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Test: Power Systems- 1 - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Power Systems- 1

Test: Power Systems- 1 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Power Systems- 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Power Systems- 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Power Systems- 1 below.
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Test: Power Systems- 1 - Question 1

Which of the following rotor is used in thermal power plants? 

Detailed Solution for Test: Power Systems- 1 - Question 1
  • Cylindrical rotor is also called as round rotor or smooth rotor, there is no projection, there a closed portion contain field winding which is distributed and unslotted portion also acts as poles .
  • It has large axial length and small diameter, resulting high peripheral speed.
  • As the air gap is uniform throughout the machine it is more suitable for high speed operation, employed in all thermal, nuclear power plants containing turbo alternators with two or maximum 4 poles only.
     
Test: Power Systems- 1 - Question 2

Galvanised steel is generally used as:

Detailed Solution for Test: Power Systems- 1 - Question 2
  • If the wires are made up with some other ordinary steels, rust and corrosion attacked the wire after some time due to the environmental wet conditions.
  • A layer of zinc oxide can be provided on the steel wire by some chemical process.
  • This zinc oxide layer protects the steel wire from the rust and corrosion effects. That’s why galvanized steel is used in many places.
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Test: Power Systems- 1 - Question 3

Which of the following is not the advantage of higher transmission voltage:

Detailed Solution for Test: Power Systems- 1 - Question 3

Advantages of higher transmission voltage are:

  1. Power transfer capability of the transmission line is increased
    Pmax = Vs*Vr/Xs
    Where, Vs = Supply voltage
    Vr = Receiving end voltage
    If Vs = Vr,
    Pmax ∝ Vs²
  2. Transmission line losses are reduced
    Power P = VI cosφ
    I = P/(V cosφ)
    Transmission line losses Pl = I²R
    Therefore, Transmission line losses Pl∝ 1/V²
  3. Area of cross section and volume of the conductor is reduced
    Resistance R = ρl/A
    Where, ρ= resistivity
    l = length of the conductor
    A = Area of cross section
    Therefore area A ∝ 1/V²
*Answer can only contain numeric values
Test: Power Systems- 1 - Question 4

In a hydroelectric plant, the available head is 80 m for a discharge 12m3/sec, and overall efficiency of the PowerStation of 80%. The specific weight of water is 9.81 k/m2. Then the power developed is – (in MW)


Detailed Solution for Test: Power Systems- 1 - Question 4

P = WQHη KW

= 9.81 × 12 × 80 × 0.8

= 7534.08 KW = 7.53 MW

Test: Power Systems- 1 - Question 5

Consider a power system with three identical generators. The transmission losses are negligible. One generator(G1) has a speed governor which maintains its speed constant at the rated value, while the other generators (G2 and G3) have governors with a drop of 5%. If the load of the system is increased, then in steady state.

Detailed Solution for Test: Power Systems- 1 - Question 5

Given power system with these identical generators G1 has Speed governor G2 and G3 has drop of 5% When load increased, in steady state generation of G1 is only increased while generation of G2 and G3 are unchanged.

*Answer can only contain numeric values
Test: Power Systems- 1 - Question 6

An industrial consumer has a daily load pattern of 2500 kW, 0.8 lag for 8 hours, 2000 kW, 0.6 lag for 8 hours and 1500 kW, unity power factor for 8 hours. What is the load factor?


Detailed Solution for Test: Power Systems- 1 - Question 6


 

= 48000/60000

= 0.8

*Answer can only contain numeric values
Test: Power Systems- 1 - Question 7

A generating station has the following data:

Installed capacity = 420 MW; capacity factor = 60%

Annual load factor = 70%.

The minimum reserve capacity of the station is – (in MW)


Detailed Solution for Test: Power Systems- 1 - Question 7


By above two equations,
Maximum demad = Installed capacity x 

Reserve capacity = Installed capacity − Maximum demand
= 420 – 360 = 60 MW

*Answer can only contain numeric values
Test: Power Systems- 1 - Question 8

Determine the incremental cost of received power of the plant shown in the figure below, if the incremental cost of production is  ________ 


Detailed Solution for Test: Power Systems- 1 - Question 8

Penalty Factor = 20/15 = 4/3

Cost of received power = 

*Answer can only contain numeric values
Test: Power Systems- 1 - Question 9

A steam power station spends Rs. 30 lakhs per annum for coal used in the station. The coal has a calorific value of 5000 kcal/kg and costs Rs. 300 per ton. If the station has thermal efficiency of 33% and electrical efficiency of 90%, find the average load on the station. (in kW) 


Detailed Solution for Test: Power Systems- 1 - Question 9

Overall efficiency, ηoverall = 0.33 × 0.9 = 0.297
Coal used/annum = 
Heat of combustion = coal used/annum × calorific value

= 107 × 5000 = 5 × 1010 kcal

Heat output = ηoverall × heat of combustion

= (0.297) × (5 × 1010) = 1485 × 107 kcal
Units generated per annum = 
Average load on station = 

Test: Power Systems- 1 - Question 10

 Which of the following statement is true?

Detailed Solution for Test: Power Systems- 1 - Question 10

At higher voltage, volume of conductor is reduced.

Area of conductor A ∝ 1/Vs²
Where Vs = Supply voltage

So that material requirement is reduced and hence cost of the material and transmission is reduced.

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