Computer Science Engineering (CSE) > GATE Computer Science Engineering(CSE) 2023 Mock Test Series > Test: Engineering Mathematics- 4
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Test: Engineering Mathematics- 4
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10 Questions MCQ Test GATE Computer Science Engineering(CSE) 2023 Mock Test Series | Test: Engineering Mathematics- 4
Test: Engineering Mathematics- 4 for Computer Science Engineering (CSE) 2023 is part of GATE Computer Science Engineering(CSE) 2023 Mock Test Series preparation. The Test: Engineering Mathematics- 4 questions and answers have been
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Detailed Solution for Test: Engineering Mathematics- 4 - Question 1
Since the limit from the left does not equal to the limit from the right. So limit does not exist.
Test: Engineering Mathematics- 4 - Question 2
If f(x) is continuous at x = 0 where
then what is the value of k?
then what is the value of k?
Detailed Solution for Test: Engineering Mathematics- 4 - Question 2
Since given function is continuous at x = 0
Alternate method:
0/0 form using L Hospital’s
Test: Engineering Mathematics- 4 - Question 3
If f(x) is continuous at x = 0 where
then what is the value of k?
then what is the value of k?
Detailed Solution for Test: Engineering Mathematics- 4 - Question 3
f(x) is continuous at x = 0
By definition of logarithm
k ≠ -4
∴ k = 4
Alternate method using L Hospital's
2logk = log (16)
2logk = 2log (4)
∴ k = 4
*Answer can only contain numeric values
will be ______
Detailed Solution for Test: Engineering Mathematics- 4 - Question 4
= 1
Detailed Solution for Test: Engineering Mathematics- 4 - Question 5
Detailed Solution for Test: Engineering Mathematics- 4 - Question 6
Applying L-Hospital Rule
Since the limit is of the form 0/0
Therefore, 
*Answer can only contain numeric values
Find ln p
Detailed Solution for Test: Engineering Mathematics- 4 - Question 7
Concept:
Detailed Solution for Test: Engineering Mathematics- 4 - Question 8
Alternate method: Using L Hospital’s
Detailed Solution for Test: Engineering Mathematics- 4 - Question 9
Detailed Solution for Test: Engineering Mathematics- 4 - Question 10
Substituting x = ∞
It is of the form 1∞
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