MCQ: Coded Inequality- 3 - Bank Exams MCQ

Combining statements: M > R > Q > N = J ≤ B < H
Checking Option A: M > J is true.
Checking Option B: N < H is true.
Checking Option C: J < M is true.
Checking Option D: Q > B

We can clearly see that the signs between Q and B get reversed therefore the relation between Q and B cannot be formed.
Hence, Option D is correct.

Combining statements: B < A > C ≥ D = E ≥ F
Checking Option A: E < A
Here we get the common sign between E and A as "<", hence it is true definitely.
Checking Option B: F > B
We can clearly see that the signs between F and B get reversed therefore the relation between F and B cannot be formed.
Checking Option C: F < A
B < A > C ≥ D = E ≥ F
Here, the common sign between F and A is "<"
Therefore, F < A is true definitely.
Hence, Option D is correct.

By combining all the statements we get:
K < P ≥ L > J; L < T; H ≤ J
Checking C1: K < T
Here, K < P ≥ L < T.
So, we can see that the opposite sign between K and T, thus no relationship can be established between them.
Therefore, C1 doesn’t follow.
Checking C2: H < T
Here, H ≤ J < L < T
The common sign between H and T is "<".
So, H < T is true.
Therefore, C2 follows.
Hence, Option B is correct.

By combining all the statements we get:
D ≥ G = Y ≤ T; M < G ≥ Z
Checking C1: D ≥ M
Here, D ≥ G > M
The common sign between D and M are ≥ and >.
So, D ≥ M is not true.
Therefore, C1 doesn’t follow.
Checking C2: T ≥ M
Here, M < G = Y ≤ T
The common sign between T and M are <, = and ≤.
So, T ≥ M is not true.
Therefore, C2 doesn’t follow.
Hence, Option D is correct.

By combining all the statements we get:
3 ≤ 6 < 9 ≥ 8; 6 ≤ 4; 5 > 9
Checking C1: 6 ≥ 3
Here, 3 ≤ 6
Therefore, C1 follows.
Checking C2: 8 < 5
Here, 5 > 9 ≥ 8
The common sign between 5 and 8 is ">".
Therefore, C2 follows.
Checking C3:  3 < 9
Here, 3 ≤ 6 < 9
The common sign between 3 and 9 is "<" .
Therefore, C3 follows.
Hence, Option D is correct.

Given Statements: 
K ≥ U > C         ….(i)
A < T ≤ S          ….(ii)
C = R > A         ….(iii)
Combining (i), (ii) and (iii), we get
K ≥ U > C = R > A < T ≤ S ….(iv)
Check for conclusion I: 
From (iv), we can’t compare C and S.
Thus, C ≤ S is not true.
Check for conclusion II: 
From (iv), we can’t compare T and U.
Thus, T ≥ U is not true.
Hence, neither I nor II is true.
Hence, option D is correct.

Given statements:
A ≥ N < T         ….(i)
U ≥ S > D         ….(ii)
H= T ≥ V          ….(iii)
V = D               ….(iv)
Combining (i), (ii), (iii) and (iv), we get
A ≥ N < T = H ≥ V = D < S ≤ U  ….(v)
Check for conclusion I: 
From (v), we can’t compare S and T.
Thus, S < T is not true.
Check for conclusion II: 
From (V), V < U or U > V is true. But U ≥ V is not true.
Hence, option D is correct.

Given statements:
U ≥ T < K          ….(i)
B ≥ L > W         ….(ii)
S= K ≥ V           ….(iii)
V = W              ….(iv)
Combining (i), (ii), (iii) and (iv), we get
U ≥ T < K = S ≥ V = W < L ≤ B  ….(v)
Check for conclusion I: 
From (v), T < S or S > T is true.
Check for conclusion II: 
From (v), we can’t compare U and V.
Hence, II (U ≤ V) is not true.
Hence, only I is true.
Hence, option A is correct. 

From the given statements we have,
B < H ≥ E < T > A; D > N ≤ T
Conclusion I: H < T
Here, we get reverse sign between H and T, so Conclusion I does not follow.
Conclusion II: A > B
Here, we get reverse sign between A and B, so Conclusion II does not follow.
So, neither conclusion I nor II follows.
Hence option D is correct.

Given statements:
E = F < G < H       …. (i)
G ≥ I                   …. (ii)
From (i) and (ii), we get
I ≤ G < H                                   …. (iii)
Thus, I < H or H > I is true.
Again, from (i) and (ii), we get
E = F < G ≥ I                              …. (iv)
We can’t compare E and I. Hence, E > I is not true.
Hence, only conclusion I is true.
Hence, option A correct.

L ≤ O ≤ D = I ≤ N < G
≤, ≤, =, ≤, < symbols are sufficient to make G > L definitely true.
Hence, Option C is correct.

Check options one by one
Checking Option A: O < T > R ≥ U
We can clearly see that the signs between R and O get reversed therefore the relation between R and O cannot be formed.
Checking Option B: O ≥ U = R < H
We can clearly see that R ≤ O.
So, R < O is not true.
Checking Option C: S < O < G = R
We can clearly see that R > O.
So, R < O is not true.
Checking Option D: R = C < T < O
We can clearly see that R < O is definitely true.
Hence, Option D is correct.

By combining all the statements we get:
K > J > V > D = N ≥ M > G < H
Checking C1: H > D
Here, D = N ≥ M > G < H, so no relation is possible because of opposite sign between them.
Therefore, C1 doesn’t follow.
Checking C2: G < K
Here, K > J > V > D = N ≥ M > G, so G < K.
Therefore, C2 follows.
Checking C3: H < M
Here, H > G < M, so no relation is possible because of opposite sign between them.
Therefore, C3 doesn’t follow.
Hence, Option C is correct.

Statements: A > W > E = K < O < J ≤ M
Checking C1: W > K
Here, W > E = K, so W > K.
Therefore, C1 follows.
Checking C2: M > K
Here, K < O < J ≤ M, so, M > K.
Therefore, C2 follows.
Checking C3: A > K
Here, A > W > E = K, so A > K.
Therefore, C3 follows.
Hence, all the conclusions follow.
Hence, Option D is correct.

By combining all the statements we get:
P = M < N > Y > A; T > N
Checking C1: M < Y
Here, P = M < N > Y, so, no relation is possible because of opposite sign between them.
Therefore, C1 doesn’t follow.
Checking C2: P ≥ Y
Here, P = M < N > Y, so, no relation is possible because of opposite sign between them.
Therefore, C2 doesn’t follow.
But evaluating the options, in both the conclusions elements can be made same as "P = M" and also all the signs "<, >, =" can be found between them(P/M and Y). Hence, it is complementary pair.
So, either I or II can be true.
Hence, Option C is correct.