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# Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions)

## 30 Questions MCQ Test Physics Class 12 | Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions)

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This mock test of Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions) for Class 12 helps you for every Class 12 entrance exam. This contains 30 Multiple Choice Questions for Class 12 Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions) (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions) quiz give you a good mix of easy questions and tough questions. Class 12 students definitely take this Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions) exercise for a better result in the exam. You can find other Test: Dual Nature Of Radiation And Matter (CBSE Level With Solutions) extra questions, long questions & short questions for Class 12 on EduRev as well by searching above.
QUESTION: 1

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QUESTION: 2

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QUESTION: 3

### The work function of a photoelectric material is 3.32 eV. The threshold frequency will be equal to

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QUESTION: 4

Energy of a photon of green light of wavelength 5500m  is (given: h = 6.62 ×10−34Js−1) approximately

Solution:

As we know,
the formula for energy of photon in terms of wavelength is,, E = hc/ λ
where, E = energy of photon
h = Planck's constant =
= 6.63×10-34 Js
c = speed of light
= 3×108 m/s
and lambda = wavelength
so,
E = [6.63×10-34 J. s×3×108 m/s]/5500×10-10m
= [0.36×10-26]/10-8
= 0.36×10-18
= 3.6×10-19 J
Or, 2.26ev

QUESTION: 5

Uniform electric and magnetic fields are produced pointing in the same direction. An electron is projected pointing in the same direction, then

Solution:

Electromagnetic force on electron will be zero V×B=0
Electrostatic force will be Fe​=−E backward, hence electron decelerate and velocity will decrease in magnitude.

QUESTION: 6

In which case is electron emission from a metal not known?

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QUESTION: 7

Photons can be

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QUESTION: 8

Given h = 6.6 ×10−34 joule sec, the momentum of each photon in a given radiation is 3.3 ×10−29 kg metre/sec. The frequency of radiation is

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QUESTION: 9

If the work function of a material is 2eV, then minimum frequency of light required to emit photo-electrons is

Solution:

Φ= hνλ => 2eV= 6.626 x 10-34 x ν

2 x 1.6 x 10-19= 6.626 x 10-34 x ν

On solving we get ν = 4.6 x 1014 Hz.

QUESTION: 10

In Thomson’s method for finding specific charge of positive rays, the electric and magnetic fields are

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QUESTION: 11

Photoelectric effect is

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QUESTION: 12

In a photon-particle collision (such as photon-electron collision) the quantity which is not conserved is

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QUESTION: 13

The specific charge for positive rays is much less than that for cathode rays. This is because

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QUESTION: 14

Photoelectric effect is possible

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QUESTION: 15

Davisson Germer experiment proves that

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QUESTION: 16

If the voltage across the electrodes of a cathode ray tube is 500 volts then energy gained by the electrons is

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QUESTION: 17

If work function of a metal plate is negligible then the K.E.of the photoelectrons emitted when radiations of 1000 Â are incident on the metal surface is

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QUESTION: 18

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential is

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QUESTION: 19

In Photoelectric effect

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QUESTION: 20

A photon is

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QUESTION: 21

If maximum velocity with which an electron can be emitted from a photo cell is 3.75×108cms−1 then stopping potential is

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QUESTION: 22

In an experiment of photoelectric emission for incident light of 4000 Â, the stopping potential is 2V. If the wavelength of incident light is made 3000 Â, then stopping potential will be

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QUESTION: 23

In the above experimental set up for studying photoelectric effect, if keeping the frequency of the incident radiation and the accelerating potential fixed, the intensity of light is varied, then

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QUESTION: 24

Photo-electric effect can be explained only by assuming that light

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QUESTION: 25

Wavelength of light incident on a photo cell is 3000 Â, if stopping potential is 2.5 volts, then work function of the cathode of photo cell is

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QUESTION: 26

in photoelectric effect, the photoelectric current

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QUESTION: 27

In various experiments on photo electricity the stopping potential for a given frequency of the incident radiation

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QUESTION: 28

In order to increase the kinetic energy of ejected photoelectrons, there should be an increase in

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QUESTION: 29

Each photon has the same speed but different

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QUESTION: 30

Number of ejected photoelectrons increases with increase

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