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MCQ: Coded Inequality- 3 - SSC CGL MCQ


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15 Questions MCQ Test General Intelligence and Reasoning for SSC CGL - MCQ: Coded Inequality- 3

MCQ: Coded Inequality- 3 for SSC CGL 2024 is part of General Intelligence and Reasoning for SSC CGL preparation. The MCQ: Coded Inequality- 3 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Coded Inequality- 3 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Coded Inequality- 3 below.
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MCQ: Coded Inequality- 3 - Question 1

If the expression, ‘M > R > Q, Q > N = J and J ≤ B < H are true then which of the following combinations will be possibly false?

Detailed Solution for MCQ: Coded Inequality- 3 - Question 1

Combining statements: M > R > Q > N = J ≤ B < H
Checking Option A: M > J is true.
Checking Option B: N < H is true.
Checking Option C: J < M is true.
Checking Option D: Q > B

We can clearly see that the signs between Q and B get reversed therefore the relation between Q and B cannot be formed.
Hence, Option D is correct.

MCQ: Coded Inequality- 3 - Question 2

If the expression, A > B, C < A and C ≥ D = E ≥ F are true then, which of the following combinations will be definitely true?

Detailed Solution for MCQ: Coded Inequality- 3 - Question 2

Combining statements: B < A > C ≥ D = E ≥ F
Checking Option A: E < A
Here we get the common sign between E and A as "<", hence it is true definitely.
Checking Option B: F > B
We can clearly see that the signs between F and B get reversed therefore the relation between F and B cannot be formed.
Checking Option C: F < A
B < A > C ≥ D = E ≥ F
Here, the common sign between F and A is "<"
Therefore, F < A is true definitely.
Hence, Option D is correct.

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MCQ: Coded Inequality- 3 - Question 3

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements: 
K < P ≥ L > J; L < T; H ≤ J
Conclusions: I. K < T  II. H < T

Detailed Solution for MCQ: Coded Inequality- 3 - Question 3

By combining all the statements we get:
K < P ≥ L > J; L < T; H ≤ J
Checking C1: K < T
Here, K < P ≥ L < T.
So, we can see that the opposite sign between K and T, thus no relationship can be established between them.
Therefore, C1 doesn’t follow.
Checking C2: H < T
Here, H ≤ J < L < T
The common sign between H and T is "<".
So, H < T is true.
Therefore, C2 follows.
Hence, Option B is correct.

MCQ: Coded Inequality- 3 - Question 4

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements: 
D ≥ G = Y ≤ T; M < G ≥ Z
Conclusions: I. D ≥ M  II. T ≥ M

Detailed Solution for MCQ: Coded Inequality- 3 - Question 4

By combining all the statements we get:
D ≥ G = Y ≤ T; M < G ≥ Z
Checking C1: D ≥ M
Here, D ≥ G > M
The common sign between D and M are ≥ and >.
So, D ≥ M is not true.
Therefore, C1 doesn’t follow.
Checking C2: T ≥ M
Here, M < G = Y ≤ T
The common sign between T and M are <, = and ≤.
So, T ≥ M is not true.
Therefore, C2 doesn’t follow.
Hence, Option D is correct.

MCQ: Coded Inequality- 3 - Question 5

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements:
 3 ≤ 6 < 9 ≥ 8; 6 ≤ 4; 5 > 9
Conclusions: I. 6 ≥ 3  II. 8 < 5  III. 3 < 9

Detailed Solution for MCQ: Coded Inequality- 3 - Question 5

By combining all the statements we get:
3 ≤ 6 < 9 ≥ 8; 6 ≤ 4; 5 > 9
Checking C1: 6 ≥ 3
Here, 3 ≤ 6
Therefore, C1 follows.
Checking C2: 8 < 5
Here, 5 > 9 ≥ 8
The common sign between 5 and 8 is ">".
Therefore, C2 follows.
Checking C3:  3 < 9
Here, 3 ≤ 6 < 9
The common sign between 3 and 9 is "<" .
Therefore, C3 follows.
Hence, Option D is correct.

MCQ: Coded Inequality- 3 - Question 6

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements:    
K ≥ U > C, A < T ≤ S, C = R > A
Conclusions:   I. C ≤ S             II. T ≥ U

Detailed Solution for MCQ: Coded Inequality- 3 - Question 6

Given Statements: 
K ≥ U > C         ….(i)
A < T ≤ S          ….(ii)
C = R > A         ….(iii)
Combining (i), (ii) and (iii), we get
K ≥ U > C = R > A < T ≤ S ….(iv)
Check for conclusion I: 
From (iv), we can’t compare C and S.
Thus, C ≤ S is not true.
Check for conclusion II: 
From (iv), we can’t compare T and U.
Thus, T ≥ U is not true.
Hence, neither I nor II is true.
Hence, option D is correct.

MCQ: Coded Inequality- 3 - Question 7

 Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements:    
A ≥ N < T, U ≥ S > D, H = T ≥ V, V = D
Conclusions:   I. S < T             II. U ≥ V

Detailed Solution for MCQ: Coded Inequality- 3 - Question 7

Given statements:
A ≥ N < T         ….(i)
U ≥ S > D         ….(ii)
H= T ≥ V          ….(iii)
V = D               ….(iv)
Combining (i), (ii), (iii) and (iv), we get
A ≥ N < T = H ≥ V = D < S ≤ U  ….(v)
Check for conclusion I: 
From (v), we can’t compare S and T.
Thus, S < T is not true.
Check for conclusion II: 
From (V), V < U or U > V is true. But U ≥ V is not true.
Hence, option D is correct.

