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Fun(2)

2*fun(3)

2*fun(4)

4 After tree evaluation we get 16
So, C is the correct answer
Consider the following recursive function fun(x, y). What is the value of fun(4, 3)
The function fun() calculates and returns ((1 + 2 … + x1 + x) +y) which is x(x+1)/2 + y.
The function mainly prints binary representation in reverse order.
The function adds x to itself y times which is x*y.
The function multiplies x to itself y times which is x^{y}.
Consider the following recursive C function that takes two arguments
unsigned int foo(unsigned int n, unsigned int r){
if(n >0) return (n%r + foo (n/r, r));
else return 0;
}
Q.
What is the return value of the function foo when it is called as foo(345, 10) ?
The call foo(345, 10) returns sum of decimal digits (because r is 10) in the number n. Sum of digits for 345 is 3 + 4 + 5 = 12.
Consider the same recursive C function that takes two arguments
Q. What is the return value of the function foo when it is called as foo(513, 2)?
foo(513, 2) will return 1 + foo(256, 2). All subsequent recursive calls (including foo(256, 2)) will return 0 + foo(n/2, 2) except the last call foo(1, 2). The last call foo(1, 2) returns 1. So, the value returned by foo(513, 2) is 1 + 0 + 0…. + 0 + 1. The function foo(n, 2) basically returns sum of bits (or count of set bits) in the number n.
f() is a recursive function which adds f(a+1, n1) to *a if *a is even. If *a is odd then f() subtracts f(a+1, n1) from *a. See below recursion tree for execution of f(a, 6).
So, the final returned value is 12 + (7 – (13 – (4 + (11 – (6 + 0))))) = 15
Consider the following code snippet:
What will happen when the above snippet is executed?
Every function call is stored in the stack memory. In this case, there is no terminating condition(base case). So, my_recursive_function() will be called continuously till the stack overflows and there is no more space to store the function calls. At this point of time, the program will stop abruptly.
Consider the C function given below.
Q. Which one of the following is TRUE?
When j is 50, the function would call itself again and again as neither i nor j is changed inside the recursion.
Consider the following C function:
The value returned by f(1) is
Consider the following C function.
Q. The return value of fun(5) is __________.
Consider the following recursive C function. If get(6) function is being called in main() then how many times will the get() function be invoked before returning to the main()?
count(3) will print value of n and d. So 3 1 will be printed and d will become 2.
Then count(2) will be called. It will print value of n and d.
So 2 2 will be printed and d will become 3.
Then count(1) will be called. It will print value of n and d.
So 1 3 will be printed and d will become 4.
Now count(1) will print value of d which is 4. count(1) will finish its execution.
Then count(2) will print value of d which is 4.
Similarly, count(3) will print value of d which is 4.
So series will be A.
The function f is defined as follows:
Assuming that arbitrarily large integers can be passed as a parameter to the function, consider the following statements.
1. The function f terminates for finitely many different values of n ≥ 1.
ii. The function f terminates for infinitely many different values of n ≥ 1.
iii. The function f does not terminate for finitely many different values of n ≥ 1.
iv. The function f does not terminate for infinitely many different values of n ≥ 1.
Which one of the following options is true of the above?
The function terminates for all values having a factor of 2 {(2.x)2==0}
So, (i) is false and (ii) is TRUE.
Let n = 3, it will terminate in 2nd iteration.
Let n=5, it will go like 5  14  7  20  10  5 – and now it will repeat.
And any number with a factor of 5 and 2, there are infinite recursions possible.
So, (iv) is TRUE and (iii) is false.
150 docs215 tests

150 docs215 tests
