For any charge configuration, equipotential surface through a point is _____to the electric field at that point.
Two equipotential surfaces have a potential of -10V and 90V respectively, what is the difference in potential between these surfaces?
Potential = high potential - low potential
so our high potential is 90V and low potential is 10V,
potential = 90-(-10)=100V
Optical analogue of an equipotential surface is
Electric field is steepest in the direction in which the potential
In the direction of electric field the electric potential decreases. This is because electric potential is the work done against the direction of the electric field.
Equipotential surfaces cannot
The electric field lines are perpendicular to the equipotential surface. The field lines can not intersect each other because the electric force can not have two directions at a point.
The shape of equipotential surface for an infinite line charge is:
When a positive charge is moved in an electrostatic field from a point at high potential to a low potential, its kinetic energy
We can generalise it by assuming a positive charge moving away from another positive charge. now both of them are repelling each other with some force. so that positive charge will accelerate which results in the increase in K.E.
Shape of equipotential surfaces for a uniform electric field along x-axis are
The value of electric field vector along the surface of constant potential of 100 V
As we know that electric field is in the reverse sense of the directional gradient of electric potential, so if V is constant, E should be zero. So, for E to be zero, either V has to be zero, or constant, or the 3 directional derivative components of V must cancel out each other in space. So we can not claim that V always has to be zero, if E is zero in a region, since E is a vector & V is a scalar quantity. But if V is zero, then surely E has to be zero; the reverse case is not always true.
The amount of work done in moving a unit positive charge through distance of 10 cm on an equipotential surface is