Test: Power Electronics- 6
10 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Power Electronics- 6
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A single-phase voltage source square-wave inverter feeds pure inductive load. The waveform of the load current will be
A single-phase voltage source square-wave inverter feeds pure inductive load. The waveform of the load current will be triangular.
The output value e1 and e2 of two full bridge inverter are added using output transformer. In order to eliminate the 3rd harmonic from output voltage, the phase angle between e1 and e2 should be ______ degree.
It is possible when
3θ = π
θ = π/3
A single phase full bridge inverter is fed from a 48 V battery and is delivering power to a pure resistance load what is the value of fundaments output voltage?
Concept:
For single phase full bridge inverter
Calculation:
The RMS value of the fundamental voltage
A single phase full-bridge inverter, connected to 230 V dc source, feeds a resistive load 20 Ω find the average current of each SCR.
Concept:
In full-bridge inverter SCR conducts for 180° during one cycle of 360°
Average SCR current = 
and peak current of each thyristor = 
Calculation:
ITP = 230/20 = 11.5A
∴ Average current of each SCR = 
A single phase full bridge inverter feeds power to a load of R = 12 Ω and L = 0.04 H from a 400 V dc source. If the inverter operates the frequency of 50 Hz, determine the power delivered to load (in watt) for square wave operation. (Consider first and third harmonic).
RMS value of fundamental voltage is
Load impedance at fundamental frequency
RMS value of resultant.
A single phase full converter, connected 240 V, 50 Hz source, is feeding a load R = 10 Ω in series with a larger inductance that makes the load current ripple free. For a firing angle 30°, calculated R.M.S value of fundamental current (in A).
The R.M.S value of nth harmonic input current
R.M.S value of fundamental current
A single phase half bridge inverter is feeding power into a load of resistance 20 Ω, dc input to the inverter is 500V. Then the power factor is_____
RMS value of output voltage is, 
RMS value of load current is, 
Power delivered, 
Power factor, cosϕ = P/VI = 0.99
A single phase half bridge VSI has load R = 1.8 Ω and DC source voltage 130 – 0 – 130 V. Find the power delivered to the load due to fundamental current.
Vdc = 260 V
P01 = (65.023)2 (1.8)
= 7610.38 W
= 7.61 kW
A single phase full converter feeds power to RLE load. If one of the four SCR gets open circuited due to fault. Find the value of average load current (in A) for firing angle 40°.
A single phase half-bridge inverter, connected to 230 V dc source, feeds a resistive load of 15 Ω.
The Input power factor is
Inputpowerfactor = 
Fourier series of output voltage
RMS value of fundamental voltage
R.M.S value of fundamental current
Total R.M.S output voltage = 
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