Test: Method of Analysis


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15 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Method of Analysis

Test: Method of Analysis for Railways 2022 is part of GATE Electrical Engineering (EE) 2023 Mock Test Series preparation. The Test: Method of Analysis questions and answers have been prepared according to the Railways exam syllabus.The Test: Method of Analysis MCQs are made for Railways 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Method of Analysis below.
Solutions of Test: Method of Analysis questions in English are available as part of our GATE Electrical Engineering (EE) 2023 Mock Test Series for Railways & Test: Method of Analysis solutions in Hindi for GATE Electrical Engineering (EE) 2023 Mock Test Series course. Download more important topics, notes, lectures and mock test series for Railways Exam by signing up for free. Attempt Test: Method of Analysis | 15 questions in 45 minutes | Mock test for Railways preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) 2023 Mock Test Series for Railways Exam | Download free PDF with solutions
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Test: Method of Analysis - Question 1

v1 = ?

Detailed Solution for Test: Method of Analysis - Question 1

Applying the nodal analysis

Test: Method of Analysis - Question 2

va = ?

Detailed Solution for Test: Method of Analysis - Question 2

v= 2(3+1) + 3(1) =11V

Test: Method of Analysis - Question 3

v1 = ?

Detailed Solution for Test: Method of Analysis - Question 3

Test: Method of Analysis - Question 4

va = ?

Detailed Solution for Test: Method of Analysis - Question 4

Test: Method of Analysis - Question 5

v2 = ?

Detailed Solution for Test: Method of Analysis - Question 5

Test: Method of Analysis - Question 6

ib = ?

Detailed Solution for Test: Method of Analysis - Question 6

Test: Method of Analysis - Question 7

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 7

sing Thevenin equivalent and source transform

Test: Method of Analysis - Question 8

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 8

75 = 90ki1+ 10k(i1 - 7.5m)

150 = 100ki1 = i1 = 1.5 mA

Test: Method of Analysis - Question 9

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 9

3 = 2i1 + 3(i1 - 4) 

i1 = 3 A

Test: Method of Analysis - Question 10

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 10

45 = 2ki1 + 500(i1 + 15m)

= i1 = 15 mA

Test: Method of Analysis - Question 11

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 11

6.6 = 50i1 + 100(i1 + 0.1) + 40(i1 - 0.06) + 60(i1 - 0.1) i1 = 0.02 A

Test: Method of Analysis - Question 12

For the circuit of Fig. the value of vs , that will result in v1 = 0, is

Detailed Solution for Test: Method of Analysis - Question 12

If v1 = 0, the dependent source is a short circuit
 

Test: Method of Analysis - Question 13

i1 , i2 = ?

Detailed Solution for Test: Method of Analysis - Question 13

ix = i1 - i2
15 = 4i1 -2(i1 - i2) + 6(i1 - i2)
⇒ 8i1 - 4i2 = 15   ..........(i)
-18 = 2i2 + 6(i2 -i1)
⇒ 3i1 -4i2 = 9    ..........(ii)
i1 =1.2 A, i2 = -1.35 A 

Test: Method of Analysis - Question 14

v1 = ?

Detailed Solution for Test: Method of Analysis - Question 14

14 = 3i1 + vy + 6 (i1 - 2 - 7) + 2vy + 2(i1 -7)
vy = 3(i1 - 2)
14 = 3i1 +9(i1 - 2)+ 6(i1 - 9)+2(i1 -7)
14 = 20i1 -18 - 54 - 14 ⇒ i1 = 5 A
v1 = 6(5 - 2 - 7) + 2 x 3(5 - 2)+2(5 - 7) = -10 V 

Test: Method of Analysis - Question 15

vx = ?

Detailed Solution for Test: Method of Analysis - Question 15

Let i1 and i2 be two loop current

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