There is water tank already 4/7 full. If Jose adds 5 gallons of water to the water tank, the tank will be 13/14 full. How many gallons of water would the water tank hold if it were full?
In this case, we need to solve for the volume of the water tank, so we set the full volume of the water tank as x. According to the question, 4/7 -full can be replaced as -full would be 13/14x Therefore, we can write out the equation as:
Then we can solve the equation and find the answer is 14 gallons.
There exists a set X = {1, 2, 3, 4}. Which of the following defines a function of X?
Let's look at f,g,and h and see if any of them are functions.
1. f = {(2, 3), (1, 4), (2, 1), (3, 2), (4, 4)}: This cannot be a function of X because two of the ordered pairs, (2, 3) and (2, 1) have the same number (2) as the first coordinate.
2. g = {(3, 1), (4, 2), (1, 1)}: This cannot be a function of X because it contains no ordered pair with first coordinate 2. Because the set X = {1, 2, 3, 4}, we need an ordered pair of the form (2, ) .
3. h = {(2, 1), (3, 4), (1, 4), (2, 1), (4, 4)}: This is a function. Even though two of the ordered pairs have the same number (2) as the first coordinate, h is still a function of X because (2, 1) is simply repeated twice, so the two ordered pairs with first coordinate 2 are equal.
Let f be a function that assigns x2 to each real number x. Which of the following is NOT an appropriate way to define f?
This is a definition question. The only choice that does not equal the others is f(y)=x2. This describes a function that assigns x2 to some number y, instead of assigning x2 to its own square root, x.
If f(x)=x2, find
We are given f(x) and h, so the only missing piece is f(x + h).
f(x+h)=(x+h)2=x2+2xh+h2
Then
Give the range of the function:
We look at the range of the function on each of the three parts of the domain. The overall range is the union of these three intervals.
On (−∞,−2), f(x) takes the values:
x<−2
2x−1<2(−2)−1
2x−1<−5
f(x)<−5
or (−∞,−5)
On [−2,2], f(x) takes the values:
−2≤x≤2
−3(−2)≥−3x≥−3(2)
6≥−3x≥−6
−6≤f(x)≤6,
or [−6,6]
On (2,∞), f(x) takes only value 5.
The range of f(x) is therefore (−∞,−5)∪[−6,6]∪{5} , which simplifies to (−∞,6].
A sequence begins as follows:
8,12,...
It is formed the same way that the Fibonacci sequence is formed. What are the next two numbers in the sequence?
Each term of the Fibonacci sequence is formed by adding the previous two terms. Therefore, do the same to form this sequence:
8+12=20
12+20=32
Give the inverse of f(x)=5x−7
The easiest way to find the inverse of f(x) is to replace f(x) in the definition with y , switch y with x, and solve for y in the new equation.
y=5x−7
x=5y−7
x+7=5y−7+7
x+7=5y
Define f(x)=x3−8. Give f−1(x)
The easiest way to find the inverse of f(x) is to replace f(x) in the definition with y , switch y with x, and solve for y in the new equation.
y=x3−8
x=y3−8
x+8=y3−8+8
x+8=y3
Define f(x)=x2−4 and g(x)=x2+4.
Give the definition of (f∘g)(x) .
(f∘g)(x)=f(g(x))
=f(x2+4)
=(x2+4)2−4
=x4+8x2+16−4
=x4+8x2+12
Define g(x)=5x−2 .
If g(A)=11, evaluate A.
Solve for A in this equation:
g(A)=5A−2=11
5A−2+2=11+2
5A=13
5A÷5=13÷5
A=2.6
Define the operation Θ as follows:
aΘb=ab+100
Solve for x : 4Θx=72
4Θx=72
4x+100=72
4x+100−100=72−100
4x=−28
4x÷4=−28÷4
x=−7
Define f(x)=A(x−B)3, where A≠0,B≠0.
Evaluate f−1(1) in terms of A and B.
This is equivalent to asking for the value of x for which f(x)=1, so we solve for x in the following equation:
f(x)=1
A(x−B)3=1
Define an operation ⊙ as follows:
For any real numbers a,b ,
a⊙b=(a−1)(b−1)
Evaluate (5⊙5)⊙5.
(5⊙5)⊙5
=[(5−1)(5−1)]⊙5
=(4⋅4)⊙5
=16⊙5
=(16−1)(5−1)
=15⋅4=60
An infinite sequence begins as follows:
1,2,−3,4,5,−6,7,8,−9...
Assuming this pattern continues infinitely, what is the sum of the 1000th, 1001st and 1002nd terms?
This can be seen as a sequence in which the Nth term is equal to N if N is not divisible by 3, and −N otherwise. Since 1,000 and 1,001 are not multiples of 3, but 1,002 is, the 1000th, 1001st, and 1002nd terms are, respectively,
1000,1001,−1002
and their sum is
1000+1001+(−1002)=999
Define f(x)=√x . What is (f∘f)(x) ?
This can best be solved by rewriting √x as1/x2 and using the power of a power property.
(f∘f)(x)=f(f(x)) =
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