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This mock test of Number System - MCQ 5 for Quant helps you for every Quant entrance exam.
This contains 20 Multiple Choice Questions for Quant Number System - MCQ 5 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

What is the number if 60% of it added to 60 gives the number itself ?

Solution:

From ans…150

40% of numb = 60

60% of 150 = 90

90+60 = 150

QUESTION: 2

(6084)^{1/2} = ?

Solution:

QUESTION: 3

9/16 of a number is 51 greater than 50% of the number, then the number is

Solution:

(9x/16)-(x/2) = 51

X = 51*16 = 816

QUESTION: 4

The sum of the number and its square is 1406. What is the number ?

Solution:

See the last digit 06…..go for 7

Last digit ..37+(37*37) = 7+49 = 16

So ans: 37

QUESTION: 5

The number is 0.01 is how many times as great as the number (0.0001)^{2} ?

Solution:

0.01 = 10^{-2}

(0.0001)^{2} = 10^{-8}

10^{-2}/10^{-8} = 10^{6}

QUESTION: 6

In a bag there are coins of 25 paise and 10 paise in the ratio of 5:16. If the bag contains Rs.16 then the number of 10 paise coin is

Solution:

25*5+10*16 = 285

Rs 16 = 1600

No of 10p = 1600*16/285 = 89.82 = 90

QUESTION: 7

a+b = c and abc = 30, then what is the value of a^{3} + b^{3 }– c^{3 }?

Solution:

a^{3} + b^{3} – c^{3} = -3(abc) = -3(30) = -90

QUESTION: 8

a^{2} + b^{2} + c^{2} = ab + bc + ca then the value of (a+b)/(b+c) is

Solution:

Equation will be satisfied when a=b=c=1

(a+b)/c = (1+1)/(1+1) = 2/2 = 1

QUESTION: 9

(a-b) = 1, (b-c) = 2 and (c-a) = 3 then the value of (a^{3} +b^{3} +c^{3} -3abc)/(a+b+c) is

Solution:

(a^{3} +b^{3} +c^{3} -3abc)/(a+b+c) =1/2[(a-b) ^{2}+(b-c)^{2} +(c-a)^{2}] = ½(1+4+9) = 14/2 = 7

QUESTION: 10

If *=+, /=-, + = *, – = / then 43*561+500-100/10 = ?

Solution:

43*561+500-100/10 = 43+561*500/100-10 = 43+561*5-10

= 43+2805-10 =2838

QUESTION: 11

Two third of a positive number and 25/216 of its reciprocal are equal.The number is

Solution:

(2/3)x = (25/216)(1/x)

X^{2} = (25×3)/(216×2) = 25/144

X = 5/12

QUESTION: 12

If 2(1/2) is added to a number and the sum multiplied by 4(1/2)and 3 is added to the product and then divide the sum by 1(1/5), the quotient becomes 25 .What is the number ?

Solution:

{4(1/2)[X+2(1/2)]+3}/[1(1/5)] = 25

(9X/2)+(45/4)+3 = 25×(6/5)

9X/2 =63/4 X=7/2 or 3(1/2)

QUESTION: 13

In a division sum ,the divisor is 3 times the quotient and 6 times the remainder.If the remainder is 2 then the dividend is

Solution:

Divident = Quotient × Divisor +Remainder

Divisor = 6×2 = 12

Q = 12/3 = 4

Divident = 4×12+3 =48+2 = 50

QUESTION: 14

The sum of two number is 24.The greatest product of these two numbers can be

Solution:

X + Y = 24

Greatest Product then x and y must be equal

Possibility of getting 24 12+12= 24

12×12 = 144

QUESTION: 15

Twenty times a positive integer is less than its square by 96.What is the integer ?

Solution:

X^{2} – 20X = 96

X^{2}-20X-96 = 0

(X-24)(X+4) = 0

X= 24, -4

positive integer = 24

QUESTION: 16

If (a-b) 3, (b-c) = 5 and (c-a) = 1 then the value of (a^{3}+b^{3}+c^{3}- 3abc)/(a+b+c)

Solution:

QUESTION: 17

The product of the 2 consecutive odd number is 6723.What is the greater number ?

Solution:

X ×(X+2) = 6723

X^{2} + 2X = 6723

X^{2}+2X-6723 = 0

(X – 81)(X+83) = 0

Greatest number = 83

QUESTION: 18

The sum of three number is 264. If the first number be twice the second and third number be one third of the first then the second number is

Solution:

2X+X+(2X/3) = 264

(6X+3X+2X)/3 = 264

11X/3 = 264

X= (264×3)/11 = 72

QUESTION: 19

If the number obtained on interchanging the digits of a 2 digit number is 18 more than the original number and the sum of the digit is 8.Then what is the original number?

Solution:

Unit digit= x ; Ten’s digit = (8-x)

[10(8-x)+x] – [10x+(8-x)] = 18

80-10x+x-10x-8+x = 18

-18x = 18-80+8

18x = 54

X = 54/18 = 3

8 – x = 8 – 3 = 5

Hence the number is 35

QUESTION: 20

The sum of three consecutive multiple of 4 is 72 .What is the largest number ?

Solution:

4x+(4x+4)+(4x+8) = 72

12x+12 = 72

X=(72-12)/12

X=5

Largest number = 4(5)+8 = 20+8 = 28

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