Test: Sinusoidal Steady State Analysis
20 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Sinusoidal Steady State Analysis
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In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66sin (10 t) V, i(t) = 2.3sin (103t + 68.3o) A.The nature of the elements would be
R-Ccauses a positive phase shift in voltage
10 sin (t + 30°) = 10 cos (t - 60°)
Let Vo be the voltage across current source
Vo(20 + j10) - (20 + j40) Vx = j600
Determine the complex power for hte given values in question.
P = 269 W, Q = 150 VAR (capacitive)
S = P-jQ = 269-j150 VA
Determine the complex power for hte given valuesin question.
Q = 2000 VAR, pf =09. (leading)
pf = cos θ = 0.9 ⇒ θ = 25.84°
Q = S sin θ ⇒ 
Determine the complex power for hte given values in question.
S = 60 VA, Q = 45 VAR (inductive)
Q = S sin θ ⇒ 
Determine the complex power for hte given values in question.
Vrms = 220 V, P = 1 kW, |Z| = 40Ω (inductive)
= 0.8264 or θ = 34.26°,
Determine the complex power for hte given values in question
Vrms = 21∠20°V, Vrms = 21∠20°V, Irms = 8.5∠-50°A
S = Vrms I*rms = (21∠20°)(8.5∠50°)
= 61+j167.7VA
Determine the complex power for hte given values in question.
Vrms = 120∠30°V, Z = 40 + j80Ω
= 72 + j144 VA
In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be
A relay coil is connected to a 210 V, 50 Hz supply. If it has resistance of 30Ω and an inductance of 0.5 H, the apparent power is
Z= 30 + j(0.5)(2π)(50) = 30 + j157,
Apparent power 
= 275.6 VA
In the circuit shown in fig. power factor is
= 4 - j6 = 7.21∠ - 56.31°, pf = cos 56.31° = 0.555 leading
The power factor seen by the voltage source is
I1 = 1∠36.9°
pf = cos 36.9° = 0.8 leading
The average power supplied by the dependent source is
(2∠ - 90°)4.8 = -Ix (4.8 + j1.92) + 0.6Ix(8)
Ix = 5∠0°, Va = 0.6 x 5 x 8 = 24∠0°,
In the circuit of fig. the maximum power absorbed by ZL is
The value of the load impedance, that would absorbs the maximum average power is
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