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Percentage - MCQ 2 - Mechanical Engineering MCQ


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20 Questions MCQ Test General Aptitude for GATE - Percentage - MCQ 2

Percentage - MCQ 2 for Mechanical Engineering 2024 is part of General Aptitude for GATE preparation. The Percentage - MCQ 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Percentage - MCQ 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Percentage - MCQ 2 below.
Solutions of Percentage - MCQ 2 questions in English are available as part of our General Aptitude for GATE for Mechanical Engineering & Percentage - MCQ 2 solutions in Hindi for General Aptitude for GATE course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt Percentage - MCQ 2 | 20 questions in 40 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study General Aptitude for GATE for Mechanical Engineering Exam | Download free PDF with solutions
Percentage - MCQ 2 - Question 1

In an election contested by two parties A and B, party A secured 25 percent of the total votes more than Party B. If party B gets 15000 votes. By how much votes does party B loses the election?

Detailed Solution for Percentage - MCQ 2 - Question 1

Let total votes = T and party B gets 15000 votes then party A will get T -15000 votes
T – 15000 – 15000 = 25T/100
T = 40000, so A get 25000 and B gets 15000 votes, so difference = 10000

Percentage - MCQ 2 - Question 2

A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

Detailed Solution for Percentage - MCQ 2 - Question 2

Let total apples be 100
first day he throws = 50*20/100 = 10 apples
next day he throws = 40*40/100 = 16 apples
so total = 26

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Percentage - MCQ 2 - Question 3

40% of the women are above 30 years of age and 80 percent of the women are less than or equal to 50 years of age. 20 percent of all women play basketball. If 30 percent of the women above the age of 50 plays basketball, what percent of players are less than or equal to 50 years?

Detailed Solution for Percentage - MCQ 2 - Question 3

take total women =100
Women less than or equal to 50 years = 80 and women above 50 years = 20
20 = women plays basketball
30% of the women above 50 plays basketball = 6
So remaining 14 women who plays basketball are less than or equal to 50 years
So (14/20)*100 = 70%

Percentage - MCQ 2 - Question 4

Alisha goes to a supermarket and bought things worth rupees 60, out of which 40 paise went on sales tax. If the tax rate is 10 percent, then what was the cost of tax free items?

Detailed Solution for Percentage - MCQ 2 - Question 4

tax = 40/100 = (10/100)*T, T = 4
so cost of tax free items = 60 – 4 – 0.40 = 55.60

Percentage - MCQ 2 - Question 5

60 percent of the employees of a company are women and 75% of the women earn 20000 or more in a month. Total number of employees who earns more than 20000 per month in the company is 60 percent of the total employees. What fraction of men earns less than 20000 per month?

Detailed Solution for Percentage - MCQ 2 - Question 5

let total employees are 100
males = 40 and females = 60 (45 women earns more than 20000)
total 60 employee earns more than 20000 per month, so number of males earns more than 20000 is 15
so fraction = 25/40 = 5/8

Percentage - MCQ 2 - Question 6

In a library, 30% of the books are in History. 50% of the remaining are in English and 40% of the remaining are in German. The remaining 4200 books are in regional languages. What is the total number of books in library?

Detailed Solution for Percentage - MCQ 2 - Question 6

(70/100)*T*(50/100)*(60/100) = 4200

Percentage - MCQ 2 - Question 7

A got 30% of the maximum marks in an examination and failed by 10 marks. However, B who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?

Detailed Solution for Percentage - MCQ 2 - Question 7

(30/100)*T = P -10
(40/100)*T = P + 15
U will get P = 85

Percentage - MCQ 2 - Question 8

The population of a town is 15000. It increases by 10 percent in the first year and 20 percent in the second year. But in the third year it decreases by 10 percent. What will be the population after 3 years.

Detailed Solution for Percentage - MCQ 2 - Question 8

15000*(11/10)*(12/10)*(9/10) = 17820

Percentage - MCQ 2 - Question 9

30 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol?

Detailed Solution for Percentage - MCQ 2 - Question 9

alcohol = 30*2/5 = 12 and water = 18 litres 
(12 + x)/(30 +x) = 60/100, we will get x = 15

Percentage - MCQ 2 - Question 10

2000 sweets need to be distributed equally among the school students in such a way that each student gets sweet equal to 20% of total students. Then the number of sweets, each student gets.

Detailed Solution for Percentage - MCQ 2 - Question 10

(20/100)*t*t = 2000 (total students = t)

Percentage - MCQ 2 - Question 11

A reduction of 20% percent in the price of rice enables a housewife to buy 5 kg more for rupees 1200. The reduced price per kg of rice.

Detailed Solution for Percentage - MCQ 2 - Question 11

let original price is x rupees per kg
1200/(4x/5) – 1200/x = 5
We will get x = 60, so reduced price = (4*60)/5 = 48

Percentage - MCQ 2 - Question 12

The population of a village has increased annually at the rate of 20%. If at the end of 3 years it is 21600, the population in the beginning of the first year?

Detailed Solution for Percentage - MCQ 2 - Question 12

21600 = P*(1 + 20/100)3

Percentage - MCQ 2 - Question 13

12 percent of the voters in an election did not cast their votes. In this election there are only two candidates. The winner by obtaining 45% of the total votes and defeated his rival by 2000 votes. The total number of votes in the election.

Detailed Solution for Percentage - MCQ 2 - Question 13

12% percent didn’t cast their vote. 45% of total votes get by the winning candidates, so remaining 43% will be scored by his rival. So,
(45/100 -43/100)*P = 2000
P = 100000

Percentage - MCQ 2 - Question 14

A number is first decreased by 25%. The decreased number is then increased by 20%. The resulting number is less than the original number by 40. Then the original number is –

Detailed Solution for Percentage - MCQ 2 - Question 14

Let the number is a
a – (75/100)*a*(120/100) = 40
we will get a = 400

Percentage - MCQ 2 - Question 15

The number of seats in a cinema hall is decreased by 8% and also the price of the ticket is increased by 4 percent. What is the effect on the revenue collected?

Detailed Solution for Percentage - MCQ 2 - Question 15

Let initially seats are 100 and price of each seat is 100, so total initial revenue = 10000
now, seats are 92 and price of each seat = 104, so total revenue = 92*104 = 9568
so percent change in revenue = (432/10000)*100 = 4.32 decrease

Percentage - MCQ 2 - Question 16

A man spends 60% of his income. His income is increased by 20% and his expenditure also increases by 10%. Find the percentage decrease in his saving?

Detailed Solution for Percentage - MCQ 2 - Question 16

Let initially income is 100. So, expenditure = 60 and saving = 40
now income is increased by 20% i.e. 120. So, expenditure = (70/100)*120 = 84 and saving = 36
so % percent decrease in saving = (4/40)*100 = 10%

Percentage - MCQ 2 - Question 17

Weights of two friends A and B are in the ratio of 1:2. A’s weight increases by 20% and the total weight of A and B together becomes 60 kg, with an increase of 30%. By what percent the weight of B increase?

Detailed Solution for Percentage - MCQ 2 - Question 17

weight of A is x and weight of B is 2x
given that 60 kg weight is the 30% percent increase of the original weight, so
(130/100)*W = 60, W = 600/13 kg (W = original weight)
X + 2x = 600/13, x = 200/13
So weight of A = 200/13 and of B = 400/13
(120/100)*(200/13) + [(100 + a)/100]*(400/13) = 60
Solve for a. We will get a = 35%

Percentage - MCQ 2 - Question 18

The marked price of an article is 20% higher than the cost price. A discount of 20% is given on the marked price. In this transaction the seller.

Detailed Solution for Percentage - MCQ 2 - Question 18

let cost price = 100 so, marked price = 120
now discount of 20% is given, so sp = 120*80/100 = 96
so % loss = (4/100)*100 = 4 percent

Percentage - MCQ 2 - Question 19

When the price of rice is increased by 30 percent, a family reduces its consumption such that the expenditure is only 20 percent more than before. If 50 kg of rice is consumed by family before, then find the new consumption of family (approx.)

Detailed Solution for Percentage - MCQ 2 - Question 19

Suppose initially price per kg of rice is 100 then their expenditure is 5000.
Now their expenditure is only increased by only 20% i.e – 6000.
Increased price of rice = 130.
So new consumption = 6000/130 = 46

Percentage - MCQ 2 - Question 20

A man has 4000 rupees in his account two years ago. In the first year he deposited 20 percent of the amount in his account. In the next year he deposited 10 percent of the increased amount in the account. Find the total amount in the account of the person after 2 years.

Detailed Solution for Percentage - MCQ 2 - Question 20

4000 + 800 + 480 = 5280

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