MCQ: Clock & Calendar - 1(Easy) - SSC CGL MCQ

Anuj reached the place of meeting at 8:15 h, he reached 30 min earlier than the man who was 40 min late, Hence, the scheduled time of the meeting was 8:05 h.

In 12 h, they are at a right angles, 22 times.
So, in 24 h, they are at right angles, 44 times.

The hands of a clock point towards each other 11 times in every 12 h (because between 5 and 7, they point towards each other only once at 6 O'clock).
Therefore, in a day, the hands points 22 times in all, towards each other.

Here, 363/7 = 51 weeks + 6 days

Everyday of the weeks is repeated after 7 days.
Hence, it will be Wednesday after 84 days.

The century divisible by 400 is a leap year. The year 707 is not a leap year.

Next bus will leave at 9 : 35 am. So, last bus left at (9 : 35 - 0 : 30) = 9 : 50 am
So, inquiry clerk gave the information to the passenger at = (9 : 05 + 0 : 10)
= 9 : 15 am

So, the next Tuesday will come on the Mrs Susheela's wedding anniversary in 30th September, 2003

At 4 : 20 A.M. from the formula here P = 4 and Q = 20 so required angle is 11 x 20/2 - 30 x 4 = 110 - 120 = - 10 or ignoring the negative sign the required angle is 10°

Total number of days from January 1 to march 1
= 31 + 29 + 1
= 61 days
(February in leap years = 29 days) = 61 ÷ 7
= 8 weeks and 5 odd days
So, the fifth day from Friday = Tuesday

At 10 : 10 from the formula here P = 10 and Q = 10 so required angle is 11 x 10/2 - 30 x 10 = 55 - 300 = - 245 the required angle is 245°

Since a day of the week repeat after every 7 days, divide 59 by 7, remainder is 3 so number of odd days is 3, and 3 days after Monday is Thursday.

Number of days in June is 30 -2 = 28, and number of days in July is 7, total number of days is 28 + 7 = 35, when we divide 35 by 7 remainder is 0, or number of odd days is 0 hence 7th July must be the same day as that of 2nd June i.e. Saturday in this case.

The century divisible by 400 is a leap year. 2100 is not divisible by 400 hence is not a leap year.

On 31^st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009
= (1 + 1 +2 + 1) = 5 days.
∴ On 31^st December, 2009, it was Thursday.
Thus, on 1^st Jan, 2010 it is Friday.

At 11 : 50 A.M. from the formula here P = 11 and Q = 50
required angle is 11 x 50/2 - 30 x 11
= 275 - 330
= -55 or ignoring the negative sign the required angle is 55°