Test: Time Response - Electrical Engineering (EE) MCQ

# Test: Time Response - Electrical Engineering (EE) MCQ

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## 20 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Time Response

Test: Time Response for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Time Response questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Time Response MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Time Response below.
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Test: Time Response - Question 1

### The open-loop transfer function of a ufb control system is The position, velocity and acceleration error constants are respectively

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Test: Time Response - Question 2

### The open-loop transfer function of a unit feedback system is The position, velocity and acceleration errorconstants are respectively

Detailed Solution for Test: Time Response - Question 2

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Test: Time Response - Question 3

### If a type 0 system is subjected to step input, what is its effect on steady state error?

Test: Time Response - Question 4

The forward-path transfer function of a unity negative feedback system is given by:

The value of K which will place both the poles of the closed-loop system at the same location is.​​​​

Detailed Solution for Test: Time Response - Question 4

Concept:

Poles of closed-loop system = zeroes of the characteristic equation.

Characteristic equation is given by:

1 + G(s) H(s) = 0

(s + 2) (s – 1) + K = 0

s2 + s – 2 + k = 0

s2 + s + (k – 2) = 0

Given that the poles of closed system ‘or’ we can say zeroes of the characteristic equation are at same location. This indicates that the roots of the characteristic equation will be real, i.e.

b2 – 4ac = 0

Here, b = 1, a = 1 and c = k – 2

b2 – 4ac = 1 – 4(1) (k -2) = 0

1 – 4 (k - 2) = 0

1 – 4k + 8 = 0

4k = 9

K = 2.25

Test: Time Response - Question 5

For the system shown in fig.the steady state error component due to unit step disturbance is 0.000012 and steady state error component due to unit ramp input is 0.003. The values of K1 and K2 are respectively

Detailed Solution for Test: Time Response - Question 5

If R (s) = 0

Error in output due to disturbance

Error due to ramp input

Test: Time Response - Question 6

The transfer function for a single loop nonunity feedback control system is

The steady state error due to unit step input is

Detailed Solution for Test: Time Response - Question 6

E(s) = R(s) - C(s) H(s)

Test: Time Response - Question 7

For the system of fig. the total steady state error due to a unit step input and a unit step disturbance is

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where  and

Test: Time Response - Question 8

The forward path transfer function of a ufb system is

If a unit ramp is applied, the minimum possiblesteady-state error is

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Using Routh-Hurwitz Criterion, system is stable for 0 < K < 2000

Test: Time Response - Question 9

The forward-path transfer function of a ufb system is

The system has r(t) = t3 applied to its input. Thesteady state error is

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Test: Time Response - Question 10

Consider a unity feedback system with forward transfer function given by

The steady-state error in the output of the system for a unit-step input is _________ (up to 2 decimal places).

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Test: Time Response - Question 11

A system has position error constant Kp  = 3. The steady state error for input of 8tu(t) is

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System is zero type

Test: Time Response - Question 12

The forward path transfer function of a unity feedback system is

For input of 60u(t) steady state error is

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Test: Time Response - Question 13

For ufb system shown in fig. the transfer function is

If input is 30t2 , then steady state error is

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Test: Time Response - Question 14

The forward-path transfer function of a ufb control system is

The steady state errors for the test input 37tu(t) is

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Test: Time Response - Question 15

In the system shown in fig. r(t) =  1 + 2t , t > 0. The steady state error e(t) is equal to

Detailed Solution for Test: Time Response - Question 15

The system is type 2. Thus to step and ramp input error will be zero.

Test: Time Response - Question 16

A ufb control system has a forward path transfer function

If the system is subjected to an input r(t) = 1 + t + 1/2 t2 , t > 0the steady state error of the system will be

Detailed Solution for Test: Time Response - Question 16

Explanation : R(s) = (1/s)+(1/s2) + (1/s3)

E(s) = R(s) / {1 + G(s)} = 1/10s

ess = lim sE(s) = 0.1

Test: Time Response - Question 17

The system shown in fig. has steady-state error 0.1 to unit step input. The value of K is

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Test: Time Response - Question 18

Block diagram of a position control system is shown in fig.

If Kt = 0 and Ka= 5, then the steady state error tounit ramp input is

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Test: Time Response - Question 19

Block diagram of a position control system is shown in fig.

If the damping ratio of the system is increased to 0.7 without affecting the steady state error, then thevalue of Ka and Kt are

Detailed Solution for Test: Time Response - Question 19

The equivalent open-loop transfer function

Test: Time Response - Question 20

A system has the following transfer function

The type and order of the system are respectively

Detailed Solution for Test: Time Response - Question 20

The s has power of 4 and denominator has order of 7. So Type 4 and Order 7.

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## GATE Electrical Engineering (EE) Mock Test Series 2025

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