1 Crore+ students have signed up on EduRev. Have you? 
Applying the nodal analysis
v_{a }= 2(3+1) + 3(1) =11V
sing Thevenin equivalent and source transform
75 = 90ki_{1}+ 10k(i_{1}  7.5m)
150 = 100ki_{1} = i_{1} = 1.5 mA
3 = 2i_{1} + 3(i_{1}  4)
i_{1} = 3 A
45 = 2ki_{1} + 500(i_{1} + 15m)
= i_{1} = 15 mA
6.6 = 50i_{1} + 100(i_{1} + 0.1) + 40(i_{1}  0.06) + 60(i_{1}  0.1) i_{1} = 0.02 A
For the circuit of Fig. the value of v_{s} , that will result in v_{1} = 0, is
If v_{1} = 0, the dependent source is a short circuit
i_{x} = i_{1}  i_{2}
15 = 4i_{1} 2(i_{1}  i_{2}) + 6(i_{1}  i_{2})
⇒ 8i_{1}  4i_{2} = 15 ..........(i)
18 = 2i_{2} + 6(i_{2} i_{1})
⇒ 3i_{1} 4i_{2} = 9 ..........(ii)
i_{1} =1.2 A, i_{2} = 1.35 A
14 = 3i_{1} + v_{y} + 6 (i_{1}  2  7) + 2v_{y} + 2(i_{1} 7)
v_{y} = 3(i_{1}  2)
14 = 3i_{1} +9(i_{1}  2)+ 6(i_{1}  9)+2(i_{1} 7)
14 = 20i_{1} 18  54  14 ⇒ i_{1} = 5 A
v_{1} = 6(5  2  7) + 2 x 3(5  2)+2(5  7) = 10 V
Let i_{1} and i_{2} be two loop current
21 docs222 tests

Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 
21 docs222 tests









