphorous Compounds - NEET MCQ


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20 Questions MCQ Test Chemistry Class 12 - Test: Nitrogen & Phosphorous Compounds

Test: Nitrogen & Phosphorous Compounds for NEET 2024 is part of Chemistry Class 12 preparation. The Test: Nitrogen & Phosphorous Compounds questions and answers have been prepared according to the NEET exam syllabus.The Test: Nitrogen & Phosphorous Compounds MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Nitrogen & Phosphorous Compounds below.
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Test: Nitrogen & Phosphorous Compounds - Question 1

Direction (Q. Nos. 1-7) This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q. 

The hybridisation of N in solid state for N2O5 is

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 1

In solid state, N2O5 exists as nitronium nitrate 
In   nitrogen is sp and in  , nitrogen is sp2.

Test: Nitrogen & Phosphorous Compounds - Question 2

PH3 becomes spontaneously inflammable due to the presence of

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 2

Pure phoshine is not inflammable but due to contamination of P2H4 and P4 vapours, it becomes inflammabl.

Test: Nitrogen & Phosphorous Compounds - Question 3

Which is incorrect among the following options?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 3

Reducing property of P oxyacids is due to P—H bonds in the acid. Correct reducing property order is

Test: Nitrogen & Phosphorous Compounds - Question 4

The number of P – O bonds and lone pairs of electron present in P4O6 molecule respectively  

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 4

Number of P – O bonds = 12 
Number of pair of electron = 16 

Test: Nitrogen & Phosphorous Compounds - Question 5

Which is the correct order of basic strength ?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 5

NH2OH and NH2—NH2 may be considered as NH3 derivatives in which H is replaced but — OH and NH2 respectively. Due to their electron withdrawing nature, these groups decreases electron density over nitrogen making them less basic. The effect of — OH group is stronger than —NH2

Test: Nitrogen & Phosphorous Compounds - Question 6

Solid PCl5 and solid PBr5 exist respectively as

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 6

PBr does not split in the same fashion. The anion is not possible due to large size of Br-atoms. Hence, it splits differently.

Test: Nitrogen & Phosphorous Compounds - Question 7

Number of moles of NaOH needed to neutralise one mole each of H3PO2, H3PO3 and H3PO4 respectively are

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 7

H3PO2, H3PO3 and H3PO4 are mono, di and tribasic acids respectively.

*Multiple options can be correct
Test: Nitrogen & Phosphorous Compounds - Question 8

Direction (Q. Nos. 8-12) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. 

Which of the following can act as dehydrating agent ?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 8

P4O10,POCI3 and cone. H2SO4 are act as dehydrating agent.

*Multiple options can be correct
Test: Nitrogen & Phosphorous Compounds - Question 9

NO2 is obtained by heating

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 9

Sodium and potassium nitrate on heating gives nitrite and oxygen but not NO2

*Multiple options can be correct
Test: Nitrogen & Phosphorous Compounds - Question 10

Phosphine is obtained when

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 10

*Multiple options can be correct
Test: Nitrogen & Phosphorous Compounds - Question 11

Acetamide can be converted to methenamine by which of the following reactions?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 11

 Option (B) Hoffmann bromamide reaction

Test: Nitrogen & Phosphorous Compounds - Question 12

Which of the correct statement for the given acids?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 12

Phosphinic acid is a monoprotic acid as it contains one P−OH bond while phosphonic acid is a diprotic acid as it contains two P−OH bonds.

Test: Nitrogen & Phosphorous Compounds - Question 13

Direction (Q. Nos. 13 and 14) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

In the all oxyacids of phosphorus, each phosphorus atom is in sp3-hybridised state. All these acids contain P—OH bonds, the hydrogen atom of which are ionisable imparting acidic nature to the compound. The ‘ous’ acids (oxidation state of P is + 1 or + 3) also have P—H bonds in which hydrogens are not ionisable.
The presence of P—H bonds in these acids imparts reducing properties. The structure of some oxyacids are drawn below:


 

 

Q. 

Although metaphosphoric acid is written as a monomer, it exists as a polymer (HPO3)n. The number of P—O—P bonds in cyclic trimetaphosphoric acid is

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 13


Test: Nitrogen & Phosphorous Compounds - Question 14

In the all oxyacids of phosphorus, each phosphorus atom is in sp3-hybridised state. All these acids contain P—OH bonds, the hydrogen atom of which are ionisable imparting acidic nature to the compound. The ‘ous’ acids (oxidation state of P is + 1 or + 3) also have P—H bonds in which hydrogens are not ionisable.
The presence of P—H bonds in these acids imparts reducing properties. The structure of some oxyacids are drawn below:

 


 

 

Q. 

Which of the acids show reducing properties?

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 14

Due to the presence of H in A and B , they showre ducing properties.

Test: Nitrogen & Phosphorous Compounds - Question 15

Direction (Q. Nos. 15 and 16) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Q.

Match the Column I with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 15

Test: Nitrogen & Phosphorous Compounds - Question 16

Match the Column I with Column II and mark the correct option from the codes given below.

 

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 16

*Answer can only contain numeric values
Test: Nitrogen & Phosphorous Compounds - Question 17

Direction (Q. Nos. 17-19) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q. 

Number of chemical species having bond between nitrogen atoms

N2O4, N2O5, N2H4, N2O , N2O3, NH4NO3, H2N2O2 


Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 17

N2O5 , N2O and NH4NO3 have no bond between nitrogen atoms while others have.

*Answer can only contain numeric values
Test: Nitrogen & Phosphorous Compounds - Question 18

Number of metals that show passivity with cone. HNO3 among Cr, Fe, Ni, Cu, Zn Al, Ag, Sn.


Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 18

Cr, Fe, Ni and Al are passive towards cone . HNO3.

*Answer can only contain numeric values
Test: Nitrogen & Phosphorous Compounds - Question 19

2H3PO2 → H3PO4 + PH3  in this equivalent weight of the acid in the reactant side is obtained by dividing molecular weight with


Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 19


Equivalent weight, E1 (oxidation) = M/4 and
Equivalent weight, E2 (reduction) 
= M /4 
Equivalent wight of H3PO2 in the disproportionation reaction

Molecular nitrogen is less reactive than that of oxygen because nitrogen has high dissociation energy in comparison to oxygen so, its reactivity is less. Also bond length of nitrogen is shorter than oxygen because of the presence of triple bond between nitrogen atoms. So, both are true but not correct explanation.  

Test: Nitrogen & Phosphorous Compounds - Question 20

Direction (Q. No. 20)  This section is bassed on Statment I and Statment II. II. Select the correct answer from the codes given below.

Q. 

 Statement I : NF3 is a weaker ligand than N(CH3)3

Statement II : NF3 ionises to give F- ions in aqueous solutio

Detailed Solution for Test: Nitrogen & Phosphorous Compounds - Question 20

Due to e- withdrawing capacity of fluorideion, it withdraws. from nitrogen in NF3 make it weakerlig and while presence of e- donating methyl group makes the nitrogen in N(CH3)3 a strong ligand. In aqueous medium, NF3 furnishes fluorideion.

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