A particle of mass 1 kg and charge 1/3μC is projected towards a non conducting fixed spherical shell having the same charge uniformly distributed on its surface. The minimum initial velocity V0 of projection of particle required if the particle just grazes the shell is
From conservation of angular momentum,
from conservation of energy,
A uniform electric field 100 V/ m is directed vertically downwards. Find the change in potential energy of an electron whose height decreases by 0.5 m.
Negative mutual potential energy corresponds to attraction between two charges
The amount of work done in moving a charge from one point to another along an equipotential line or surface charge is
Since Potential difference between two points in equipotential surfaces is zero, the work done between two points in equipotential surface is also zero.
In bringing an electron towards another electron, the electrostatic potential energy of the system
The potential energy of a system containing only one point charge is
A proton is accelerated from rest through a potential of 500 volts. Its final kinetic energy is
K = qV
The electrostatic potential energy between two charges q1 and q2 separated by a distance by r is given by
We know that energy required/gained = force x displacement
As F = kqQ / r2 and displacement is r
We get U = kQq /r
Where k = 1/4ϵ
What is the electrostatic potential energy of a system containing two charges 40 nC and 60 nC at a distance of 36 cm?
Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostaic energy of the configuration is zero, find the value Q\q is [Take √2 = 1.4]
Net electrostatic energy of the configuration will be
Putting U = 0 we get,
-(2-√2) = -0.6