MCQ: Coded Inequality- 3 - Question 8

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements:   
 U ≥ T < K, B ≥ L > W, S = K ≥ V, V = W
Conclusions:   I. S > T             II. U ≤ V

Detailed Solution for MCQ: Coded Inequality- 3 - Question 8

Given statements:
U ≥ T < K          ….(i)
B ≥ L > W         ….(ii)
S= K ≥ V           ….(iii)
V = W              ….(iv)
Combining (i), (ii), (iii) and (iv), we get
U ≥ T < K = S ≥ V = W < L ≤ B  ….(v)
Check for conclusion I: 
From (v), T < S or S > T is true.
Check for conclusion II: 
From (v), we can’t compare U and V.
Hence, II (U ≤ V) is not true.
Hence, only I is true.
Hence, option A is correct. 

MCQ: Coded Inequality- 3 - Question 9

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements: 
 B < H ≥ E ; E < T > A; D > N ≤ T
Conclusions:  I. H < T  II.A > B

Detailed Solution for MCQ: Coded Inequality- 3 - Question 9

From the given statements we have,
B < H ≥ E < T > A; D > N ≤ T
Conclusion I: H < T
Here, we get reverse sign between H and T, so Conclusion I does not follow.
Conclusion II: A > B
Here, we get reverse sign between A and B, so Conclusion II does not follow.
So, neither conclusion I nor II follows.
Hence option D is correct.

MCQ: Coded Inequality- 3 - Question 10

Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct answer on the basis of information given below.
Statements:

E = F < G < H;    G ≥ I
 Conclusions:
I. H > I    II. E > I

Detailed Solution for MCQ: Coded Inequality- 3 - Question 10

Given statements:
E = F < G < H       …. (i)
G ≥ I                   …. (ii)
From (i) and (ii), we get
I ≤ G < H                                   …. (iii)
Thus, I < H or H > I is true.
Again, from (i) and (ii), we get
E = F < G ≥ I                              …. (iv)
We can’t compare E and I. Hence, E > I is not true.
Hence, only conclusion I is true.
Hence, option A correct.

MCQ: Coded Inequality- 3 - Question 11

Direction: Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given expression in such a manner that ‘G > L’ definitely holds true?
L _ O _ D _ I _ N _ G

Detailed Solution for MCQ: Coded Inequality- 3 - Question 11

L ≤ O ≤ D = I ≤ N < G
≤, ≤, =, ≤, < symbols are sufficient to make G > L definitely true.
Hence, Option C is correct.

MCQ: Coded Inequality- 3 - Question 12

In which of the following expressions will make the expression R < O be definitely true?

Detailed Solution for MCQ: Coded Inequality- 3 - Question 12

Check options one by one
Checking Option A: O < T > R ≥ U
We can clearly see that the signs between R and O get reversed therefore the relation between R and O cannot be formed.
Checking Option B: O ≥ U = R < H
We can clearly see that R ≤ O.
So, R < O is not true.
Checking Option C: S < O < G = R
We can clearly see that R > O.
So, R < O is not true.
Checking Option D: R = C < T < O
We can clearly see that R < O is definitely true.
Hence, Option D is correct.

MCQ: Coded Inequality- 3 - Question 13

Direction: In the following question, assume the given information to be true and mark the appropriate options.
Statements: 
K > J; D < V, V < J; D = N ≥ M; H > G < M
Conclusions: I. H > D  II. G < K  III. H < M

Detailed Solution for MCQ: Coded Inequality- 3 - Question 13

By combining all the statements we get:
K > J > V > D = N ≥ M > G < H
Checking C1: H > D
Here, D = N ≥ M > G < H, so no relation is possible because of opposite sign between them.
Therefore, C1 doesn’t follow.
Checking C2: G < K
Here, K > J > V > D = N ≥ M > G, so G < K.
Therefore, C2 follows.
Checking C3: H < M
Here, H > G < M, so no relation is possible because of opposite sign between them.
Therefore, C3 doesn’t follow.
Hence, Option C is correct.

MCQ: Coded Inequality- 3 - Question 14

Direction: In the following question, assume the given information to be true and mark the appropriate options.
Statements: 
A > W > E = K < O < J ≤ M
Conclusions: I. W > K  II. M > K  III. A > K

Detailed Solution for MCQ: Coded Inequality- 3 - Question 14

Statements: A > W > E = K < O < J ≤ M
Checking C1: W > K
Here, W > E = K, so W > K.
Therefore, C1 follows.
Checking C2: M > K
Here, K < O < J ≤ M, so, M > K.
Therefore, C2 follows.
Checking C3: A > K
Here, A > W > E = K, so A > K.
Therefore, C3 follows.
Hence, all the conclusions follow.
Hence, Option D is correct.

MCQ: Coded Inequality- 3 - Question 15

Direction: In the following question, assume the given information to be true and mark the appropriate options.
Statements: 
N > Y > A; P = M < N; T > N
Conclusions: I. M < Y  II. P ≥ Y

Detailed Solution for MCQ: Coded Inequality- 3 - Question 15

By combining all the statements we get:
P = M < N > Y > A; T > N
Checking C1: M < Y
Here, P = M < N > Y, so, no relation is possible because of opposite sign between them.
Therefore, C1 doesn’t follow.
Checking C2: P ≥ Y
Here, P = M < N > Y, so, no relation is possible because of opposite sign between them.
Therefore, C2 doesn’t follow.
But evaluating the options, in both the conclusions elements can be made same as "P = M" and also all the signs "<, >, =" can be found between them(P/M and Y). Hence, it is complementary pair.
So, either I or II can be true.
Hence, Option C is correct.

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