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This mock test of Test: Combination Of Cells for Class 12 helps you for every Class 12 entrance exam.
This contains 10 Multiple Choice Questions for Class 12 Test: Combination Of Cells (mcq) to study with solutions a complete question bank.
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QUESTION: 1

If cells are joined in parallel, they have _______.

Solution:

QUESTION: 2

If the internal resistance of a cell is 20 ohm and resistance of the circuit is also 20 ohm. Will the current remain same whether the given n identical cells are in series or in parallel?

Solution:

**Correct Answer :- a**

**Explanation:- Since the internal resistance and resistance of the current is same. Therefore for same current R = r**

**For a series combination of n cells**

**the Current is given by:**

**I = n E /(R +n r)**

**For a parallel combination of n cells**

**I = n E /(nR + r)**

QUESTION: 3

Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is

Solution:

QUESTION: 4

When number of identical cells, in parallel combination are increased, the voltage of the circuit will

Solution:

QUESTION: 5

When numbers of cells in series combination are increased, the current of the circuit will

Solution:

QUESTION: 6

If there are n cells of emf E_{1}, E_{2}, …E_{n} and of internal resistances r_{1}, r_{2} …r_{n} , connected in parallel, the combination is equivalent to a cell of emf Eeq such that

Solution:

QUESTION: 7

The equivalent emf of two cells (with ε_{1} > ε_{2}) in series if we connect two negative electrodes of adjacent cells is

Solution:

QUESTION: 8

The internal resistance of two identical cells, with same current whether joined in series or parallel to a 1Ω resistor is

Solution:

QUESTION: 9

If cells are joined in series, they have ________.

Solution:

QUESTION: 10

Three identical cells, each of 2V and internal resistance of 0.2 ohm are connected in series to an external resistance of 7.4 ohm. The current in the circuit will be

Solution:

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