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In a series RLC circuit there becomes a frequency point were the inductive reactance of the inductor becomes equal in value to the capacitive reactance of the capacitor. In other words, XL = XC.
Series Resonance circuits are one of the most important circuits used electrical and electronic circuits.
In an RLC circuit, which of the following is always used as a vector reference?
In an RLC circuit, the voltage is always used as a reference and according to the phase of the voltage, the phase of the other parameters is decided.
A 1.0 mH inductance, a10μF capacitance and a 5.0 ohm resistance are connected series to an a.c. source. It is found that inductor and the capacitor show equal reactance. The reactance should be nearest to:
From the formula we get,
X_{L}=X_{C}
ωL=1/ωC
⇒ω^{2}=1/LC
⇒ω=1/√Lc
⇒ω=1/√10^{3}x10^{5}
⇒ω=10^{4}
We also know that,
X_{L}=ωL
⇒X_{L}=104x103
⇒X_{L}=10 Ω
Therefore,X_{L}=X_{C}=10Ω
In which of the following cases the power factor is not equal to 1
What is the inductance of a choke required for a lamp running at 60 volt d.c consuming 5 A current connected to 110 volt, 50 Hz ac mains?
Hotwire instruments are based on the heat I_{rms}^{2}Rt and/or power I_{rms}^{2}R producing property of current. Hence it can measure both ac and dc current as both produce heat when passed through a conductor.
What is the value of power factor in RLC circuit
In a series LCR what will be phase difference between voltage drop across inductor and capacitor
Let’s keep this simple and to the point. We know that:
1.in a series circuit the same current flows through each component
2.the voltage across an ideal inductor L is 90˚ ahead of an AC current through it
3.the voltage across an ideal capacitor C is 90˚ behind an AC current through it
So putting these facts together we can conclude that given an AC series current the voltages across any L and C must have a phase difference of 180˚
A resistance of 5 ohm and an inductance of 50 mH are connected in series with an a. c. I = 100 sin (100 t). What is the phase difference between the instantaneous current and voltage?
Cosφ=R/Z=R/√R^{2}/ ω^{2}L^{2}=5/√(25+(50)^{2}x (0.1)^{2})
=5/√(25+25)=1/√2
⇒φ=π/4
In electrical engineering, admittance is a measure of how easily a circuit or device will allow a current to flow. It is defined as the reciprocal of impedance, analogous to how conductance & resistance are defined. The SI unit of admittance is the siemens (symbol S); the older, synonymous unit is mho, and its symbol is ℧ (an upsidedown uppercase omega Ω). Oliver Heaviside coined the term admittance in December 1887.
Admittance is defined as
Y=1/Z
where
Y is the admittance, measured in siemens
Z is the impedance, measured in ohms
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