All Courses
Get the App Signup / Login
Sign in Open App
CA Foundation Exam  >  CA Foundation Tests  >  Quantitative Aptitude for CA Foundation  >  Test: Basic Concepts Of Differential And Integral Calculus- 1 - CA Foundation MCQ

Test: Basic Concepts Of Differential And Integral Calculus- 1 - CA Foundation MCQ


Test Description

30 Questions MCQ Test Quantitative Aptitude for CA Foundation - Test: Basic Concepts Of Differential And Integral Calculus- 1

Test: Basic Concepts Of Differential And Integral Calculus- 1 for CA Foundation 2024 is part of Quantitative Aptitude for CA Foundation preparation. The Test: Basic Concepts Of Differential And Integral Calculus- 1 questions and answers have been prepared according to the CA Foundation exam syllabus.The Test: Basic Concepts Of Differential And Integral Calculus- 1 MCQs are made for CA Foundation 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basic Concepts Of Differential And Integral Calculus- 1 below.
Solutions of Test: Basic Concepts Of Differential And Integral Calculus- 1 questions in English are available as part of our Quantitative Aptitude for CA Foundation for CA Foundation & Test: Basic Concepts Of Differential And Integral Calculus- 1 solutions in Hindi for Quantitative Aptitude for CA Foundation course. Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free. Attempt Test: Basic Concepts Of Differential And Integral Calculus- 1 | 40 questions in 40 minutes | Mock test for CA Foundation preparation | Free important questions MCQ to study Quantitative Aptitude for CA Foundation for CA Foundation Exam | Download free PDF with solutions
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 1
Save

Choose the most appropriate option (a) (b) (c) or (d)

The gradient of the curve y = 2x3 –3x2 – 12x +8 at x = 0 is

Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 1

ANSWER :- a

Solution :- 2x^3 - 3x^2 -12x + 8 = 0 

dy/dx = 6x^2 - 6x -12 = 0

(At x=0) = 6(0)^2 - 6(0) - 12 

        = -12

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 2
Save

The gradient of the curve y = 2x3 –5x2 – 3x at x = 0 is

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 3
Save

The derivative of y = 

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 4
Save

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 5
Save

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 6
Save

If y = x (x –1) (x – 2) then  is
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 7
Save

The gradient of the curve y – xy + 2px + 3qy = 0 at the point (3, 2 ) is and q are
Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 7



Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 8
Save

The curve y2 = ux3 + v passes through the point P(2, 3) and  = 4 at P. The values of u and v are 
Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 8

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 9
Save

The gradient of the curve y + px +qy = 0 at (1, 1) is 1/2. The values of p and q are
Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 9

y+px+qy=0
y+qy=-px
(1+q)y=-px
y=-[p/(1+q)]x
This is a linear function, so has constant gradient at all points on the curve. Hence
-p/(1+q)=1/2
2p=-(1+q)
But there is an issue: you have stated that the curve's gradient is 1/2 at the point (1,1) but the curve does not cross through this point! Regardless of our choices for p and q satisfying the expressions above this paragraph, the equation of the curve will always simplify to y=0.5x, which crosses through the origin (0,0), as well as (1,0.5) and (2,1) - but not (-1,1).
For your curve to pass through (-1,1), we would need to add a constant term, like so:
y+px+qy=1/2
 

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 10
Save

If xy = 1 then y2 + dy/dx is equal to
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 11
Save

The derivative of the function 
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 12
Save

Given e-xy –4xy = 0,  can be proved to be
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 13
Save

Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 13

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 14
Save

If log (x / y) = x + y,   may be found to be
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 15
Save

If f(x, y) = x3 + y3 – 3axy = 0,  can be found out as
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 16
Save

Given x = at2, y = 2at;  is calculated as
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 17
Save

Given x = 2t + 5, y = t2 – 2;  is calculated as 
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 18
Save

If y = 
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 19
Save

If x = 3t2 –1, y = t3 –t, then   is equal to
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 20
Save

The slope of the tangent to the curve y = at the point, where the ordinate and the abscissa are equal, is
Detailed Solution for Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 20

so the point is (√2,√2)

= -1

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 21
Save

The slope of the tangent to the curve y = x2 –x at the point, where the line y = 2 cuts the curve in the Ist quadrant, is
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 22
Save

For the curve x2 + y2 + 2gx + 2hy = 0, the value of  at (0, 0) is
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 23
Save

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 24
Save

If xy.yx = M, M is constant then is equal to
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 25
Save

Given x = t + t–1 and y = t – t–1 the value of  at t = 2 is
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 26
Save

If x3 –2x2 y2 + 5x +y –5 =0 then  at x = 1, y = 1 is equal to
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 27
Save

The derivative of x2 log x is
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 28
Save

The derivative of 
Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 29
Save

Test: Basic Concepts Of Differential And Integral Calculus- 1 - Question 30
Save

View more questions
148 videos|174 docs|99 tests
Join Course
Information about Test: Basic Concepts Of Differential And Integral Calculus- 1 Page
In this test you can find the Exam questions for Test: Basic Concepts Of Differential And Integral Calculus- 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Basic Concepts Of Differential And Integral Calculus- 1, EduRev gives you an ample number of Online tests for practice

Top Courses for CA Foundation

Download as PDF

Top Courses for CA Foundation

Important Questions for Basic Concepts Of Differential And Integral Calculus- 1

Find all the important questions for Basic Concepts Of Differential And Integral Calculus- 1 at EduRev.Get fully prepared for Basic Concepts Of Differential And Integral Calculus- 1 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Basic Concepts Of Differential And Integral Calculus- 1 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Basic Concepts Of Differential And Integral Calculus- 1 resources.

Basic Concepts Of Differential And Integral Calculus- 1 MCQs with Answers

Prepare for the Basic Concepts Of Differential And Integral Calculus- 1 within the CA Foundation exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Basic Concepts Of Differential And Integral Calculus- 1 Quantitative Aptitude for CA Foundation

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Basic Concepts Of Differential And Integral Calculus- 1 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup