Probability - MCQ 5 - Banking Exams MCQ

# Probability - MCQ 5 - Banking Exams MCQ

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## 20 Questions MCQ Test Quantitative Aptitude for Competitive Examinations - Probability - MCQ 5

Probability - MCQ 5 for Banking Exams 2024 is part of Quantitative Aptitude for Competitive Examinations preparation. The Probability - MCQ 5 questions and answers have been prepared according to the Banking Exams exam syllabus.The Probability - MCQ 5 MCQs are made for Banking Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Probability - MCQ 5 below.
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Probability - MCQ 5 - Question 1

### The probability of two persons of passing the interview are 1/3 and 3/5. Then calculate the probability that only one of them pass the interview ?

Detailed Solution for Probability - MCQ 5 - Question 1

(P = pass, F = fail)
ApassBfail + AfailBpass
PF + FP
1/3*2/5 + 2/3*3/5 = 8/15

Probability - MCQ 5 - Question 2

### Among a group of 5 boys and 6 girls, 4 members is to be selected for an event. Find the probability that at least one boy is selected ?

Detailed Solution for Probability - MCQ 5 - Question 2

we can solve this by calculating the probability of the opposite event (no boys selected) and subtracting it from 1 (since probabilities of all events must sum to 1).

Here's how:

Step 1: Probability of no boys selected (unfavorable event)

• We can choose 4 girls out of 6 girls in ⁶C₄ ways (combinations, order doesn't matter).
• The total number of ways to choose 4 members from 11 (5 boys + 6 girls) is ¹¹C₄ ways.

Probability (no boys) = Favorable cases (girls only) / Total cases = ⁶C₄ / ¹¹C₄

Step 2: Probability of at least one boy (favorable event)

Probability (at least one boy) = 1 - Probability (no boys)

Calculation:

⁶C₄ = (6 * 5 * 4 * 3) / (4 * 3 * 2 * 1) = 15 ¹¹C₄ = (11 * 10 * 9 * 8) / (4 * 3 * 2 * 1) = 330

Probability (no boys) = 15 / 330 = 1/22

Probability (at least one boy) = 1 - (1/22) = 21/22

Therefore, the probability that at least one boy is selected is 21/22.

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Probability - MCQ 5 - Question 3

### The probability that the problem will be solved by three persons are 1/2, 1/3 and 1/6. Find the probability that the problem is solved ?

Detailed Solution for Probability - MCQ 5 - Question 3

1 – 1/2*2/3*5/6 = 13/18

Probability - MCQ 5 - Question 4

A urn contains 4 red balls, 5 green balls and 6 white balls, If one ball is drawn at random, find the probability that it is neither red nor white ?

Detailed Solution for Probability - MCQ 5 - Question 4

Total Number of balls = 4 +5 +6 =15 balls
neither red nor white
means it is Green
so P = no of green ball / Total Number of Balls
P = 5/15 = 1/3

Probability - MCQ 5 - Question 5

An elevator starts with 4 passenger and stops at 7 floors of an apartment. Find the probability that all 4 passengers travel to different floor ?

Detailed Solution for Probability - MCQ 5 - Question 5

Total number of outcomes = 7*7*7*7
Favourable outcome = 7*6*5*4
P = (7*6*5*4)/7*7*7*7 = 120/343

Probability - MCQ 5 - Question 6

A five digit number is formed from the numbers 1,3,5,7,8 and 9 without repeating the numbers. Find the probability that the number is divisible by 5 ?

Detailed Solution for Probability - MCQ 5 - Question 6

Total number of outcome = 6*5*4*3*2
Favourable outcome = 5*4*3*2. So, P = 1/6

Probability - MCQ 5 - Question 7

From a deck of 52 cards, a card is selected and without replacing the card a new card is selected. Find out the probability that the first card is an ace and second card is a king ?

Detailed Solution for Probability - MCQ 5 - Question 7

4/52*4/51

Probability - MCQ 5 - Question 8

The probability that a person will be alive after 20 years is 1/4 and that of his wife is 2/5. Find out the probability that both are not alive after 20 years ?

Detailed Solution for Probability - MCQ 5 - Question 8

prob. That man is not alive = 3/4 and that of his wife = 3/5
Prob. That both will be dead = 3/4*3/5 = 9/20

Probability - MCQ 5 - Question 9

Three coins are tossed simultaneously.

Q.

Find out the probability that there is at least 2 heads ?

Detailed Solution for Probability - MCQ 5 - Question 9

= Total outcomes = {HHH,HTH,HHT,THH,TTT,TTH,THT,HTT}
Favourable outcome = HHH, HTH, HHT,THH
Prob = 4/8 = 1/2

Probability - MCQ 5 - Question 10

Three coins are tossed simultaneously.

Q.

Find the probability that there is exactly two tails ?

Detailed Solution for Probability - MCQ 5 - Question 10

Favourable outcome = TTH, THT, HTT
So, prob. = 3/8

Probability - MCQ 5 - Question 11

An urn contain 6 orange, 4 green,3 pink and 4 black balls

Q.

If 3 balls are picked at random, what is the probability that all are pink ?

Detailed Solution for Probability - MCQ 5 - Question 11

17C3 = 17*16*15/3*2*1 = 4080/6 = 680
3C3 = 1
P = 1/680

Probability - MCQ 5 - Question 12

An urn contain 6 orange, 4 green,3 pink and 4 black balls

Q.

If 5 balls are picked at random, what is the probability that none are orange ?

Detailed Solution for Probability - MCQ 5 - Question 12

17C5 = 17*16*15*14*13/5*4*3*2*1 = 742560/120 = 6188
11C5 = 11*10*9*8*7/5*4*3*2*1 = 55440/120 = 462
P = 462/6188 = 33/442

Probability - MCQ 5 - Question 13

An urn contain 6 orange, 4 green,3 pink and 4 black balls.

Q.

If 3 balls are drawn at random, what is the probability that 1 is green and the other 2 are black ?

Detailed Solution for Probability - MCQ 5 - Question 13

17C3 = 17*16*15/3*2*1 = 4080/6 = 680
4C1 × 4C2 = 4*4*3/2*1 = 24
P = 24/680 = 3/85

Probability - MCQ 5 - Question 14

There are 8 positive numbers and 6 negative numbers. 4 numbers are chosen at random and multiplied. Find the probability that the product is a positive number ?

Detailed Solution for Probability - MCQ 5 - Question 14

14C4 = 14*13*12*11/4*3*2*1 = 1001
4 No positive+4 no negative + (2 no positive * 2 no negative)
= 6C4 + 8C4 +(6C2 ×8C2) = 15+70+15*28 = 505
P = 505/1001

Probability - MCQ 5 - Question 15

A five digit number is formed with the digit 1,2,3,4 and 5 without repetition. Find the chance that the number is divisible by 5 ?

Detailed Solution for Probability - MCQ 5 - Question 15

5! = 5*4*3*2*1 = 120
4! = 4*3*2*1 = 24
P = 24/120 = 1/5

Probability - MCQ 5 - Question 16

A bag contains 6 red, 5 blue and 2 green balls. If 2 balls are picked at random, what is the probability that both are green?

Detailed Solution for Probability - MCQ 5 - Question 16

13C2 = 13*12/2 =78
2C2 = 1
P = 1/78

Probability - MCQ 5 - Question 17

If You toss a coin and roll a die. What is the probability of getting a head and a 3 on the die?

Detailed Solution for Probability - MCQ 5 - Question 17

1/2 * 1/6 = 1/12

Probability - MCQ 5 - Question 18

From a pack of 52 cards, 3 cards are drawn. What is the probability that one is ace, one is queen and one is jack?

Detailed Solution for Probability - MCQ 5 - Question 18

=4C1×4C1×4C1 / 52C3
=4×4×4 / 22100
=16/5525

Probability - MCQ 5 - Question 19

Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice.

Detailed Solution for Probability - MCQ 5 - Question 19

n(S) = 36
n(E) = (2,3),(2,6),(4,3),(4,6),(6,3),(6,6),(3,2),(6,2),(3,4),(6,4),(3,6)
P = 11/36

Probability - MCQ 5 - Question 20

Two dice are tossed. The probability that the total score is a prime number is

Detailed Solution for Probability - MCQ 5 - Question 20

E = (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5)
n(E) = 15
n(S) = 6*6 = 36
P = 15/36 = 5/12

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## Quantitative Aptitude for Competitive Examinations

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