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QUESTION: 1

A particle of mass 1 kg and charge 1/3μC is projected towards a non conducting fixed spherical shell having the same charge uniformly distributed on its surface. The minimum initial velocity V_{0} of projection of particle required if the particle just grazes the shell is

Solution:

From conservation of angular momentum,

from conservation of energy,

QUESTION: 2

A uniform electric field 100 V/ m is directed vertically downwards. Find the change in potential energy of an electron whose height decreases by 0.5 m.

Solution:

Definition based

QUESTION: 3

Negative mutual potential energy corresponds to attraction between two charges

Solution:

Definition based

QUESTION: 4

The amount of work done in moving a charge from one point to another along an equipotential line or surface charge is

Solution:

Since Potential difference between two points in equipotential surfaces is zero, the work done between two points in equipotential surface is also zero.

QUESTION: 5

In bringing an electron towards another electron, the electrostatic potential energy of the system

Solution:

Definition based

QUESTION: 6

The potential energy of a system containing only one point charge is

Solution:

QUESTION: 7

A proton is accelerated from rest through a potential of 500 volts. Its final kinetic energy is

Solution:

K = qV

QUESTION: 8

The electrostatic potential energy between two charges q1 and q2 separated by a distance by r is given by

Solution:

We know that energy required/gained = force x displacement

As F = kqQ / r^{2} and displacement is r

We get U = kQq /r

Where k = 1/4ϵ

QUESTION: 9

What is the electrostatic potential energy of a system containing two charges 40 nC and 60 nC at a distance of 36 cm?

Solution:

Definition based

*Answer can only contain numeric values

QUESTION: 10

Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostaic energy of the configuration is zero, find the value Q\q is [Take √2 = 1.4]

Solution:

Net electrostatic energy of the configuration will be

Putting U = 0 we get,

-(2-√2) = -0.6

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