Test: Bohr’S Model Of Atom


10 Questions MCQ Test Physics Class 12 | Test: Bohr’S Model Of Atom


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This mock test of Test: Bohr’S Model Of Atom for Class 12 helps you for every Class 12 entrance exam. This contains 10 Multiple Choice Questions for Class 12 Test: Bohr’S Model Of Atom (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Bohr’S Model Of Atom quiz give you a good mix of easy questions and tough questions. Class 12 students definitely take this Test: Bohr’S Model Of Atom exercise for a better result in the exam. You can find other Test: Bohr’S Model Of Atom extra questions, long questions & short questions for Class 12 on EduRev as well by searching above.
QUESTION: 1

If the electron in H atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by

Solution:

We know that
1/λ​=R(1/n21​−1/n22​​)
1/λ=R(1/22) − (1/32​)⇒R(1/4)−(1/9​)
1/λ​=(9−4​/36)R=5R​/36⇒λ=36​/5R

QUESTION: 2

The ratio of the speed of the electron in the ground state of hydrogen atom to the speed of light is​

Solution:

The speed of revolving electron in nth state of hydrogen atom is:
v=​e2/2nhϵ0
For n=1,
v= (1.6×10−19)2​/2(1)(6.6×10−34)(8.85×10−12)
v=2.56×10−38​/116.82×10−46
 
v=0.0219×108ms−1
The speed of light is 3×108
Hence, 
v/c​=0.0219×108​/3×108
v/c​=1/137
 

QUESTION: 3

In hydrogen atom the kinetic energy of electron in an orbit of radius r is given by

Solution:

K.E. of nth orbit
=> (1/k) Ze2/2r
For H atom,
K.E.=(1/4πε) x (e2/2r)

QUESTION: 4

In hydrogen atom the angular momentum of the electron in the lowest energy state is

Solution:
QUESTION: 5

According to Bohr model of hydrogen atom, the radius of stationary orbit characterized by the principal quantum number n is proportional to​

Solution:

r=(0.529Å)n2/7
r ∝n2

QUESTION: 6

Select an incorrect alternative:
i. the radius of the nth orbit is proprtional to n2
ii. the total energy of the electron in the nth orbit is inversely proportional to n
iii. the angular momentum of the electron in nth orbit is an integral multiple of h/2
iv. the magnitude of potential energy of the electron in any orbit is greater than its kinetic energy​

Solution:

Correct Answer :- c

Explanation:- Radius of Bohr's orbit of hydrogen atom is given by

r=(n2h2)/(4π2mKze2)

or

r=(0.59 A˚)(n2)/z

So from expression we found r α n2

 And according to Bohr's theory

Angular momentum of electron in an orbit will be Integral multiple of (h/2π)

Magnitude of potential energy is twice of kinetic energy of electron in an orbit

∣P.E∣=2∣K.E∣

K.E=(13.6ev)[(z2)/(n2)]

QUESTION: 7

To explain his theory Bohr used:

Solution:
QUESTION: 8

In Bohr model of hydrogen atom, radiation is emitted when the electron

Solution:
QUESTION: 9

The number of times an electron goes around the first Bohr orbit in a second is

Solution:

We know that,
mvr=h/2π (for first orbit)
⇒mωr2=h2π⇒m×2πv×r2=h/2π
⇒v=h/4π2mr2

QUESTION: 10

The ratio of volume of atom to volume of nucleus is​

Solution:

The ratio of the volume of the atom and the volume of the nucleus is 1015
The radius of an atomic nucleus is of the order of 10−13cm or 10−15m or one Fermi unit.
On the other hand, the radius of an atom is of the order of 10−8cm or 10−10m or one angstrom unit.
Note:
The radius of nucleus is much smaller than atomic radius.
The ratio of atomic radius to radius of nucleus is 10−10m /10−15m ​=105
Volume is proportional to cube of radius.
The ratio of atomic radius to radius of nucleus is (105)3=1015

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